relation between two positive definite matrices via similarity transformation.












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$begingroup$


If $A$ and $B$ are two complex hermitian semi-definite matrices of order $Ntimes N$. Show that $exists$ an invertible matrix $Tinmathbb{C}^{Ntimes N}$ s.t



$T^H A T=Lambda_N$



$T^H B T= I_N$



where $Lambda_N$ is a diagonal matrix with positive entries and $I_N$ is the identity matrix.










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    0












    $begingroup$


    If $A$ and $B$ are two complex hermitian semi-definite matrices of order $Ntimes N$. Show that $exists$ an invertible matrix $Tinmathbb{C}^{Ntimes N}$ s.t



    $T^H A T=Lambda_N$



    $T^H B T= I_N$



    where $Lambda_N$ is a diagonal matrix with positive entries and $I_N$ is the identity matrix.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      If $A$ and $B$ are two complex hermitian semi-definite matrices of order $Ntimes N$. Show that $exists$ an invertible matrix $Tinmathbb{C}^{Ntimes N}$ s.t



      $T^H A T=Lambda_N$



      $T^H B T= I_N$



      where $Lambda_N$ is a diagonal matrix with positive entries and $I_N$ is the identity matrix.










      share|cite|improve this question









      $endgroup$




      If $A$ and $B$ are two complex hermitian semi-definite matrices of order $Ntimes N$. Show that $exists$ an invertible matrix $Tinmathbb{C}^{Ntimes N}$ s.t



      $T^H A T=Lambda_N$



      $T^H B T= I_N$



      where $Lambda_N$ is a diagonal matrix with positive entries and $I_N$ is the identity matrix.







      linear-algebra






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      asked Jan 10 at 11:12









      MD Afaque AzamMD Afaque Azam

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      62






















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          $begingroup$

          Hint: Let $B=Q^{H}DQ$, be the eigen value decomposition of $B$ so $D$ is the diagonal then choose $T= Q^{H}D^{-1/2}$, and show that both relations hold.






          share|cite|improve this answer









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            $begingroup$

            Hint: Let $B=Q^{H}DQ$, be the eigen value decomposition of $B$ so $D$ is the diagonal then choose $T= Q^{H}D^{-1/2}$, and show that both relations hold.






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              Hint: Let $B=Q^{H}DQ$, be the eigen value decomposition of $B$ so $D$ is the diagonal then choose $T= Q^{H}D^{-1/2}$, and show that both relations hold.






              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                Hint: Let $B=Q^{H}DQ$, be the eigen value decomposition of $B$ so $D$ is the diagonal then choose $T= Q^{H}D^{-1/2}$, and show that both relations hold.






                share|cite|improve this answer









                $endgroup$



                Hint: Let $B=Q^{H}DQ$, be the eigen value decomposition of $B$ so $D$ is the diagonal then choose $T= Q^{H}D^{-1/2}$, and show that both relations hold.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 10 at 13:38









                zimbra314zimbra314

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