'Trying to get property of non-object' after using array_unshift
I have an object :
$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);
I am getting the NO
and ID_JPS
properties within a for
loop.
for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}
I'd like to insert a blank data into $data_ori
so I use array_unshift()
:
$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);
But, after doing that, my for
loop stops working. The error message is:
Message: Trying to get property of non-object.
How do I get the data from the inserted item?
php arrays
add a comment |
I have an object :
$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);
I am getting the NO
and ID_JPS
properties within a for
loop.
for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}
I'd like to insert a blank data into $data_ori
so I use array_unshift()
:
$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);
But, after doing that, my for
loop stops working. The error message is:
Message: Trying to get property of non-object.
How do I get the data from the inserted item?
php arrays
is$count
intentional?
– Scuzzy
Nov 21 '18 at 4:13
ups... I'll edit it
– ashura91
Nov 21 '18 at 4:14
Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.
– miken32
Nov 29 '18 at 21:41
add a comment |
I have an object :
$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);
I am getting the NO
and ID_JPS
properties within a for
loop.
for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}
I'd like to insert a blank data into $data_ori
so I use array_unshift()
:
$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);
But, after doing that, my for
loop stops working. The error message is:
Message: Trying to get property of non-object.
How do I get the data from the inserted item?
php arrays
I have an object :
$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);
I am getting the NO
and ID_JPS
properties within a for
loop.
for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}
I'd like to insert a blank data into $data_ori
so I use array_unshift()
:
$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);
But, after doing that, my for
loop stops working. The error message is:
Message: Trying to get property of non-object.
How do I get the data from the inserted item?
php arrays
php arrays
edited Nov 21 '18 at 4:20
miken32
23.7k84972
23.7k84972
asked Nov 21 '18 at 4:10
ashura91ashura91
256112
256112
is$count
intentional?
– Scuzzy
Nov 21 '18 at 4:13
ups... I'll edit it
– ashura91
Nov 21 '18 at 4:14
Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.
– miken32
Nov 29 '18 at 21:41
add a comment |
is$count
intentional?
– Scuzzy
Nov 21 '18 at 4:13
ups... I'll edit it
– ashura91
Nov 21 '18 at 4:14
Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.
– miken32
Nov 29 '18 at 21:41
is
$count
intentional?– Scuzzy
Nov 21 '18 at 4:13
is
$count
intentional?– Scuzzy
Nov 21 '18 at 4:13
ups... I'll edit it
– ashura91
Nov 21 '18 at 4:14
ups... I'll edit it
– ashura91
Nov 21 '18 at 4:14
Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.
– miken32
Nov 29 '18 at 21:41
Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.
– miken32
Nov 29 '18 at 21:41
add a comment |
1 Answer
1
active
oldest
votes
That's because you're inserting an array, not an object. Easiest is just to cast it:
$data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
That's because you're inserting an array, not an object. Easiest is just to cast it:
$data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');
add a comment |
That's because you're inserting an array, not an object. Easiest is just to cast it:
$data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');
add a comment |
That's because you're inserting an array, not an object. Easiest is just to cast it:
$data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');
That's because you're inserting an array, not an object. Easiest is just to cast it:
$data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');
answered Nov 21 '18 at 4:13
miken32miken32
23.7k84972
23.7k84972
add a comment |
add a comment |
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is
$count
intentional?– Scuzzy
Nov 21 '18 at 4:13
ups... I'll edit it
– ashura91
Nov 21 '18 at 4:14
Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.
– miken32
Nov 29 '18 at 21:41