How can i get help for integer method in python3
If i want to get the information about string's methods i write
help('blabla'.islower())
But how can i get the information about methods of integers. See the examples below
help((1).numerator())
The error is
TypeError: 'int' object is not callable
or for any other method
python-3.x
add a comment |
If i want to get the information about string's methods i write
help('blabla'.islower())
But how can i get the information about methods of integers. See the examples below
help((1).numerator())
The error is
TypeError: 'int' object is not callable
or for any other method
python-3.x
tryhelp(int.numerator)
– davedwards
Jan 1 at 22:26
add a comment |
If i want to get the information about string's methods i write
help('blabla'.islower())
But how can i get the information about methods of integers. See the examples below
help((1).numerator())
The error is
TypeError: 'int' object is not callable
or for any other method
python-3.x
If i want to get the information about string's methods i write
help('blabla'.islower())
But how can i get the information about methods of integers. See the examples below
help((1).numerator())
The error is
TypeError: 'int' object is not callable
or for any other method
python-3.x
python-3.x
asked Jan 1 at 22:23
sanchosancho
61
61
tryhelp(int.numerator)
– davedwards
Jan 1 at 22:26
add a comment |
tryhelp(int.numerator)
– davedwards
Jan 1 at 22:26
try
help(int.numerator)
– davedwards
Jan 1 at 22:26
try
help(int.numerator)
– davedwards
Jan 1 at 22:26
add a comment |
1 Answer
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help(int.numerator)
The canonical format for help on a classmethod would be help(cls.method)
. help
takes objects, classes, or functions, and returns the documentation for those respectively. To get docs for a method, pass in that method (int.numerator
is an example of such a method)
Additionally if you insist on wanting to pass in an integer object:
a = 1
help(a.numerator)
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
help(int.numerator)
The canonical format for help on a classmethod would be help(cls.method)
. help
takes objects, classes, or functions, and returns the documentation for those respectively. To get docs for a method, pass in that method (int.numerator
is an example of such a method)
Additionally if you insist on wanting to pass in an integer object:
a = 1
help(a.numerator)
add a comment |
help(int.numerator)
The canonical format for help on a classmethod would be help(cls.method)
. help
takes objects, classes, or functions, and returns the documentation for those respectively. To get docs for a method, pass in that method (int.numerator
is an example of such a method)
Additionally if you insist on wanting to pass in an integer object:
a = 1
help(a.numerator)
add a comment |
help(int.numerator)
The canonical format for help on a classmethod would be help(cls.method)
. help
takes objects, classes, or functions, and returns the documentation for those respectively. To get docs for a method, pass in that method (int.numerator
is an example of such a method)
Additionally if you insist on wanting to pass in an integer object:
a = 1
help(a.numerator)
help(int.numerator)
The canonical format for help on a classmethod would be help(cls.method)
. help
takes objects, classes, or functions, and returns the documentation for those respectively. To get docs for a method, pass in that method (int.numerator
is an example of such a method)
Additionally if you insist on wanting to pass in an integer object:
a = 1
help(a.numerator)
answered Jan 1 at 22:29
PrimusaPrimusa
7,9902832
7,9902832
add a comment |
add a comment |
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try
help(int.numerator)
– davedwards
Jan 1 at 22:26