Finding Alpha Level from Rejection Rule












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I have a question which asks:




A researcher wants to evaluate the sensitivity of their assay for
measuring urinary mercury. The standard is to have a 99% probability
of detecting a sample with mercury concentration 1 ppm. Therefore,
they wish to test the null hypothesis H_0: p=0.99, where p is the
probability of a positive test when the concentration is 1 ppm. The
alternative hypothesis is that p is not equal to 0.99. The researcher
created 500 samples with a 1ppm mercury concentration and tested them.
The number of samples that tested positive was recorded.



2.1. Suppose that they decide to reject H_0 if the number of positive samples is 494 or less. What is the type I error probability of this
rejection rule?




If the null hypothesis is true, we expect 99% of the samples to be positive, which is 495 samples. So this rejection rule says that if anything less than 99% are positive we are rejecting the null. This seems like it must be a high alpha (a high probability of rejecting a true null hypothesis due to chance), but I'm confused about how to calculate it.










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    0












    $begingroup$


    I have a question which asks:




    A researcher wants to evaluate the sensitivity of their assay for
    measuring urinary mercury. The standard is to have a 99% probability
    of detecting a sample with mercury concentration 1 ppm. Therefore,
    they wish to test the null hypothesis H_0: p=0.99, where p is the
    probability of a positive test when the concentration is 1 ppm. The
    alternative hypothesis is that p is not equal to 0.99. The researcher
    created 500 samples with a 1ppm mercury concentration and tested them.
    The number of samples that tested positive was recorded.



    2.1. Suppose that they decide to reject H_0 if the number of positive samples is 494 or less. What is the type I error probability of this
    rejection rule?




    If the null hypothesis is true, we expect 99% of the samples to be positive, which is 495 samples. So this rejection rule says that if anything less than 99% are positive we are rejecting the null. This seems like it must be a high alpha (a high probability of rejecting a true null hypothesis due to chance), but I'm confused about how to calculate it.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I have a question which asks:




      A researcher wants to evaluate the sensitivity of their assay for
      measuring urinary mercury. The standard is to have a 99% probability
      of detecting a sample with mercury concentration 1 ppm. Therefore,
      they wish to test the null hypothesis H_0: p=0.99, where p is the
      probability of a positive test when the concentration is 1 ppm. The
      alternative hypothesis is that p is not equal to 0.99. The researcher
      created 500 samples with a 1ppm mercury concentration and tested them.
      The number of samples that tested positive was recorded.



      2.1. Suppose that they decide to reject H_0 if the number of positive samples is 494 or less. What is the type I error probability of this
      rejection rule?




      If the null hypothesis is true, we expect 99% of the samples to be positive, which is 495 samples. So this rejection rule says that if anything less than 99% are positive we are rejecting the null. This seems like it must be a high alpha (a high probability of rejecting a true null hypothesis due to chance), but I'm confused about how to calculate it.










      share|cite|improve this question









      $endgroup$




      I have a question which asks:




      A researcher wants to evaluate the sensitivity of their assay for
      measuring urinary mercury. The standard is to have a 99% probability
      of detecting a sample with mercury concentration 1 ppm. Therefore,
      they wish to test the null hypothesis H_0: p=0.99, where p is the
      probability of a positive test when the concentration is 1 ppm. The
      alternative hypothesis is that p is not equal to 0.99. The researcher
      created 500 samples with a 1ppm mercury concentration and tested them.
      The number of samples that tested positive was recorded.



      2.1. Suppose that they decide to reject H_0 if the number of positive samples is 494 or less. What is the type I error probability of this
      rejection rule?




      If the null hypothesis is true, we expect 99% of the samples to be positive, which is 495 samples. So this rejection rule says that if anything less than 99% are positive we are rejecting the null. This seems like it must be a high alpha (a high probability of rejecting a true null hypothesis due to chance), but I'm confused about how to calculate it.







      statistics hypothesis-testing






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      asked Jan 23 at 19:41









      hemerahemera

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