Difference of a regular language and a context-free language












2












$begingroup$


I know that given the context-free language L and the regular language R, the language L R is context free. But what about R L ? My attempt is as follows:

R L = R $cap$ $overline{L}$

We cannot know whether $overline{L}$ is CF or not, so my guess is that we decide whether R L is context-free or not.

Am I right? Any help would be appreciated.










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$endgroup$












  • $begingroup$
    Well, there is one regular language $R$ of all possible words. So $Rsetminus L=overline{L}$. So if you know of CF languages $L$ so that $overline{L}$ is not CF, then you are done.
    $endgroup$
    – Thomas Andrews
    Apr 23 '16 at 22:39










  • $begingroup$
    @ThomasAndrews Well, I am not given a particular L, so I cannot say anyhting about $overline{L}$ . Am I correct in understanding your comment?
    $endgroup$
    – Success
    Apr 23 '16 at 22:47
















2












$begingroup$


I know that given the context-free language L and the regular language R, the language L R is context free. But what about R L ? My attempt is as follows:

R L = R $cap$ $overline{L}$

We cannot know whether $overline{L}$ is CF or not, so my guess is that we decide whether R L is context-free or not.

Am I right? Any help would be appreciated.










share|cite|improve this question









$endgroup$












  • $begingroup$
    Well, there is one regular language $R$ of all possible words. So $Rsetminus L=overline{L}$. So if you know of CF languages $L$ so that $overline{L}$ is not CF, then you are done.
    $endgroup$
    – Thomas Andrews
    Apr 23 '16 at 22:39










  • $begingroup$
    @ThomasAndrews Well, I am not given a particular L, so I cannot say anyhting about $overline{L}$ . Am I correct in understanding your comment?
    $endgroup$
    – Success
    Apr 23 '16 at 22:47














2












2








2





$begingroup$


I know that given the context-free language L and the regular language R, the language L R is context free. But what about R L ? My attempt is as follows:

R L = R $cap$ $overline{L}$

We cannot know whether $overline{L}$ is CF or not, so my guess is that we decide whether R L is context-free or not.

Am I right? Any help would be appreciated.










share|cite|improve this question









$endgroup$




I know that given the context-free language L and the regular language R, the language L R is context free. But what about R L ? My attempt is as follows:

R L = R $cap$ $overline{L}$

We cannot know whether $overline{L}$ is CF or not, so my guess is that we decide whether R L is context-free or not.

Am I right? Any help would be appreciated.







formal-languages regular-language context-free-grammar






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asked Apr 23 '16 at 22:35









SuccessSuccess

967




967












  • $begingroup$
    Well, there is one regular language $R$ of all possible words. So $Rsetminus L=overline{L}$. So if you know of CF languages $L$ so that $overline{L}$ is not CF, then you are done.
    $endgroup$
    – Thomas Andrews
    Apr 23 '16 at 22:39










  • $begingroup$
    @ThomasAndrews Well, I am not given a particular L, so I cannot say anyhting about $overline{L}$ . Am I correct in understanding your comment?
    $endgroup$
    – Success
    Apr 23 '16 at 22:47


















  • $begingroup$
    Well, there is one regular language $R$ of all possible words. So $Rsetminus L=overline{L}$. So if you know of CF languages $L$ so that $overline{L}$ is not CF, then you are done.
    $endgroup$
    – Thomas Andrews
    Apr 23 '16 at 22:39










  • $begingroup$
    @ThomasAndrews Well, I am not given a particular L, so I cannot say anyhting about $overline{L}$ . Am I correct in understanding your comment?
    $endgroup$
    – Success
    Apr 23 '16 at 22:47
















$begingroup$
Well, there is one regular language $R$ of all possible words. So $Rsetminus L=overline{L}$. So if you know of CF languages $L$ so that $overline{L}$ is not CF, then you are done.
$endgroup$
– Thomas Andrews
Apr 23 '16 at 22:39




$begingroup$
Well, there is one regular language $R$ of all possible words. So $Rsetminus L=overline{L}$. So if you know of CF languages $L$ so that $overline{L}$ is not CF, then you are done.
$endgroup$
– Thomas Andrews
Apr 23 '16 at 22:39












$begingroup$
@ThomasAndrews Well, I am not given a particular L, so I cannot say anyhting about $overline{L}$ . Am I correct in understanding your comment?
$endgroup$
– Success
Apr 23 '16 at 22:47




$begingroup$
@ThomasAndrews Well, I am not given a particular L, so I cannot say anyhting about $overline{L}$ . Am I correct in understanding your comment?
$endgroup$
– Success
Apr 23 '16 at 22:47










1 Answer
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$begingroup$

HINT:




Since, regular languages are closed under complement property and context-free languages are not closed under complement property.







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    1 Answer
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    1 Answer
    1






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    oldest

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    active

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    active

    oldest

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    0












    $begingroup$

    HINT:




    Since, regular languages are closed under complement property and context-free languages are not closed under complement property.







    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      HINT:




      Since, regular languages are closed under complement property and context-free languages are not closed under complement property.







      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        HINT:




        Since, regular languages are closed under complement property and context-free languages are not closed under complement property.







        share|cite|improve this answer









        $endgroup$



        HINT:




        Since, regular languages are closed under complement property and context-free languages are not closed under complement property.








        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered May 20 '16 at 14:12









        Mithlesh UpadhyayMithlesh Upadhyay

        2,93282968




        2,93282968






























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