Mixing
Access object inside array
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-1
I have an object and I want to access the value of types as a property to another object like a.Fax, a.Email, a.Call etc. But I have written a function down below and it pushes the values to a.ttt. So instead of ttt I want to access each value inside types i.e Fax, Email, Call, Text which is stored in ttt.
export const ActionTypes2 = [
{ value: "OtherLawyer", label: "Other Lawyer", types: ["Fax", "Email", "Call", "Text"] },
{ value: "OtherClerk", label: "Other Clerk", types: ["Fax", "Email", "Call", "Text"] },
{ value: "BrokerageAgent", label: "Brokerage Agent", types: ["Fax", "Email", "Call", "Text"] },
{ value: "Lawyer", label: "Lawyer", types: ["Email", "Call", "Text"] },
{ value: "Clerk", label: "Clerk", types: ["Email", "Call", "Text"] },
{ value: "Client", label: "Client", types: ["Email", "Call", "Text"] },
{ value: "ListingAgent", label: "Listing Agent", types: ["Email", "Call", "Text"] },
{ value: "CooperatingAgent", label: "Cooperating Agent", types: ["Email", "Call", "Text"] }
]
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(t);
// console.log(ttt);
})
})
console.log(f);
}
javascript
angular asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
add a comment |
-1
I have an object and I want to access the value of types as a property to another object like a.Fax, a.Email, a.Call etc. But I have written a function down below and it pushes the values to a.ttt. So instead of ttt I want to access each value inside types i.e Fax, Email, Call, Text which is stored in ttt.
export const ActionTypes2 = [
{ value: "OtherLawyer", label: "Other Lawyer", types: ["Fax", "Email", "Call", "Text"] },
{ value: "OtherClerk", label: "Other Clerk", types: ["Fax", "Email", "Call", "Text"] },
{ value: "BrokerageAgent", label: "Brokerage Agent", types: ["Fax", "Email", "Call", "Text"] },
{ value: "Lawyer", label: "Lawyer", types: ["Email", "Call", "Text"] },
{ value: "Clerk", label: "Clerk", types: ["Email", "Call", "Text"] },
{ value: "Client", label: "Client", types: ["Email", "Call", "Text"] },
{ value: "ListingAgent", label: "Listing Agent", types: ["Email", "Call", "Text"] },
{ value: "CooperatingAgent", label: "Cooperating Agent", types: ["Email", "Call", "Text"] }
]
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(t);
// console.log(ttt);
})
})
console.log(f);
}
javascript
angular asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
3
Please provide example result array
– styopdev
Jan 3 at 7:11
Your code should already work but you needif (!f[ttt]),f[ttt] = ;andf[ttt].push(t);. I would also advice to not use map but forEach, map is used to return a new array and usually does not mutate something or use reduce as in my answer as that's used to return a new value from an array of values (like sum an array of numbers).
– HMR
Jan 3 at 8:26
add a comment |
-1
-1
-1
I have an object and I want to access the value of types as a property to another object like a.Fax, a.Email, a.Call etc. But I have written a function down below and it pushes the values to a.ttt. So instead of ttt I want to access each value inside types i.e Fax, Email, Call, Text which is stored in ttt.
export const ActionTypes2 = [
{ value: "OtherLawyer", label: "Other Lawyer", types: ["Fax", "Email", "Call", "Text"] },
{ value: "OtherClerk", label: "Other Clerk", types: ["Fax", "Email", "Call", "Text"] },
{ value: "BrokerageAgent", label: "Brokerage Agent", types: ["Fax", "Email", "Call", "Text"] },
{ value: "Lawyer", label: "Lawyer", types: ["Email", "Call", "Text"] },
{ value: "Clerk", label: "Clerk", types: ["Email", "Call", "Text"] },
{ value: "Client", label: "Client", types: ["Email", "Call", "Text"] },
{ value: "ListingAgent", label: "Listing Agent", types: ["Email", "Call", "Text"] },
{ value: "CooperatingAgent", label: "Cooperating Agent", types: ["Email", "Call", "Text"] }
]
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(t);
// console.log(ttt);
})
})
console.log(f);
}
javascript
angular asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
I have an object and I want to access the value of types as a property to another object like a.Fax, a.Email, a.Call etc. But I have written a function down below and it pushes the values to a.ttt. So instead of ttt I want to access each value inside types i.e Fax, Email, Call, Text which is stored in ttt.
