Mixing
Datagridview paint issue
I have a datagridview in which I process the data from a datatable. Then change the color on fields that are an issue. I do this through the ProgressChanged event. This is the code:
private void bgwCompare_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
ReportRow rr = (ReportRow)e.UserState;
if (rr.nRow == 1 && rr.nColumn == 2)
rr.nColumn = 2; // If I leave this in it works, if I remove it the single cell is not colored
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
This gets... REALLY bizarre... I only appear to have a problem with a single cell out of over 1000 records.
IF I try to watch the cell get set, it works. (see the above code rr.nRow == 1 && rr.nColumn == 2)
If I comment that code out, the cell doesn't get painted. If I leave that code in, the cell gets painted. I know the value getting set to itself isn't doing anything, I just used that to set a break point. However, if I take the breakpoint off but leave the code it; it works. I'm baffled on what the heck is going on...
Anyone have any ideas?
c# winforms
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
add a comment |
I have a datagridview in which I process the data from a datatable. Then change the color on fields that are an issue. I do this through the ProgressChanged event. This is the code:
private void bgwCompare_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
ReportRow rr = (ReportRow)e.UserState;
if (rr.nRow == 1 && rr.nColumn == 2)
rr.nColumn = 2; // If I leave this in it works, if I remove it the single cell is not colored
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
This gets... REALLY bizarre... I only appear to have a problem with a single cell out of over 1000 records.
IF I try to watch the cell get set, it works. (see the above code rr.nRow == 1 && rr.nColumn == 2)
If I comment that code out, the cell doesn't get painted. If I leave that code in, the cell gets painted. I know the value getting set to itself isn't doing anything, I just used that to set a break point. However, if I take the breakpoint off but leave the code it; it works. I'm baffled on what the heck is going on...
Anyone have any ideas?
c# winforms
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
add a comment |
I have a datagridview in which I process the data from a datatable. Then change the color on fields that are an issue. I do this through the ProgressChanged event. This is the code:
private void bgwCompare_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
ReportRow rr = (ReportRow)e.UserState;
if (rr.nRow == 1 && rr.nColumn == 2)
rr.nColumn = 2; // If I leave this in it works, if I remove it the single cell is not colored
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
This gets... REALLY bizarre... I only appear to have a problem with a single cell out of over 1000 records.
IF I try to watch the cell get set, it works. (see the above code rr.nRow == 1 && rr.nColumn == 2)
If I comment that code out, the cell doesn't get painted. If I leave that code in, the cell gets painted. I know the value getting set to itself isn't doing anything, I just used that to set a break point. However, if I take the breakpoint off but leave the code it; it works. I'm baffled on what the heck is going on...
Anyone have any ideas?
c# winforms
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
I have a datagridview in which I process the data from a datatable. Then change the color on fields that are an issue. I do this through the ProgressChanged event. This is the code:
private void bgwCompare_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
ReportRow rr = (ReportRow)e.UserState;
if (rr.nRow == 1 && rr.nColumn == 2)
rr.nColumn = 2; // If I leave this in it works, if I remove it the single cell is not colored
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
This gets... REALLY bizarre... I only appear to have a problem with a single cell out of over 1000 records.
IF I try to watch the cell get set, it works. (see the above code rr.nRow == 1 && rr.nColumn == 2)
If I comment that code out, the cell doesn't get painted. If I leave that code in, the cell gets painted. I know the value getting set to itself isn't doing anything, I just used that to set a break point. However, if I take the breakpoint off but leave the code it; it works. I'm baffled on what the heck is going on...
Anyone have any ideas?
c# winforms
c# winforms
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
asked Nov 21 '18 at 4:17
DaBlueDaBlue
724625
724625
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
I think that if you comment your line rr.nColumn = 2 out the code will be interpreted as like
if (rr.nRow == 1 && rr.nColumn == 2)
{
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
and then the BackColor on [1,2] is not set as desired.
@DaBlue as you say in the comments no my code is not interpreted like this, please then try the following
if (false)
MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
In this case "2" will be shown and then try out the following code
if (false)
//MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
this time you won't see any pop up
IMHO you should always use curly braces even if it's an "one-liner"
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
1
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
add a comment |
Turns out it was working ok. I restarted my computer and re-ran the project with out the "debug code" and it worked perfectly. There must have been something in the OS that was causing issues.
