Mixing
Calculating relative difference between two data sets which include negative numbers
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I need to determine the relative difference between each element in vector 'A' and its corresponding element in 'B'. The vectors are:
A = 18.40,6.06,12.46,25.25,60.00,30.77,48.95,35.77,29.73,38.40,36.36,35.33,20.18,82.46,34.25,10.83,49.08,25.00,63.06,-5.31,15.55,35.02,15.96
B = -2.40,-43.94,-2.36,-6.57,21.82,11.83,20.92,15.45,17.57,24.80,24.24,24,14.8,74.85,33.33,10.83,49.21,25.56,64.72,-5.54,16.39,40.11,36.17
Normally I would simply divide A by B to get the ratio between the two numbers, however these data vectors contain negative numbers meaning the magnitude of the absolute difference (A-B) between A and B is not being captured. Is there a way to transform the data such that I always get a positive ratio between the two numbers and that for example A=6.06 and B=-43.94 (absolute difference = 50.00) gives a larger ratio than e.g. A=60.00 and B=21.82?
Thank you for your time,
Laura
ratio
asked Jul 5 '17 at 14:40
Laura Laura
1
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add a comment |
$begingroup$
I need to determine the relative difference between each element in vector 'A' and its corresponding element in 'B'. The vectors are:
A = 18.40,6.06,12.46,25.25,60.00,30.77,48.95,35.77,29.73,38.40,36.36,35.33,20.18,82.46,34.25,10.83,49.08,25.00,63.06,-5.31,15.55,35.02,15.96
B = -2.40,-43.94,-2.36,-6.57,21.82,11.83,20.92,15.45,17.57,24.80,24.24,24,14.8,74.85,33.33,10.83,49.21,25.56,64.72,-5.54,16.39,40.11,36.17
Normally I would simply divide A by B to get the ratio between the two numbers, however these data vectors contain negative numbers meaning the magnitude of the absolute difference (A-B) between A and B is not being captured. Is there a way to transform the data such that I always get a positive ratio between the two numbers and that for example A=6.06 and B=-43.94 (absolute difference = 50.00) gives a larger ratio than e.g. A=60.00 and B=21.82?
Thank you for your time,
Laura
ratio
asked Jul 5 '17 at 14:40
Laura Laura
1
$endgroup$
add a comment |
$begingroup$
I need to determine the relative difference between each element in vector 'A' and its corresponding element in 'B'. The vectors are:
A = 18.40,6.06,12.46,25.25,60.00,30.77,48.95,35.77,29.73,38.40,36.36,35.33,20.18,82.46,34.25,10.83,49.08,25.00,63.06,-5.31,15.55,35.02,15.96
B = -2.40,-43.94,-2.36,-6.57,21.82,11.83,20.92,15.45,17.57,24.80,24.24,24,14.8,74.85,33.33,10.83,49.21,25.56,64.72,-5.54,16.39,40.11,36.17
Normally I would simply divide A by B to get the ratio between the two numbers, however these data vectors contain negative numbers meaning the magnitude of the absolute difference (A-B) between A and B is not being captured. Is there a way to transform the data such that I always get a positive ratio between the two numbers and that for example A=6.06 and B=-43.94 (absolute difference = 50.00) gives a larger ratio than e.g. A=60.00 and B=21.82?
Thank you for your time,
Laura
ratio
asked Jul 5 '17 at 14:40
Laura Laura
1
$endgroup$
I need to determine the relative difference between each element in vector 'A' and its corresponding element in 'B'. The vectors are:
A = 18.40,6.06,12.46,25.25,60.00,30.77,48.95,35.77,29.73,38.40,36.36,35.33,20.18,82.46,34.25,10.83,49.08,25.00,63.06,-5.31,15.55,35.02,15.96
B = -2.40,-43.94,-2.36,-6.57,21.82,11.83,20.92,15.45,17.57,24.80,24.24,24,14.8,74.85,33.33,10.83,49.21,25.56,64.72,-5.54,16.39,40.11,36.17
Normally I would simply divide A by B to get the ratio between the two numbers, however these data vectors contain negative numbers meaning the magnitude of the absolute difference (A-B) between A and B is not being captured. Is there a way to transform the data such that I always get a positive ratio between the two numbers and that for example A=6.06 and B=-43.94 (absolute difference = 50.00) gives a larger ratio than e.g. A=60.00 and B=21.82?
Thank you for your time,
Laura
ratio
ratio
asked Jul 5 '17 at 14:40
Laura Laura
1
asked Jul 5 '17 at 14:40
Laura Laura
1
asked Jul 5 '17 at 14:40
Laura Laura
1
asked Jul 5 '17 at 14:40
Laura Laura
1
asked Jul 5 '17 at 14:40
Laura Laura
1
1
add a comment |
add a comment |
1 Answer
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You may use the formula for relative difference:
$$frac{|x-y|}{max(|x|,|y|)}.$$
It is always positive but between the values of $x, y$ at least one must be non-zero.
answered Jul 5 '17 at 15:41
alephaleph
177
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Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
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Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
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Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
add a comment |
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1 Answer
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1 Answer
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$begingroup$
You may use the formula for relative difference:
$$frac{|x-y|}{max(|x|,|y|)}.$$
It is always positive but between the values of $x, y$ at least one must be non-zero.
answered Jul 5 '17 at 15:41
alephaleph
177
$endgroup$
$begingroup$
Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
$begingroup$
Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
$begingroup$
Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
add a comment |
$begingroup$
You may use the formula for relative difference:
$$frac{|x-y|}{max(|x|,|y|)}.$$
It is always positive but between the values of $x, y$ at least one must be non-zero.
answered Jul 5 '17 at 15:41
alephaleph
177
$endgroup$
$begingroup$
Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
$begingroup$
Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
$begingroup$
Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
add a comment |
$begingroup$
You may use the formula for relative difference:
$$frac{|x-y|}{max(|x|,|y|)}.$$
It is always positive but between the values of $x, y$ at least one must be non-zero.
answered Jul 5 '17 at 15:41
alephaleph
177
$endgroup$
You may use the formula for relative difference:
$$frac{|x-y|}{max(|x|,|y|)}.$$
It is always positive but between the values of $x, y$ at least one must be non-zero.
answered Jul 5 '17 at 15:41
alephaleph
177
answered Jul 5 '17 at 15:41
alephaleph
177
answered Jul 5 '17 at 15:41
alephaleph
177
answered Jul 5 '17 at 15:41
alephaleph
177
177
$begingroup$
Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
$begingroup$
Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
$begingroup$
Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
add a comment |
$begingroup$
Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
$begingroup$
Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
$begingroup$
Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
$begingroup$
Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
$begingroup$
Thank you for your answer. Could you please explain what you mean by the comma between the absolute values of x and y?
$endgroup$
– Laura
Jul 6 '17 at 9:19
$begingroup$
Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
$begingroup$
Yes off course. It means that between the absolute values of $x ,y$ you pick the maximum.
$endgroup$
– aleph
Jul 6 '17 at 10:18
$begingroup$
Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Thank you. To make sure I have this absolutely correct, could you please confirm that an example calculation from the first elements of the data vectors would be: (18.40--2.40) / 18.4 I.e. the max value used is of the specific x and y values and not of the maximum of the whole data vector?
$endgroup$
– Laura
Jul 6 '17 at 10:29
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
$begingroup$
Yes, that is correct :)
$endgroup$
– aleph
Jul 6 '17 at 10:53
add a comment |
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