export const ActionTypes2 = [
{ value: "OtherLawyer", label: "Other Lawyer", types: ["Fax", "Email", "Call", "Text"] },
{ value: "OtherClerk", label: "Other Clerk", types: ["Fax", "Email", "Call", "Text"] },
{ value: "BrokerageAgent", label: "Brokerage Agent", types: ["Fax", "Email", "Call", "Text"] },
{ value: "Lawyer", label: "Lawyer", types: ["Email", "Call", "Text"] },
{ value: "Clerk", label: "Clerk", types: ["Email", "Call", "Text"] },
{ value: "Client", label: "Client", types: ["Email", "Call", "Text"] },
{ value: "ListingAgent", label: "Listing Agent", types: ["Email", "Call", "Text"] },
{ value: "CooperatingAgent", label: "Cooperating Agent", types: ["Email", "Call", "Text"] }
]
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(t);
// console.log(ttt);
})
})
console.log(f);
}
javascript
angular javascript
angular asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
asked Jan 3 at 7:03
Ammar HussainAmmar Hussain
1067
1067
3
Please provide example result array
– styopdev
Jan 3 at 7:11
Your code should already work but you needif (!f[ttt]),f[ttt] = ;andf[ttt].push(t);. I would also advice to not use map but forEach, map is used to return a new array and usually does not mutate something or use reduce as in my answer as that's used to return a new value from an array of values (like sum an array of numbers).
– HMR
Jan 3 at 8:26
add a comment |
3
Please provide example result array
– styopdev
Jan 3 at 7:11
Your code should already work but you needif (!f[ttt]),f[ttt] = ;andf[ttt].push(t);. I would also advice to not use map but forEach, map is used to return a new array and usually does not mutate something or use reduce as in my answer as that's used to return a new value from an array of values (like sum an array of numbers).
– HMR
Jan 3 at 8:26
3
3
Please provide example result array
– styopdev
Jan 3 at 7:11
Please provide example result array
– styopdev
Jan 3 at 7:11
Your code should already work but you need
if (!f[ttt]) , f[ttt] = ; and f[ttt].push(t);. I would also advice to not use map but forEach, map is used to return a new array and usually does not mutate something or use reduce as in my answer as that's used to return a new value from an array of values (like sum an array of numbers).– HMR
Jan 3 at 8:26
Your code should already work but you need
if (!f[ttt]) , f[ttt] = ; and f[ttt].push(t);. I would also advice to not use map but forEach, map is used to return a new array and usually does not mutate something or use reduce as in my answer as that's used to return a new value from an array of values (like sum an array of numbers).– HMR
Jan 3 at 8:26
add a comment |
3 Answers
3
active
oldest
votes
0
How about below,
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(tt.types);
})
console.log(f.ttt); }
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
add a comment |
0
you should replace f.ttt with f[ttt] as follows
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f[ttt]) {
f[ttt] = ;
}
f[ttt].push(t);
// console.log(ttt);
})
})
console.log(f);
}
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
add a comment |
0
You can reduce the array to an object (note that SO prints the console a bit strange, press F12 and check out the console for the actual result):
const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));Array.prototype.map is used to convert an array of 'T to an array of 'U or even produce a new array of the same type but doubled (for example [1,2,3].map(x=>x*2)). The function passed to map should be a pure function so it should not use or mutate something defined outside the function or change the array being mapped.
