Does $L_1$ convergence of continuous functions imply pointwise convergence?












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Suppose that $(f_n)$ is a sequence in $C[0,1]$ which is convergent with respect to the $L_1$ norm. Then is $(f_n(x))$ necessarily convergent for all $xin[0,1]$?



I'm pretty sure the answer is no, but I'm not aware of a counterexample.










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    3












    $begingroup$


    Suppose that $(f_n)$ is a sequence in $C[0,1]$ which is convergent with respect to the $L_1$ norm. Then is $(f_n(x))$ necessarily convergent for all $xin[0,1]$?



    I'm pretty sure the answer is no, but I'm not aware of a counterexample.










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      3








      3





      $begingroup$


      Suppose that $(f_n)$ is a sequence in $C[0,1]$ which is convergent with respect to the $L_1$ norm. Then is $(f_n(x))$ necessarily convergent for all $xin[0,1]$?



      I'm pretty sure the answer is no, but I'm not aware of a counterexample.










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      $endgroup$




      Suppose that $(f_n)$ is a sequence in $C[0,1]$ which is convergent with respect to the $L_1$ norm. Then is $(f_n(x))$ necessarily convergent for all $xin[0,1]$?



      I'm pretty sure the answer is no, but I'm not aware of a counterexample.







      functional-analysis convergence examples-counterexamples lp-spaces pointwise-convergence






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      asked Jan 24 at 2:52









      Keshav SrinivasanKeshav Srinivasan

      2,33421445




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          2 Answers
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          $begingroup$

          Consider $f_n(x) = (-1)^n x^n.$ Then $f_nin C[0,1],$ and $f_n to 0$ in $L^1,$ but $f_n(1)$ does not converge.






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            $begingroup$

            The "dancing indicators" counterexample:
            $$chi_{[0, 1/2]}, chi_{[1/2, 1]}, chi_{[0, 1/3]}, chi_{[1/3, 2/3]}, chi_{[2/3, 1]}, chi_{[0, 1/4]}, chi_{[1/4, 2/4]}, ldots$$



            Edit: as noted in the comments, these functions are not continuous. However, if you replace the indicators with continuous "tent" functions supported on the same interval, you obtain the same contradiction. I like this type of counterexample more than the one given by zhw since you can use it to construct a sequence that fails to converges pointwise for all $x in [0,1]$, rather than one that fails to converge pointwise at a single $x$.






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            • 1




              $begingroup$
              well, those are not continuous
              $endgroup$
              – zhw.
              Jan 24 at 4:20






            • 1




              $begingroup$
              If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
              $endgroup$
              – eepperly16
              Jan 24 at 4:28











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            2 Answers
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            6












            $begingroup$

            Consider $f_n(x) = (-1)^n x^n.$ Then $f_nin C[0,1],$ and $f_n to 0$ in $L^1,$ but $f_n(1)$ does not converge.






            share|cite|improve this answer









            $endgroup$


















              6












              $begingroup$

              Consider $f_n(x) = (-1)^n x^n.$ Then $f_nin C[0,1],$ and $f_n to 0$ in $L^1,$ but $f_n(1)$ does not converge.






              share|cite|improve this answer









              $endgroup$
















                6












                6








                6





                $begingroup$

                Consider $f_n(x) = (-1)^n x^n.$ Then $f_nin C[0,1],$ and $f_n to 0$ in $L^1,$ but $f_n(1)$ does not converge.






                share|cite|improve this answer









                $endgroup$



                Consider $f_n(x) = (-1)^n x^n.$ Then $f_nin C[0,1],$ and $f_n to 0$ in $L^1,$ but $f_n(1)$ does not converge.







                share|cite|improve this answer












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                share|cite|improve this answer










                answered Jan 24 at 4:23









                zhw.zhw.

