'Trying to get property of non-object' after using array_unshift












0















I have an object :



$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);


I am getting the NO and ID_JPS properties within a for loop.



for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}


I'd like to insert a blank data into $data_ori so I use array_unshift():



$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);


But, after doing that, my for loop stops working. The error message is:




Message: Trying to get property of non-object.




How do I get the data from the inserted item?










share|improve this question

























  • is $count intentional?

    – Scuzzy
    Nov 21 '18 at 4:13











  • ups... I'll edit it

    – ashura91
    Nov 21 '18 at 4:14











  • Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.

    – miken32
    Nov 29 '18 at 21:41
















0















I have an object :



$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);


I am getting the NO and ID_JPS properties within a for loop.



for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}


I'd like to insert a blank data into $data_ori so I use array_unshift():



$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);


But, after doing that, my for loop stops working. The error message is:




Message: Trying to get property of non-object.




How do I get the data from the inserted item?










share|improve this question

























  • is $count intentional?

    – Scuzzy
    Nov 21 '18 at 4:13











  • ups... I'll edit it

    – ashura91
    Nov 21 '18 at 4:14











  • Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.

    – miken32
    Nov 29 '18 at 21:41














0












0








0








I have an object :



$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);


I am getting the NO and ID_JPS properties within a for loop.



for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}


I'd like to insert a blank data into $data_ori so I use array_unshift():



$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);


But, after doing that, my for loop stops working. The error message is:




Message: Trying to get property of non-object.




How do I get the data from the inserted item?










share|improve this question
















I have an object :



$data = '[{"NO":"1","ID_JPS":"AAA"},{"NO":"2","ID_JPS":"BBB"}]';
$data_ori = json_decode($data);


I am getting the NO and ID_JPS properties within a for loop.



for($i=0; $i < count($data_ori); $i++){
echo $id_item = "NO = " . $data_ori[$i]->NO . " & ID_JPS = " . $data_ori[$i]->ID_JPS;
}


I'd like to insert a blank data into $data_ori so I use array_unshift():



$data_blank = array( 'NO' => 'NULL','ID_JPS' => 'NULL');
array_unshift($data_ori,$data_blank);


But, after doing that, my for loop stops working. The error message is:




Message: Trying to get property of non-object.




How do I get the data from the inserted item?







php arrays






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 4:20









miken32

23.7k84972




23.7k84972










asked Nov 21 '18 at 4:10









ashura91ashura91

256112




256112













  • is $count intentional?

    – Scuzzy
    Nov 21 '18 at 4:13











  • ups... I'll edit it

    – ashura91
    Nov 21 '18 at 4:14











  • Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.

    – miken32
    Nov 29 '18 at 21:41



















  • is $count intentional?

    – Scuzzy
    Nov 21 '18 at 4:13











  • ups... I'll edit it

    – ashura91
    Nov 21 '18 at 4:14











  • Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.

    – miken32
    Nov 29 '18 at 21:41

















is $count intentional?

– Scuzzy
Nov 21 '18 at 4:13





is $count intentional?

– Scuzzy
Nov 21 '18 at 4:13













ups... I'll edit it

– ashura91
Nov 21 '18 at 4:14





ups... I'll edit it

– ashura91
Nov 21 '18 at 4:14













Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.

– miken32
Nov 29 '18 at 21:41





Were any of the provided answers helpful? You should upvote all answers that were helpful if you have the reputation to do so, and mark accepted the one answer that best answered your question. This will mark the question as "closed," and give you some reputation on the site. See stackoverflow.com/help/someone-answers for more information.

– miken32
Nov 29 '18 at 21:41












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That's because you're inserting an array, not an object. Easiest is just to cast it:



$data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');





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    1 Answer
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    1 Answer
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    active

    oldest

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    active

    oldest

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    That's because you're inserting an array, not an object. Easiest is just to cast it:



    $data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');





    share|improve this answer




























      1














      That's because you're inserting an array, not an object. Easiest is just to cast it:



      $data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');





      share|improve this answer


























        1












        1








        1







        That's because you're inserting an array, not an object. Easiest is just to cast it:



        $data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');





        share|improve this answer













        That's because you're inserting an array, not an object. Easiest is just to cast it:



        $data_blank = (object)array( 'NO' => 'NULL','ID_JPS' => 'NULL');






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 4:13









        miken32miken32

        23.7k84972




        23.7k84972






























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