How to use the service mentioned in the documentation to generate a url?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I don't know how to use the url generated by the service.
This is the link:
symfony Routing
Symfony Version:Symfony 4.2.1 (env: dev, debug: true)
I created a service file.
└── Service
└── SomeService.php
namespace AppService;
use SymfonyComponentRoutingGeneratorUrlGeneratorInterface;
class SomeService {
private $router;
public function __construct(UrlGeneratorInterface $router) {
$this->router = $router;
}
public function someMethod() {
$url = $this->router->generate(
'blog_show',
['slug' => 'my-blog-post']
);
return $url;
}
}
I created controller file.
├── Controller
│ ├── BlogController.php
namespace AppController;
use SymfonyBundleFrameworkBundleControllerAbstractController;
use SymfonyComponentHttpFoundationJsonResponse;
use SymfonyComponentHttpFoundationRedirectResponse;
use SymfonyComponentHttpFoundationResponse;
use SymfonyComponentRoutingAnnotationRoute;
class BlogController extends AbstractController {
/**
* Matches /blog exactly
* @Route("/blog/{page?1}", name="blog_list", requirements={"page"="d+"})
*/
public function list($page = 1) {
// $url = $this->generateUrl(
// 'blog_slug',
// ['slug' => 'my-blog-post']
// );
// RedirectResponse
// return new RedirectResponse($url);
// JsonResponse
return new JsonResponse(['page' => $page, 'url' => $url], 200);
// Redponse
// return new Response("This is list controlelr. Page: ".$page. "<br>URL: " . $url);
}
/**
* Matches /blog/*
*
* @Route("/blog/{slug}", name="blog_slug")
*
*/
public function show($slug) {
// $slug will equal the dynamic part of the URL
// e.g. at /blog/yay-routing, then $slug='yay-routing'
// ...
return new Response("This is show controller.".$slug);
}
}
How do I call a service in a controller?
How do I use the url created by the service in the controller list method?
symfony
add a comment |
I don't know how to use the url generated by the service.
This is the link:
symfony Routing
Symfony Version:Symfony 4.2.1 (env: dev, debug: true)
I created a service file.
└── Service
└── SomeService.php
namespace AppService;
use SymfonyComponentRoutingGeneratorUrlGeneratorInterface;
class SomeService {
private $router;
public function __construct(UrlGeneratorInterface $router) {
$this->router = $router;
}
public function someMethod() {
$url = $this->router->generate(
'blog_show',
['slug' => 'my-blog-post']
);
return $url;
}
}
I created controller file.
├── Controller
│ ├── BlogController.php
namespace AppController;
use SymfonyBundleFrameworkBundleControllerAbstractController;
use SymfonyComponentHttpFoundationJsonResponse;
use SymfonyComponentHttpFoundationRedirectResponse;
use SymfonyComponentHttpFoundationResponse;
use SymfonyComponentRoutingAnnotationRoute;
class BlogController extends AbstractController {
/**
* Matches /blog exactly
* @Route("/blog/{page?1}", name="blog_list", requirements={"page"="d+"})
*/
public function list($page = 1) {
// $url = $this->generateUrl(
// 'blog_slug',
// ['slug' => 'my-blog-post']
// );
// RedirectResponse
// return new RedirectResponse($url);
// JsonResponse
return new JsonResponse(['page' => $page, 'url' => $url], 200);
// Redponse
// return new Response("This is list controlelr. Page: ".$page. "<br>URL: " . $url);
}
/**
* Matches /blog/*
*
* @Route("/blog/{slug}", name="blog_slug")
*
*/
public function show($slug) {
// $slug will equal the dynamic part of the URL
// e.g. at /blog/yay-routing, then $slug='yay-routing'
// ...
return new Response("This is show controller.".$slug);
}
}
How do I call a service in a controller?
How do I use the url created by the service in the controller list method?
symfony
You can use :$this->get('service_name')->someMethod();
– Sylvain Attoumani
Jan 3 at 8:53
You should inject your service via Controller's__construct
in the same manner you do that in your service
– malarzm
Jan 3 at 9:33
@malarzm Thank you.
– shaolong zhu
Jan 3 at 9:44
use AppServiceSomeService; protected $url; public function __construct(SomeService $service) { $this->url = $service; }
– shaolong zhu
Jan 3 at 9:45
add a comment |
I don't know how to use the url generated by the service.
This is the link:
symfony Routing
Symfony Version:Symfony 4.2.1 (env: dev, debug: true)
I created a service file.
└── Service
└── SomeService.php
namespace AppService;
use SymfonyComponentRoutingGeneratorUrlGeneratorInterface;
class SomeService {
private $router;
public function __construct(UrlGeneratorInterface $router) {
$this->router = $router;
}
public function someMethod() {
$url = $this->router->generate(
'blog_show',
['slug' => 'my-blog-post']
);
return $url;
}
}
I created controller file.