                74.2k43175




                74.2k43175























                    3












                    $begingroup$

                    The "dancing indicators" counterexample:
                    $$chi_{[0, 1/2]}, chi_{[1/2, 1]}, chi_{[0, 1/3]}, chi_{[1/3, 2/3]}, chi_{[2/3, 1]}, chi_{[0, 1/4]}, chi_{[1/4, 2/4]}, ldots$$



                    Edit: as noted in the comments, these functions are not continuous. However, if you replace the indicators with continuous "tent" functions supported on the same interval, you obtain the same contradiction. I like this type of counterexample more than the one given by zhw since you can use it to construct a sequence that fails to converges pointwise for all $x in [0,1]$, rather than one that fails to converge pointwise at a single $x$.






                    share|cite|improve this answer











                    $endgroup$









                    • 1




                      $begingroup$
                      well, those are not continuous
                      $endgroup$
                      – zhw.
                      Jan 24 at 4:20






                    • 1




                      $begingroup$
                      If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
                      $endgroup$
                      – eepperly16
                      Jan 24 at 4:28
















                    3












                    $begingroup$

                    The "dancing indicators" counterexample:
                    $$chi_{[0, 1/2]}, chi_{[1/2, 1]}, chi_{[0, 1/3]}, chi_{[1/3, 2/3]}, chi_{[2/3, 1]}, chi_{[0, 1/4]}, chi_{[1/4, 2/4]}, ldots$$



                    Edit: as noted in the comments, these functions are not continuous. However, if you replace the indicators with continuous "tent" functions supported on the same interval, you obtain the same contradiction. I like this type of counterexample more than the one given by zhw since you can use it to construct a sequence that fails to converges pointwise for all $x in [0,1]$, rather than one that fails to converge pointwise at a single $x$.






                    share|cite|improve this answer











                    $endgroup$









                    • 1




                      $begingroup$
                      well, those are not continuous
                      $endgroup$
                      – zhw.
                      Jan 24 at 4:20






                    • 1




                      $begingroup$
                      If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
                      $endgroup$
                      – eepperly16
                      Jan 24 at 4:28














                    3












                    3








                    3





                    $begingroup$

                    The "dancing indicators" counterexample:
                    $$chi_{[0, 1/2]}, chi_{[1/2, 1]}, chi_{[0, 1/3]}, chi_{[1/3, 2/3]}, chi_{[2/3, 1]}, chi_{[0, 1/4]}, chi_{[1/4, 2/4]}, ldots$$



                    Edit: as noted in the comments, these functions are not continuous. However, if you replace the indicators with continuous "tent" functions supported on the same interval, you obtain the same contradiction. I like this type of counterexample more than the one given by zhw since you can use it to construct a sequence that fails to converges pointwise for all $x in [0,1]$, rather than one that fails to converge pointwise at a single $x$.






                    share|cite|improve this answer











                    $endgroup$



                    The "dancing indicators" counterexample:
                    $$chi_{[0, 1/2]}, chi_{[1/2, 1]}, chi_{[0, 1/3]}, chi_{[1/3, 2/3]}, chi_{[2/3, 1]}, chi_{[0, 1/4]}, chi_{[1/4, 2/4]}, ldots$$



                    Edit: as noted in the comments, these functions are not continuous. However, if you replace the indicators with continuous "tent" functions supported on the same interval, you obtain the same contradiction. I like this type of counterexample more than the one given by zhw since you can use it to construct a sequence that fails to converges pointwise for all $x in [0,1]$, rather than one that fails to converge pointwise at a single $x$.







                    share|cite|improve this answer














                    share|cite|improve this answer



                    share|cite|improve this answer








                    edited Jan 24 at 7:24

























                    answered Jan 24 at 3:05









                    angryavianangryavian

                    42.1k23381




                    42.1k23381








                    • 1




                      $begingroup$
                      well, those are not continuous
                      $endgroup$
                      – zhw.
                      Jan 24 at 4:20






                    • 1




                      $begingroup$
                      If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
                      $endgroup$
                      – eepperly16
                      Jan 24 at 4:28














                    • 1




                      $begingroup$
                      well, those are not continuous
                      $endgroup$
                      – zhw.
                      Jan 24 at 4:20






                    • 1




                      $begingroup$
                      If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
                      $endgroup$
                      – eepperly16
                      Jan 24 at 4:28








                    1




                    1




                    $begingroup$
                    well, those are not continuous
                    $endgroup$
                    – zhw.
                    Jan 24 at 4:20




                    $begingroup$
                    well, those are not continuous
                    $endgroup$
                    – zhw.
                    Jan 24 at 4:20




                    1




                    1




                    $begingroup$
                    If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
                    $endgroup$
                    – eepperly16
                    Jan 24 at 4:28




                    $begingroup$
                    If you modify the indicators to be "trapezoidal", having a linear ramp to the peak value, this example fails to converge pointwise at any point in the interval
                    $endgroup$
                    – eepperly16
                    Jan 24 at 4:28


















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