how do express “multiple” in predicate logic?
$begingroup$
I hope you can give me some tips on how to translate part of the following sentence into predicate logic:
“No woman loves a man that loves multiple women”.
Which quantifier would you use to express the part “multiple”? It of course means “more than one”, so the existential quantifier (expressing: at least one) as such does not seem enough... Any ideas?
Thank you in advance for any help you can give me!
predicate-logic
$endgroup$
add a comment |
$begingroup$
I hope you can give me some tips on how to translate part of the following sentence into predicate logic:
“No woman loves a man that loves multiple women”.
Which quantifier would you use to express the part “multiple”? It of course means “more than one”, so the existential quantifier (expressing: at least one) as such does not seem enough... Any ideas?
Thank you in advance for any help you can give me!
predicate-logic
$endgroup$
3
$begingroup$
"more than one" is "at least two".
$endgroup$
– Mauro ALLEGRANZA
Jan 22 at 15:38
$begingroup$
Thanks, yes I agree, but then my question becomes: how do I express that? Sorry, just starting out with predicate logic, so maybe the answer should be obvious...
$endgroup$
– user637252
Jan 22 at 16:36
add a comment |
$begingroup$
I hope you can give me some tips on how to translate part of the following sentence into predicate logic:
“No woman loves a man that loves multiple women”.
Which quantifier would you use to express the part “multiple”? It of course means “more than one”, so the existential quantifier (expressing: at least one) as such does not seem enough... Any ideas?
Thank you in advance for any help you can give me!
predicate-logic
$endgroup$
I hope you can give me some tips on how to translate part of the following sentence into predicate logic:
“No woman loves a man that loves multiple women”.
Which quantifier would you use to express the part “multiple”? It of course means “more than one”, so the existential quantifier (expressing: at least one) as such does not seem enough... Any ideas?
Thank you in advance for any help you can give me!
predicate-logic
predicate-logic
asked Jan 22 at 15:35
user637252user637252
11
11
3
$begingroup$
"more than one" is "at least two".
$endgroup$
– Mauro ALLEGRANZA
Jan 22 at 15:38
$begingroup$
Thanks, yes I agree, but then my question becomes: how do I express that? Sorry, just starting out with predicate logic, so maybe the answer should be obvious...
$endgroup$
– user637252
Jan 22 at 16:36
add a comment |
3
$begingroup$
"more than one" is "at least two".
$endgroup$
– Mauro ALLEGRANZA
Jan 22 at 15:38
$begingroup$
Thanks, yes I agree, but then my question becomes: how do I express that? Sorry, just starting out with predicate logic, so maybe the answer should be obvious...
$endgroup$
– user637252
Jan 22 at 16:36
3
3
$begingroup$
"more than one" is "at least two".
$endgroup$
– Mauro ALLEGRANZA
Jan 22 at 15:38
$begingroup$
"more than one" is "at least two".
$endgroup$
– Mauro ALLEGRANZA
Jan 22 at 15:38
$begingroup$
Thanks, yes I agree, but then my question becomes: how do I express that? Sorry, just starting out with predicate logic, so maybe the answer should be obvious...
$endgroup$
– user637252
Jan 22 at 16:36
$begingroup$
Thanks, yes I agree, but then my question becomes: how do I express that? Sorry, just starting out with predicate logic, so maybe the answer should be obvious...
$endgroup$
– user637252
Jan 22 at 16:36
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Rephrase that part as
There are two different women loved by the man
$exists xexists y:$ Woman$(x), land,$Woman$(y), land, lnot(x=y),land,$Love$(m,x), land,$Love$(m, y)$
$endgroup$
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Rephrase that part as
There are two different women loved by the man
$exists xexists y:$ Woman$(x), land,$Woman$(y), land, lnot(x=y),land,$Love$(m,x), land,$Love$(m, y)$
$endgroup$
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
add a comment |
$begingroup$
Rephrase that part as
There are two different women loved by the man
$exists xexists y:$ Woman$(x), land,$Woman$(y), land, lnot(x=y),land,$Love$(m,x), land,$Love$(m, y)$
$endgroup$
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
add a comment |
$begingroup$
Rephrase that part as
There are two different women loved by the man
$exists xexists y:$ Woman$(x), land,$Woman$(y), land, lnot(x=y),land,$Love$(m,x), land,$Love$(m, y)$
$endgroup$
Rephrase that part as
There are two different women loved by the man
$exists xexists y:$ Woman$(x), land,$Woman$(y), land, lnot(x=y),land,$Love$(m,x), land,$Love$(m, y)$
answered Jan 22 at 15:53
BerciBerci
61.3k23674
61.3k23674
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
add a comment |
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
I would instead write $exists x,yintext{Women}$, but it's the same concept.
$endgroup$
– Don Thousand
Jan 22 at 16:01
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
$begingroup$
thanks! that makes sense!
$endgroup$
– user637252
Jan 22 at 16:39
add a comment |
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3
$begingroup$
"more than one" is "at least two".
$endgroup$
– Mauro ALLEGRANZA
Jan 22 at 15:38
$begingroup$
Thanks, yes I agree, but then my question becomes: how do I express that? Sorry, just starting out with predicate logic, so maybe the answer should be obvious...
$endgroup$
– user637252
Jan 22 at 16:36