Sql count() for two parameters












-1















How do I get count for two parameters for the following set:



beds : 2, classRate : 3
beds : 2, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 4
beds : 4, classRate : 4
beds : 4, classRate : 4


The result set should be:



beds : 2, classRate : 3, count :2
beds : 4, classRate : 3, count :4
beds : 4, classRate : 4, count :3









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  • 2





    Hint: GROUP BY.

    – Gordon Linoff
    Jan 1 at 14:18
















-1















How do I get count for two parameters for the following set:



beds : 2, classRate : 3
beds : 2, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 4
beds : 4, classRate : 4
beds : 4, classRate : 4


The result set should be:



beds : 2, classRate : 3, count :2
beds : 4, classRate : 3, count :4
beds : 4, classRate : 4, count :3









share|improve this question


















  • 2





    Hint: GROUP BY.

    – Gordon Linoff
    Jan 1 at 14:18














-1












-1








-1








How do I get count for two parameters for the following set:



beds : 2, classRate : 3
beds : 2, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 4
beds : 4, classRate : 4
beds : 4, classRate : 4


The result set should be:



beds : 2, classRate : 3, count :2
beds : 4, classRate : 3, count :4
beds : 4, classRate : 4, count :3









share|improve this question














How do I get count for two parameters for the following set:



beds : 2, classRate : 3
beds : 2, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 3
beds : 4, classRate : 4
beds : 4, classRate : 4
beds : 4, classRate : 4


The result set should be:



beds : 2, classRate : 3, count :2
beds : 4, classRate : 3, count :4
beds : 4, classRate : 4, count :3






sql count mariadb






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asked Jan 1 at 14:16









a_chubenkoa_chubenko

4816




4816








  • 2





    Hint: GROUP BY.

    – Gordon Linoff
    Jan 1 at 14:18














  • 2





    Hint: GROUP BY.

    – Gordon Linoff
    Jan 1 at 14:18








2




2





Hint: GROUP BY.

– Gordon Linoff
Jan 1 at 14:18





Hint: GROUP BY.

– Gordon Linoff
Jan 1 at 14:18












3 Answers
3






active

oldest

votes


















2














suppose that you have Table1 with (beds, classrates) columns then,



select beds, classrates, count(*) from table1 
group by beds, classrates


would to what you need






share|improve this answer































    0














    SELECT CLASS_RATE, BEDS, COUNT(*) AS CC FROM ROOMS
    WHERE (CLASS_RATE >= ? AND CLASS_RATE <= ?) GROUP BY CLASS_RATE, BEDS





    share|improve this answer
























    • It looks like your post is mostly code, please add some more details

      – Simonare
      Jan 1 at 16:20



















    -1














    select beds, classrates, count(*) from table1 group by beds, classrates



    Try this. Count(*) will return counting of result.






    share|improve this answer

























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      suppose that you have Table1 with (beds, classrates) columns then,



      select beds, classrates, count(*) from table1 
      group by beds, classrates


      would to what you need






      share|improve this answer




























        2














        suppose that you have Table1 with (beds, classrates) columns then,



        select beds, classrates, count(*) from table1 
        group by beds, classrates


        would to what you need






        share|improve this answer


























          2












          2








          2







          suppose that you have Table1 with (beds, classrates) columns then,



          select beds, classrates, count(*) from table1 
          group by beds, classrates


          would to what you need






          share|improve this answer













          suppose that you have Table1 with (beds, classrates) columns then,



          select beds, classrates, count(*) from table1 
          group by beds, classrates


          would to what you need







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 1 at 14:26









          SimonareSimonare

          15k11840




          15k11840

























              0














              SELECT CLASS_RATE, BEDS, COUNT(*) AS CC FROM ROOMS
              WHERE (CLASS_RATE >= ? AND CLASS_RATE <= ?) GROUP BY CLASS_RATE, BEDS





              share|improve this answer
























              • It looks like your post is mostly code, please add some more details

                – Simonare
                Jan 1 at 16:20
















              0














              SELECT CLASS_RATE, BEDS, COUNT(*) AS CC FROM ROOMS
              WHERE (CLASS_RATE >= ? AND CLASS_RATE <= ?) GROUP BY CLASS_RATE, BEDS





              share|improve this answer
























              • It looks like your post is mostly code, please add some more details

                – Simonare
                Jan 1 at 16:20














              0












              0








              0







              SELECT CLASS_RATE, BEDS, COUNT(*) AS CC FROM ROOMS
              WHERE (CLASS_RATE >= ? AND CLASS_RATE <= ?) GROUP BY CLASS_RATE, BEDS





              share|improve this answer













              SELECT CLASS_RATE, BEDS, COUNT(*) AS CC FROM ROOMS
              WHERE (CLASS_RATE >= ? AND CLASS_RATE <= ?) GROUP BY CLASS_RATE, BEDS






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Jan 1 at 14:28









              a_chubenkoa_chubenko

              4816




              4816













              • It looks like your post is mostly code, please add some more details

                – Simonare
                Jan 1 at 16:20



















              • It looks like your post is mostly code, please add some more details

                – Simonare
                Jan 1 at 16:20

















              It looks like your post is mostly code, please add some more details

              – Simonare
              Jan 1 at 16:20





              It looks like your post is mostly code, please add some more details

              – Simonare
              Jan 1 at 16:20











              -1














              select beds, classrates, count(*) from table1 group by beds, classrates



              Try this. Count(*) will return counting of result.






              share|improve this answer






























                -1














                select beds, classrates, count(*) from table1 group by beds, classrates



                Try this. Count(*) will return counting of result.






                share|improve this answer




























                  -1












                  -1








                  -1







                  select beds, classrates, count(*) from table1 group by beds, classrates



                  Try this. Count(*) will return counting of result.






                  share|improve this answer















                  select beds, classrates, count(*) from table1 group by beds, classrates



                  Try this. Count(*) will return counting of result.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jan 3 at 2:20

























                  answered Jan 1 at 14:26









                  Amit GandoleAmit Gandole

                  707




                  707






























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