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
How about below,
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(tt.types);
})
console.log(f.ttt); }
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
add a comment |
0
How about below,
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(tt.types);
})
console.log(f.ttt); }
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
add a comment |
0
0
0
How about below,
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(tt.types);
})
console.log(f.ttt); }
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
How about below,
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
if (!f.ttt) {
f.ttt = ;
}
f.ttt.push(tt.types);
})
console.log(f.ttt); }
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
edited Jan 3 at 7:58
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
answered Jan 3 at 7:52
Jitendra G2Jitendra G2
803612
803612
add a comment |
add a comment |
0
you should replace f.ttt with f[ttt] as follows
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f[ttt]) {
f[ttt] = ;
}
f[ttt].push(t);
// console.log(ttt);
})
})
console.log(f);
}
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
add a comment |
0
you should replace f.ttt with f[ttt] as follows
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f[ttt]) {
f[ttt] = ;
}
f[ttt].push(t);
// console.log(ttt);
})
})
console.log(f);
}
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
add a comment |
0
0
0
you should replace f.ttt with f[ttt] as follows
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f[ttt]) {
f[ttt] = ;
}
f[ttt].push(t);
// console.log(ttt);
})
})
console.log(f);
}
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
you should replace f.ttt with f[ttt] as follows
getActionTypes() {
let t = ActionTypes2;
let f = <any>{};
t.map((tt: any) => {
tt.types.map((ttt: any) => {
if (!f[ttt]) {
f[ttt] = ;
}
f[ttt].push(t);
// console.log(ttt);
})
})
console.log(f);
}
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
answered Jan 3 at 8:09
Mohit PatilMohit Patil
8619
8619
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
add a comment |
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
Method passed to map should be a pure function, if you mutate or use something defined outside of the function you should probably use forEach instead. However; this could be more easily accomplished using reduce.
– HMR
Jan 3 at 8:18
add a comment |
0
You can reduce the array to an object (note that SO prints the console a bit strange, press F12 and check out the console for the actual result):
const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));Array.prototype.map is used to convert an array of 'T to an array of 'U or even produce a new array of the same type but doubled (for example [1,2,3].map(x=>x*2)). The function passed to map should be a pure function so it should not use or mutate something defined outside the function or change the array being mapped.
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
add a comment |
0
You can reduce the array to an object (note that SO prints the console a bit strange, press F12 and check out the console for the actual result):
const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));Array.prototype.map is used to convert an array of 'T to an array of 'U or even produce a new array of the same type but doubled (for example [1,2,3].map(x=>x*2)). The function passed to map should be a pure function so it should not use or mutate something defined outside the function or change the array being mapped.
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
add a comment |
0
0
0
You can reduce the array to an object (note that SO prints the console a bit strange, press F12 and check out the console for the actual result):
const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));Array.prototype.map is used to convert an array of 'T to an array of 'U or even produce a new array of the same type but doubled (for example [1,2,3].map(x=>x*2)). The function passed to map should be a pure function so it should not use or mutate something defined outside the function or change the array being mapped.
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
You can reduce the array to an object (note that SO prints the console a bit strange, press F12 and check out the console for the actual result):
const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));Array.prototype.map is used to convert an array of 'T to an array of 'U or even produce a new array of the same type but doubled (for example [1,2,3].map(x=>x*2)). The function passed to map should be a pure function so it should not use or mutate something defined outside the function or change the array being mapped.
const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));const data = [{"value":"OtherLawyer","label":"Other Lawyer","types":["Fax","Email","Call","Text"]},{"value":"OtherClerk","label":"Other Clerk","types":["Fax","Email","Call","Text"]},{"value":"BrokerageAgent","label":"Brokerage Agent","types":["Fax","Email","Call","Text"]},{"value":"Lawyer","label":"Lawyer","types":["Email","Call","Text"]},{"value":"Clerk","label":"Clerk","types":["Email","Call","Text"]},{"value":"Client","label":"Client","types":["Email","Call","Text"]},{"value":"ListingAgent","label":"Listing Agent","types":["Email","Call","Text"]},{"value":"CooperatingAgent","label":"Cooperating Agent","types":["Email","Call","Text"]}];
const groupByType = (data) =>
data.reduce(
(result, { types, ...rest }) =>
types.reduce((result, type) => {
result[type] = result[type] || ;
result[type].push(rest);
return result;
}, result),
{},
);
console.log(groupByType(data));answered Jan 3 at 8:13
HMRHMR
14.1k1138102
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
answered Jan 3 at 8:13
HMRHMR
14.1k1138102
14.1k1138102
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3
Please provide example result array
– styopdev
Jan 3 at 7:11
Your code should already work but you need
if (!f[ttt]),f[ttt] = ;andf[ttt].push(t);. I would also advice to not use map but forEach, map is used to return a new array and usually does not mutate something or use reduce as in my answer as that's used to return a new value from an array of values (like sum an array of numbers).– HMR
Jan 3 at 8:26