Mixing
Dunford-Pettis for Banach-Spaces
1
$begingroup$
Can anyone tell me if the Dunford-Pettis property is met for a separate refelxive Banach space $X$ with dual $X'$?
I would say that this is the case.
functional-analysis banach-spaces dual-spaces
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
$endgroup$
add a comment |
1
$begingroup$
Can anyone tell me if the Dunford-Pettis property is met for a separate refelxive Banach space $X$ with dual $X'$?
I would say that this is the case.
functional-analysis banach-spaces dual-spaces
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
$endgroup$
1
$begingroup$
No.
$endgroup$
– Theo Bendit
Jan 31 at 11:04
$begingroup$
This means, that the $L^p$-Space (for $1<p<infty$) do not have we Dunford Pettis property. Is there a similar statement for such rooms?
$endgroup$
– FuncAna09
Jan 31 at 15:55
add a comment |
1
1
1
$begingroup$
Can anyone tell me if the Dunford-Pettis property is met for a separate refelxive Banach space $X$ with dual $X'$?
I would say that this is the case.
functional-analysis banach-spaces dual-spaces
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
$endgroup$
Can anyone tell me if the Dunford-Pettis property is met for a separate refelxive Banach space $X$ with dual $X'$?
I would say that this is the case.
functional-analysis banach-spaces dual-spaces
functional-analysis banach-spaces dual-spaces
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
edited Jan 31 at 11:37
YuiTo Cheng
2,3084937
2,3084937
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
asked Jan 31 at 10:38
FuncAna09FuncAna09
113
113
1
$begingroup$
No.
$endgroup$
– Theo Bendit
Jan 31 at 11:04
$begingroup$
This means, that the $L^p$-Space (for $1<p<infty$) do not have we Dunford Pettis property. Is there a similar statement for such rooms?
$endgroup$
– FuncAna09
Jan 31 at 15:55
add a comment |
1
$begingroup$
No.
$endgroup$
– Theo Bendit
Jan 31 at 11:04
$begingroup$
This means, that the $L^p$-Space (for $1<p<infty$) do not have we Dunford Pettis property. Is there a similar statement for such rooms?
$endgroup$
– FuncAna09
Jan 31 at 15:55
1
1
$begingroup$
No.
$endgroup$
– Theo Bendit
Jan 31 at 11:04
$begingroup$
No.
$endgroup$
– Theo Bendit
Jan 31 at 11:04
$begingroup$
This means, that the $L^p$-Space (for $1<p<infty$) do not have we Dunford Pettis property. Is there a similar statement for such rooms?
$endgroup$
– FuncAna09
Jan 31 at 15:55
$begingroup$
This means, that the $L^p$-Space (for $1<p<infty$) do not have we Dunford Pettis property. Is there a similar statement for such rooms?
$endgroup$
– FuncAna09
Jan 31 at 15:55
add a comment |
0
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1
$begingroup$
No.
$endgroup$
– Theo Bendit
Jan 31 at 11:04
$begingroup$
This means, that the $L^p$-Space (for $1<p<infty$) do not have we Dunford Pettis property. Is there a similar statement for such rooms?
$endgroup$
– FuncAna09
Jan 31 at 15:55