Mixing
How to exclude a number from 3 numbers that is not min and max, elegant solution[python]?
-4
There are 3 numbers given, need to print min, then max, then the number in between.
I dont want to write it using ifs, I m seeking more elegant solution to find a number that's not min and max out of 3.
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = new list(a,b,c)
#how to exclude a 3rd element from a list that's not min and max?
number = list - m - minim
print(number)
python
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
|
show 1 more comment
-4
There are 3 numbers given, need to print min, then max, then the number in between.
I dont want to write it using ifs, I m seeking more elegant solution to find a number that's not min and max out of 3.
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = new list(a,b,c)
#how to exclude a 3rd element from a list that's not min and max?
number = list - m - minim
print(number)
python
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
1
I have no idea what you're asking.
– roganjosh
Nov 19 '18 at 15:35
new_list = [m, minim]
– floydya
Nov 19 '18 at 15:37
@roganjosh i have updated it sir, pls kindly look and help me
– ERJAN
Nov 19 '18 at 15:38
5
sorted([a,b,c])[1]?
– Chris_Rands
Nov 19 '18 at 15:39
2
It still doesn't make sense. What you've posted is not valid python. For 10k rep, I would have expected you can do equality checks. Why do you need to exclude the "middle" value here, since you never reference it anyway?
– roganjosh
Nov 19 '18 at 15:40
|
show 1 more comment
-4
-4
-4
There are 3 numbers given, need to print min, then max, then the number in between.
I dont want to write it using ifs, I m seeking more elegant solution to find a number that's not min and max out of 3.
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = new list(a,b,c)
#how to exclude a 3rd element from a list that's not min and max?
number = list - m - minim
print(number)
python
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
There are 3 numbers given, need to print min, then max, then the number in between.
I dont want to write it using ifs, I m seeking more elegant solution to find a number that's not min and max out of 3.
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = new list(a,b,c)
#how to exclude a 3rd element from a list that's not min and max?
number = list - m - minim
print(number)
python
python
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
edited Nov 19 '18 at 15:37
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
asked Nov 19 '18 at 15:34
ERJAN
9,205113466
9,205113466
1
I have no idea what you're asking.
– roganjosh
Nov 19 '18 at 15:35
new_list = [m, minim]
– floydya
Nov 19 '18 at 15:37
@roganjosh i have updated it sir, pls kindly look and help me
– ERJAN
Nov 19 '18 at 15:38
5
sorted([a,b,c])[1]?
– Chris_Rands
Nov 19 '18 at 15:39
2
It still doesn't make sense. What you've posted is not valid python. For 10k rep, I would have expected you can do equality checks. Why do you need to exclude the "middle" value here, since you never reference it anyway?
– roganjosh
Nov 19 '18 at 15:40
|
show 1 more comment
1
I have no idea what you're asking.
– roganjosh
Nov 19 '18 at 15:35
new_list = [m, minim]
– floydya
Nov 19 '18 at 15:37
@roganjosh i have updated it sir, pls kindly look and help me
– ERJAN
Nov 19 '18 at 15:38
5
sorted([a,b,c])[1]?
– Chris_Rands
Nov 19 '18 at 15:39
2
It still doesn't make sense. What you've posted is not valid python. For 10k rep, I would have expected you can do equality checks. Why do you need to exclude the "middle" value here, since you never reference it anyway?
– roganjosh
Nov 19 '18 at 15:40
1
1
I have no idea what you're asking.
– roganjosh
Nov 19 '18 at 15:35
I have no idea what you're asking.
– roganjosh
Nov 19 '18 at 15:35
new_list = [m, minim]– floydya
Nov 19 '18 at 15:37
new_list = [m, minim]– floydya
Nov 19 '18 at 15:37
@roganjosh i have updated it sir, pls kindly look and help me
– ERJAN
Nov 19 '18 at 15:38
@roganjosh i have updated it sir, pls kindly look and help me
– ERJAN
Nov 19 '18 at 15:38
5
5
sorted([a,b,c])[1] ?– Chris_Rands
Nov 19 '18 at 15:39
sorted([a,b,c])[1] ?– Chris_Rands
Nov 19 '18 at 15:39
2
2
It still doesn't make sense. What you've posted is not valid python. For 10k rep, I would have expected you can do equality checks. Why do you need to exclude the "middle" value here, since you never reference it anyway?
– roganjosh
Nov 19 '18 at 15:40
It still doesn't make sense. What you've posted is not valid python. For 10k rep, I would have expected you can do equality checks. Why do you need to exclude the "middle" value here, since you never reference it anyway?
– roganjosh
Nov 19 '18 at 15:40
|
show 1 more comment
2 Answers
2
active
oldest
votes
1
You can simply sort the list - minimum and maximum will be at the ends, and the middle number in the middle. Use index access () to fetch individual elements:
numbers = sorted((a, b, c))
print('minimum:', numbers[0])
print('maximum:', numbers[2])
print('middle :', numbers[1])
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
add a comment |
1
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = [a,b,c]
#sum - max - min
number = sum(l) - m - minim
print(number)
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can simply sort the list - minimum and maximum will be at the ends, and the middle number in the middle. Use index access () to fetch individual elements:
numbers = sorted((a, b, c))
print('minimum:', numbers[0])
print('maximum:', numbers[2])
print('middle :', numbers[1])
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
add a comment |
1
You can simply sort the list - minimum and maximum will be at the ends, and the middle number in the middle. Use index access () to fetch individual elements:
numbers = sorted((a, b, c))
print('minimum:', numbers[0])
print('maximum:', numbers[2])
print('middle :', numbers[1])
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
add a comment |
1
1
1
You can simply sort the list - minimum and maximum will be at the ends, and the middle number in the middle. Use index access () to fetch individual elements:
numbers = sorted((a, b, c))
print('minimum:', numbers[0])
print('maximum:', numbers[2])
print('middle :', numbers[1])
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
You can simply sort the list - minimum and maximum will be at the ends, and the middle number in the middle. Use index access () to fetch individual elements:
numbers = sorted((a, b, c))
print('minimum:', numbers[0])
print('maximum:', numbers[2])
print('middle :', numbers[1])
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
answered Nov 19 '18 at 15:41
MisterMiyagi
7,4042142
7,4042142
add a comment |
add a comment |
1
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = [a,b,c]
#sum - max - min
number = sum(l) - m - minim
print(number)
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
add a comment |
1
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = [a,b,c]
#sum - max - min
number = sum(l) - m - minim
print(number)
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
add a comment |
1
1
1
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = [a,b,c]
#sum - max - min
number = sum(l) - m - minim
print(number)
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
a = int(input())
b = int(input())
c = int(input())
m = max(a,b,c)
minim = min(a,b,c)
print(m)
print(minim)
l = [a,b,c]
#sum - max - min
number = sum(l) - m - minim
print(number)
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
answered Nov 19 '18 at 15:39
Rudolf Morkovskyi
720117
720117
add a comment |
add a comment |
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1
I have no idea what you're asking.
– roganjosh
Nov 19 '18 at 15:35
new_list = [m, minim]– floydya
Nov 19 '18 at 15:37
@roganjosh i have updated it sir, pls kindly look and help me
– ERJAN
Nov 19 '18 at 15:38
5
sorted([a,b,c])[1]?– Chris_Rands
Nov 19 '18 at 15:39
2
It still doesn't make sense. What you've posted is not valid python. For 10k rep, I would have expected you can do equality checks. Why do you need to exclude the "middle" value here, since you never reference it anyway?
– roganjosh
Nov 19 '18 at 15:40