├── Controller
│ ├── BlogController.php
namespace AppController;
use SymfonyBundleFrameworkBundleControllerAbstractController;
use SymfonyComponentHttpFoundationJsonResponse;
use SymfonyComponentHttpFoundationRedirectResponse;
use SymfonyComponentHttpFoundationResponse;
use SymfonyComponentRoutingAnnotationRoute;
class BlogController extends AbstractController {
/**
* Matches /blog exactly
* @Route("/blog/{page?1}", name="blog_list", requirements={"page"="d+"})
*/
public function list($page = 1) {
// $url = $this->generateUrl(
// 'blog_slug',
// ['slug' => 'my-blog-post']
// );
// RedirectResponse
// return new RedirectResponse($url);
// JsonResponse
return new JsonResponse(['page' => $page, 'url' => $url], 200);
// Redponse
// return new Response("This is list controlelr. Page: ".$page. "<br>URL: " . $url);
}
/**
* Matches /blog/*
*
* @Route("/blog/{slug}", name="blog_slug")
*
*/
public function show($slug) {
// $slug will equal the dynamic part of the URL
// e.g. at /blog/yay-routing, then $slug='yay-routing'
// ...
return new Response("This is show controller.".$slug);
}
}
How do I call a service in a controller?
How do I use the url created by the service in the controller list method?
symfony
I don't know how to use the url generated by the service.
This is the link:
symfony Routing
Symfony Version:Symfony 4.2.1 (env: dev, debug: true)
I created a service file.
└── Service
└── SomeService.php
namespace AppService;
use SymfonyComponentRoutingGeneratorUrlGeneratorInterface;
class SomeService {
private $router;
public function __construct(UrlGeneratorInterface $router) {
$this->router = $router;
}
public function someMethod() {
$url = $this->router->generate(
'blog_show',
['slug' => 'my-blog-post']
);
return $url;
}
}
I created controller file.
├── Controller
│ ├── BlogController.php
namespace AppController;
use SymfonyBundleFrameworkBundleControllerAbstractController;
use SymfonyComponentHttpFoundationJsonResponse;
use SymfonyComponentHttpFoundationRedirectResponse;
use SymfonyComponentHttpFoundationResponse;
use SymfonyComponentRoutingAnnotationRoute;
class BlogController extends AbstractController {
/**
* Matches /blog exactly
* @Route("/blog/{page?1}", name="blog_list", requirements={"page"="d+"})
*/
public function list($page = 1) {
// $url = $this->generateUrl(
// 'blog_slug',
// ['slug' => 'my-blog-post']
// );
// RedirectResponse
// return new RedirectResponse($url);
// JsonResponse
return new JsonResponse(['page' => $page, 'url' => $url], 200);
// Redponse
// return new Response("This is list controlelr. Page: ".$page. "<br>URL: " . $url);
}
/**
* Matches /blog/*
*
* @Route("/blog/{slug}", name="blog_slug")
*
*/
public function show($slug) {
// $slug will equal the dynamic part of the URL
// e.g. at /blog/yay-routing, then $slug='yay-routing'
// ...
return new Response("This is show controller.".$slug);
}
}
How do I call a service in a controller?
How do I use the url created by the service in the controller list method?
symfony
symfony
asked Jan 3 at 8:48
shaolong zhushaolong zhu
61
61
You can use :$this->get('service_name')->someMethod();
– Sylvain Attoumani
Jan 3 at 8:53
You should inject your service via Controller's__construct
in the same manner you do that in your service
– malarzm
Jan 3 at 9:33
@malarzm Thank you.
– shaolong zhu
Jan 3 at 9:44
use AppServiceSomeService; protected $url; public function __construct(SomeService $service) { $this->url = $service; }
– shaolong zhu
Jan 3 at 9:45
add a comment |
You can use :$this->get('service_name')->someMethod();
– Sylvain Attoumani
Jan 3 at 8:53
You should inject your service via Controller's__construct
in the same manner you do that in your service
– malarzm
Jan 3 at 9:33
@malarzm Thank you.
– shaolong zhu
Jan 3 at 9:44
use AppServiceSomeService; protected $url; public function __construct(SomeService $service) { $this->url = $service; }
– shaolong zhu
Jan 3 at 9:45
You can use :
$this->get('service_name')->someMethod();
– Sylvain Attoumani
Jan 3 at 8:53
You can use :
$this->get('service_name')->someMethod();
– Sylvain Attoumani
Jan 3 at 8:53
You should inject your service via Controller's
__construct
in the same manner you do that in your service– malarzm
Jan 3 at 9:33
You should inject your service via Controller's
__construct
in the same manner you do that in your service– malarzm
Jan 3 at 9:33
@malarzm Thank you.
– shaolong zhu
Jan 3 at 9:44
@malarzm Thank you.
– shaolong zhu
Jan 3 at 9:44
use AppServiceSomeService; protected $url; public function __construct(SomeService $service) { $this->url = $service; }
– shaolong zhu
Jan 3 at 9:45
use AppServiceSomeService; protected $url; public function __construct(SomeService $service) { $this->url = $service; }
– shaolong zhu
Jan 3 at 9:45
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54018932%2fhow-to-use-the-service-mentioned-in-the-documentation-to-generate-a-url%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54018932%2fhow-to-use-the-service-mentioned-in-the-documentation-to-generate-a-url%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
You can use :
$this->get('service_name')->someMethod();
– Sylvain Attoumani
Jan 3 at 8:53
You should inject your service via Controller's
__construct
in the same manner you do that in your service– malarzm
Jan 3 at 9:33
@malarzm Thank you.
– shaolong zhu
Jan 3 at 9:44
use AppServiceSomeService; protected $url; public function __construct(SomeService $service) { $this->url = $service; }
– shaolong zhu
Jan 3 at 9:45