Mixing
Systems of Linear Equations Matrices
0
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Find examples of matrices that exhibit the following behavior.
2 × 2 matrices B and C such that BC = −CB (excluding the case BC = 0).
matrices
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
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add a comment |
0
$begingroup$
Find examples of matrices that exhibit the following behavior.
2 × 2 matrices B and C such that BC = −CB (excluding the case BC = 0).
matrices
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
$endgroup$
$begingroup$
Here's a hint: if you take the determinant of both sides, you get $det B det C = - det B det C$, which implies that either $det B = 0$ and/or $det C = 0$.
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– Trevor Kafka
Feb 3 at 6:02
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$begingroup$
Find examples of matrices that exhibit the following behavior.
2 × 2 matrices B and C such that BC = −CB (excluding the case BC = 0).
matrices
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
$endgroup$
Find examples of matrices that exhibit the following behavior.
2 × 2 matrices B and C such that BC = −CB (excluding the case BC = 0).
matrices
matrices
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
asked Feb 3 at 3:29
Mandlah SibandaMandlah Sibanda
41
41
$begingroup$
Here's a hint: if you take the determinant of both sides, you get $det B det C = - det B det C$, which implies that either $det B = 0$ and/or $det C = 0$.
$endgroup$
– Trevor Kafka
Feb 3 at 6:02
add a comment |
$begingroup$
Here's a hint: if you take the determinant of both sides, you get $det B det C = - det B det C$, which implies that either $det B = 0$ and/or $det C = 0$.
$endgroup$
– Trevor Kafka
Feb 3 at 6:02
$begingroup$
Here's a hint: if you take the determinant of both sides, you get $det B det C = - det B det C$, which implies that either $det B = 0$ and/or $det C = 0$.
$endgroup$
– Trevor Kafka
Feb 3 at 6:02
$begingroup$
Here's a hint: if you take the determinant of both sides, you get $det B det C = - det B det C$, which implies that either $det B = 0$ and/or $det C = 0$.
$endgroup$
– Trevor Kafka
Feb 3 at 6:02
add a comment |
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$begingroup$
Here's a hint: if you take the determinant of both sides, you get $det B det C = - det B det C$, which implies that either $det B = 0$ and/or $det C = 0$.
$endgroup$
– Trevor Kafka
Feb 3 at 6:02