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
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oldest
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oldest
votes
I think that if you comment your line rr.nColumn = 2 out the code will be interpreted as like
if (rr.nRow == 1 && rr.nColumn == 2)
{
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
and then the BackColor on [1,2] is not set as desired.
@DaBlue as you say in the comments no my code is not interpreted like this, please then try the following
if (false)
MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
In this case "2" will be shown and then try out the following code
if (false)
//MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
this time you won't see any pop up
IMHO you should always use curly braces even if it's an "one-liner"
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
1
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
add a comment |
I think that if you comment your line rr.nColumn = 2 out the code will be interpreted as like
if (rr.nRow == 1 && rr.nColumn == 2)
{
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
and then the BackColor on [1,2] is not set as desired.
@DaBlue as you say in the comments no my code is not interpreted like this, please then try the following
if (false)
MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
In this case "2" will be shown and then try out the following code
if (false)
//MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
this time you won't see any pop up
IMHO you should always use curly braces even if it's an "one-liner"
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
1
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
add a comment |
I think that if you comment your line rr.nColumn = 2 out the code will be interpreted as like
if (rr.nRow == 1 && rr.nColumn == 2)
{
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
and then the BackColor on [1,2] is not set as desired.
@DaBlue as you say in the comments no my code is not interpreted like this, please then try the following
if (false)
MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
In this case "2" will be shown and then try out the following code
if (false)
//MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
this time you won't see any pop up
IMHO you should always use curly braces even if it's an "one-liner"
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
I think that if you comment your line rr.nColumn = 2 out the code will be interpreted as like
if (rr.nRow == 1 && rr.nColumn == 2)
{
if (rr.nColumn == -1)
dgvResults.Rows[rr.nRow].DefaultCellStyle.BackColor = Color.Yellow;
else
dgvResults.Rows[rr.nRow].Cells[rr.nColumn].Style.BackColor = Color.Salmon;
}
and then the BackColor on [1,2] is not set as desired.
@DaBlue as you say in the comments no my code is not interpreted like this, please then try the following
if (false)
MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
In this case "2" will be shown and then try out the following code
if (false)
//MessageBox.Show("1"); // If I leave this in it works, if I remove it the single cell is not colored
if (true)
MessageBox.Show("2");
else
MessageBox.Show("3");
this time you won't see any pop up
IMHO you should always use curly braces even if it's an "one-liner"
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
edited Dec 15 '18 at 17:20
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
answered Nov 21 '18 at 9:17
ChrizzleWhizzleChrizzleWhizzle
623
623
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
1
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
add a comment |
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
1
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
That "one liner" is only for debugging and sets the variable to the same value as it is. As I mentioned (and ironically), this line makes it work. This line is ONLY for debugging purposes so I can set a break point where the data is having an issue in the DGV so I can see it go through the code.
– DaBlue
Nov 21 '18 at 11:20
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
And no, it wouldn't be interpreted as you have it above.
– DaBlue
Nov 21 '18 at 11:21
1
1
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
DaBlue hes right about how your code would be interpreted and also about how you should always use braces. Especially about always using braces LOL
– Scope Creep
Nov 22 '18 at 5:27
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
I've been coding c/C++/C# for 40 years. Compile and run this and you will see it does work. Best practice has always been 1 line is no brace, multiple uses braces.
– DaBlue
Dec 12 '18 at 16:50
add a comment |
Turns out it was working ok. I restarted my computer and re-ran the project with out the "debug code" and it worked perfectly. There must have been something in the OS that was causing issues.
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
add a comment |
Turns out it was working ok. I restarted my computer and re-ran the project with out the "debug code" and it worked perfectly. There must have been something in the OS that was causing issues.
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
add a comment |
Turns out it was working ok. I restarted my computer and re-ran the project with out the "debug code" and it worked perfectly. There must have been something in the OS that was causing issues.
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
Turns out it was working ok. I restarted my computer and re-ran the project with out the "debug code" and it worked perfectly. There must have been something in the OS that was causing issues.
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
answered Nov 21 '18 at 12:23
DaBlueDaBlue
724625
724625
add a comment |
add a comment |
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