What does it mean to be a measurable function from a measurable set?
$begingroup$
let $(X,Sigma)$ be a measure space, and let $Ain Sigma$. What does it mean to say that $f:Atomathbb{R}$ is measurable?
what is the $sigma$-algebra on A?
measure-theory
$endgroup$
add a comment |
$begingroup$
let $(X,Sigma)$ be a measure space, and let $Ain Sigma$. What does it mean to say that $f:Atomathbb{R}$ is measurable?
what is the $sigma$-algebra on A?
measure-theory
$endgroup$
add a comment |
$begingroup$
let $(X,Sigma)$ be a measure space, and let $Ain Sigma$. What does it mean to say that $f:Atomathbb{R}$ is measurable?
what is the $sigma$-algebra on A?
measure-theory
$endgroup$
let $(X,Sigma)$ be a measure space, and let $Ain Sigma$. What does it mean to say that $f:Atomathbb{R}$ is measurable?
what is the $sigma$-algebra on A?
measure-theory
measure-theory
asked Feb 1 at 9:34
SlyxBrdSlyxBrd
449
449
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1 Answer
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$begingroup$
Since $Ain Sigma$, the $ sigma - $ algebra on $A$ is given by
$${B in Sigma: B subseteq A}.$$
$endgroup$
add a comment |
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1 Answer
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1 Answer
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active
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active
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votes
$begingroup$
Since $Ain Sigma$, the $ sigma - $ algebra on $A$ is given by
$${B in Sigma: B subseteq A}.$$
$endgroup$
add a comment |
$begingroup$
Since $Ain Sigma$, the $ sigma - $ algebra on $A$ is given by
$${B in Sigma: B subseteq A}.$$
$endgroup$
add a comment |
$begingroup$
Since $Ain Sigma$, the $ sigma - $ algebra on $A$ is given by
$${B in Sigma: B subseteq A}.$$
$endgroup$
Since $Ain Sigma$, the $ sigma - $ algebra on $A$ is given by
$${B in Sigma: B subseteq A}.$$
answered Feb 1 at 9:39


FredFred
48.5k11849
48.5k11849
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