Date formatting and including days
I have a csv file which has column of dates (D/M/Y format) and I want to convert it to days column. I used following approach:
In [1]: import numpy as np
import pandas as pd
from pandas import Series, DataFrame
#f = pd.read_csv(".some_file.csv")
In [2]: f=pd.DataFrame([['1/1/2013', 400, 1000]['2/1/2013', 500, 3000]], columns=['date','flights','distance'])
f['date']=pd.to_datetime(f['date'], format='%d/%m/%y',errors='ignore')
f['day']=f['date'].dt.weekday_name
I was expecting the day column. It appeared for the first time and I used that table too. However after clearing kernel I am getting NaT in date and NaN in day. After that days never appeared.
Am I doing anything wrong? If yes, how did day appeared for the first time?
Thanks for reading. Any help will be appreciated.
PS CSV has more than 330K rows. I have to assign day for each date.
python pandas datetime
add a comment |
I have a csv file which has column of dates (D/M/Y format) and I want to convert it to days column. I used following approach:
In [1]: import numpy as np
import pandas as pd
from pandas import Series, DataFrame
#f = pd.read_csv(".some_file.csv")
In [2]: f=pd.DataFrame([['1/1/2013', 400, 1000]['2/1/2013', 500, 3000]], columns=['date','flights','distance'])
f['date']=pd.to_datetime(f['date'], format='%d/%m/%y',errors='ignore')
f['day']=f['date'].dt.weekday_name
I was expecting the day column. It appeared for the first time and I used that table too. However after clearing kernel I am getting NaT in date and NaN in day. After that days never appeared.
Am I doing anything wrong? If yes, how did day appeared for the first time?
Thanks for reading. Any help will be appreciated.
PS CSV has more than 330K rows. I have to assign day for each date.
python pandas datetime
add a comment |
I have a csv file which has column of dates (D/M/Y format) and I want to convert it to days column. I used following approach:
In [1]: import numpy as np
import pandas as pd
from pandas import Series, DataFrame
#f = pd.read_csv(".some_file.csv")
In [2]: f=pd.DataFrame([['1/1/2013', 400, 1000]['2/1/2013', 500, 3000]], columns=['date','flights','distance'])
f['date']=pd.to_datetime(f['date'], format='%d/%m/%y',errors='ignore')
f['day']=f['date'].dt.weekday_name
I was expecting the day column. It appeared for the first time and I used that table too. However after clearing kernel I am getting NaT in date and NaN in day. After that days never appeared.
Am I doing anything wrong? If yes, how did day appeared for the first time?
Thanks for reading. Any help will be appreciated.
PS CSV has more than 330K rows. I have to assign day for each date.
python pandas datetime
I have a csv file which has column of dates (D/M/Y format) and I want to convert it to days column. I used following approach:
In [1]: import numpy as np
import pandas as pd
from pandas import Series, DataFrame
#f = pd.read_csv(".some_file.csv")
In [2]: f=pd.DataFrame([['1/1/2013', 400, 1000]['2/1/2013', 500, 3000]], columns=['date','flights','distance'])
f['date']=pd.to_datetime(f['date'], format='%d/%m/%y',errors='ignore')
f['day']=f['date'].dt.weekday_name
I was expecting the day column. It appeared for the first time and I used that table too. However after clearing kernel I am getting NaT in date and NaN in day. After that days never appeared.
Am I doing anything wrong? If yes, how did day appeared for the first time?
Thanks for reading. Any help will be appreciated.
PS CSV has more than 330K rows. I have to assign day for each date.
python pandas datetime
python pandas datetime
edited Nov 22 '18 at 10:27
Nikhil Jagtap
asked Nov 22 '18 at 9:56
Nikhil JagtapNikhil Jagtap
16
16
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1 Answer
1
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The problem is you have incorrectly specified the datetime
format and hidden the error by setting errors='ignore'
. You need '%Y'
for the full year (see Python's strftime
directives):
f['date'] = pd.to_datetime(f['date'], format='%d/%m/%Y', errors='coerce')
errors='coerce'
will give NaN
for non-convertible dates. Or, to raise errors, just omit the errors
parameter altogether.
For such problems, it's good practice to look at f.dtypes
to see whether your type conversion has succeeded. For example, you should see:
print(f['date'].dtype)
# datetime64[ns]
You should not see:
print(f['date'].dtype)
# object
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem is you have incorrectly specified the datetime
format and hidden the error by setting errors='ignore'
. You need '%Y'
for the full year (see Python's strftime
directives):
f['date'] = pd.to_datetime(f['date'], format='%d/%m/%Y', errors='coerce')
errors='coerce'
will give NaN
for non-convertible dates. Or, to raise errors, just omit the errors
parameter altogether.
For such problems, it's good practice to look at f.dtypes
to see whether your type conversion has succeeded. For example, you should see:
print(f['date'].dtype)
# datetime64[ns]
You should not see:
print(f['date'].dtype)
# object
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
add a comment |
The problem is you have incorrectly specified the datetime
format and hidden the error by setting errors='ignore'
. You need '%Y'
for the full year (see Python's strftime
directives):
f['date'] = pd.to_datetime(f['date'], format='%d/%m/%Y', errors='coerce')
errors='coerce'
will give NaN
for non-convertible dates. Or, to raise errors, just omit the errors
parameter altogether.
For such problems, it's good practice to look at f.dtypes
to see whether your type conversion has succeeded. For example, you should see:
print(f['date'].dtype)
# datetime64[ns]
You should not see:
print(f['date'].dtype)
# object
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
add a comment |
The problem is you have incorrectly specified the datetime
format and hidden the error by setting errors='ignore'
. You need '%Y'
for the full year (see Python's strftime
directives):
f['date'] = pd.to_datetime(f['date'], format='%d/%m/%Y', errors='coerce')
errors='coerce'
will give NaN
for non-convertible dates. Or, to raise errors, just omit the errors
parameter altogether.
For such problems, it's good practice to look at f.dtypes
to see whether your type conversion has succeeded. For example, you should see:
print(f['date'].dtype)
# datetime64[ns]
You should not see:
print(f['date'].dtype)
# object
The problem is you have incorrectly specified the datetime
format and hidden the error by setting errors='ignore'
. You need '%Y'
for the full year (see Python's strftime
directives):
f['date'] = pd.to_datetime(f['date'], format='%d/%m/%Y', errors='coerce')
errors='coerce'
will give NaN
for non-convertible dates. Or, to raise errors, just omit the errors
parameter altogether.
For such problems, it's good practice to look at f.dtypes
to see whether your type conversion has succeeded. For example, you should see:
print(f['date'].dtype)
# datetime64[ns]
You should not see:
print(f['date'].dtype)
# object
answered Nov 22 '18 at 10:27
jppjpp
101k2163112
101k2163112
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
add a comment |
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
Thank you. It worked. :)
– Nikhil Jagtap
Nov 22 '18 at 10:32
add a comment |
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