Mixing
Converse, Inverse, and Contrapositive: Please check my answers.
$begingroup$
Statement: If you finish your work, you can watch movies
converse -> If you can watch movies, then you finished your work.
inverse -> If you did not finish your work, then you can not watch movies.
contrapositive -> If you can not watch movies, then you did not finish your work.
Are they right?
logic
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
$endgroup$
add a comment |
$begingroup$
Statement: If you finish your work, you can watch movies
converse -> If you can watch movies, then you finished your work.
inverse -> If you did not finish your work, then you can not watch movies.
contrapositive -> If you can not watch movies, then you did not finish your work.
Are they right?
logic
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
$endgroup$
1
$begingroup$
I'm curious, why were you unsure of these in the first place?
$endgroup$
– Eric Tressler
Jul 29 '13 at 23:49
$begingroup$
From the amount of logic questions the OP has been asking, I think he is just preparing for an upcoming test.
$endgroup$
– Sujaan Kunalan
Jul 29 '13 at 23:50
$begingroup$
@SujaanKunalan Correct.
$endgroup$
– MethodManX
Jul 29 '13 at 23:55
add a comment |
$begingroup$
Statement: If you finish your work, you can watch movies
converse -> If you can watch movies, then you finished your work.
inverse -> If you did not finish your work, then you can not watch movies.
contrapositive -> If you can not watch movies, then you did not finish your work.
Are they right?
logic
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
$endgroup$
Statement: If you finish your work, you can watch movies
converse -> If you can watch movies, then you finished your work.
inverse -> If you did not finish your work, then you can not watch movies.
contrapositive -> If you can not watch movies, then you did not finish your work.
Are they right?
logic
logic
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
asked Jul 29 '13 at 23:44
MethodManXMethodManX
594112135
594112135
1
$begingroup$
I'm curious, why were you unsure of these in the first place?
$endgroup$
– Eric Tressler
Jul 29 '13 at 23:49
$begingroup$
From the amount of logic questions the OP has been asking, I think he is just preparing for an upcoming test.
$endgroup$
– Sujaan Kunalan
Jul 29 '13 at 23:50
$begingroup$
@SujaanKunalan Correct.
$endgroup$
– MethodManX
Jul 29 '13 at 23:55
add a comment |
1
$begingroup$
I'm curious, why were you unsure of these in the first place?
$endgroup$
– Eric Tressler
Jul 29 '13 at 23:49
$begingroup$
From the amount of logic questions the OP has been asking, I think he is just preparing for an upcoming test.
$endgroup$
– Sujaan Kunalan
Jul 29 '13 at 23:50
$begingroup$
@SujaanKunalan Correct.
$endgroup$
– MethodManX
Jul 29 '13 at 23:55
1
1
$begingroup$
I'm curious, why were you unsure of these in the first place?
$endgroup$
– Eric Tressler
Jul 29 '13 at 23:49
$begingroup$
I'm curious, why were you unsure of these in the first place?
$endgroup$
– Eric Tressler
Jul 29 '13 at 23:49
$begingroup$
From the amount of logic questions the OP has been asking, I think he is just preparing for an upcoming test.
$endgroup$
– Sujaan Kunalan
Jul 29 '13 at 23:50
$begingroup$
From the amount of logic questions the OP has been asking, I think he is just preparing for an upcoming test.
$endgroup$
– Sujaan Kunalan
Jul 29 '13 at 23:50
$begingroup$
@SujaanKunalan Correct.
$endgroup$
– MethodManX
Jul 29 '13 at 23:55
$begingroup$
@SujaanKunalan Correct.
$endgroup$
– MethodManX
Jul 29 '13 at 23:55
add a comment |
1 Answer
1
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$begingroup$
Recall,
Statement: if $p$ then $q.$
Converse: if $q$ then $p.$
Inverse: if not $p$ then not $q.$
Contrapositive: if not $q$ then not $p.$
So, yes, your answers are indeed correct.
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
$endgroup$
add a comment |
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$begingroup$
Recall,
Statement: if $p$ then $q.$
Converse: if $q$ then $p.$
Inverse: if not $p$ then not $q.$
Contrapositive: if not $q$ then not $p.$
So, yes, your answers are indeed correct.
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
$endgroup$
add a comment |
$begingroup$
Recall,
Statement: if $p$ then $q.$
Converse: if $q$ then $p.$
Inverse: if not $p$ then not $q.$
Contrapositive: if not $q$ then not $p.$
So, yes, your answers are indeed correct.
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
$endgroup$
add a comment |
$begingroup$
Recall,
Statement: if $p$ then $q.$
Converse: if $q$ then $p.$
Inverse: if not $p$ then not $q.$
Contrapositive: if not $q$ then not $p.$
So, yes, your answers are indeed correct.
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
$endgroup$
Recall,
Statement: if $p$ then $q.$
Converse: if $q$ then $p.$
Inverse: if not $p$ then not $q.$
Contrapositive: if not $q$ then not $p.$
So, yes, your answers are indeed correct.
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
answered Jul 29 '13 at 23:48
Sujaan KunalanSujaan Kunalan
7,186133972
7,186133972
add a comment |
add a comment |
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1
$begingroup$
I'm curious, why were you unsure of these in the first place?
$endgroup$
– Eric Tressler
Jul 29 '13 at 23:49
$begingroup$
From the amount of logic questions the OP has been asking, I think he is just preparing for an upcoming test.
$endgroup$
– Sujaan Kunalan
Jul 29 '13 at 23:50
$begingroup$
@SujaanKunalan Correct.
$endgroup$
– MethodManX
Jul 29 '13 at 23:55