Loop over an optional argument

I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.

So, for example, foo[5] should step the counter 5 times, one by one.

(!) Note that it is not the same as stepcounter{}{5}.

MWE

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter is textbf{3,4}



end{document}

enter image description here

asked Jan 18 at 23:45

Sigur

25.6k456139

add a comment |

I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.

So, for example, foo[5] should step the counter 5 times, one by one.

(!) Note that it is not the same as stepcounter{}{5}.

MWE

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter is textbf{3,4}



end{document}

enter image description here

asked Jan 18 at 23:45

Sigur

25.6k456139

add a comment |

I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.

So, for example, foo[5] should step the counter 5 times, one by one.

(!) Note that it is not the same as stepcounter{}{5}.

MWE

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter is textbf{3,4}



end{document}

enter image description here

asked Jan 18 at 23:45

Sigur

25.6k456139

I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.

So, for example, foo[5] should step the counter 5 times, one by one.

(!) Note that it is not the same as stepcounter{}{5}.

MWE

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter is textbf{3,4}



end{document}

enter image description here

macros counters loops

asked Jan 18 at 23:45

Sigur

25.6k456139

asked Jan 18 at 23:45

Sigur

25.6k456139

asked Jan 18 at 23:45

Sigur

25.6k456139

asked Jan 18 at 23:45

Sigur

25.6k456139

asked Jan 18 at 23:45

Sigur

25.6k456139

add a comment |

5 Answers
5

active

oldest

votes

With expl3 it's just a few lines.

documentclass{report}

usepackage{xparse}



newcounter{mycount}

setcounter{mycount}{0}



ExplSyntaxOn

NewDocumentCommand{foo}{O{1}}

 {

  int_compare:nT { #1 > 0 }

   {

    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~

    stepcounter{mycount}

    textbf{themycount}

    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}

   }

 }

ExplSyntaxOff



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



now using with option to iterate: counters are textbf{3,4}



foo[5]



end{document}

The trick is to do the first iteration and then proceed again adding first a comma.

If the number passed is zero or less nothing happens.

enter image description here

edited Jan 19 at 0:03

answered Jan 18 at 23:54

egreg

723k8819163219

Exactly what I need.

– Sigur
Jan 18 at 23:56

Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

– Sigur
Jan 18 at 23:57

2

@Sigur Your wish is my command. Updated.

– egreg
Jan 19 at 0:03

Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

– Sigur
Jan 19 at 0:08

add a comment |

Here is short code with multido, xparse and etoolbox:

documentclass{report}

usepackage{multido}

usepackage{xparse, etoolbox}

newcounter{mycount}

setcounter{mycount}{0}

NewDocumentCommand{foo}{O{1}}{counter is multido{i=1+1}{#1}{stepcounter{mycount}textbf{themycount}ifnumless{multidocount}{#1}{,,}{.}}}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[5]



end{document}

enter image description here

answered Jan 19 at 0:32

Bernard

171k775203

add a comment |

Here is an approach using multido for looping and a delayed delimiter definition:

enter image description here

documentclass{article}



usepackage{multido}



newcounter{mycount}



newcommand{foo}[1][1]{%

  counter%

  ifnum#1>1relax s areelse space isfi

  space

  % https://tex.stackexchange.com/a/89187/5764

  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle

  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%

}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counters are textbf{3, 4}



end{document}

answered Jan 19 at 0:04

Werner

446k699831689

This solution is more understandable to me... but I had never done it by myself. Very nice.

– Sigur
Jan 19 at 0:11

add a comment |

With pgffor it is even less lines.

documentclass{report}

usepackage{pgffor}

newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}[1][1]{counter is foreach X [count=Y] in

{1,...,#1}{stepcounter{mycount}%

textbf{themycount}ifnumY=#1%

else%

,fi}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



end{document}

enter image description here

edited Jan 19 at 0:31

answered Jan 19 at 0:26

marmot

104k4124236

add a comment |

A bit more code but without additional packages:

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}



newcommandExchange[2]{#2#1}%

newcommand{foo}[1][1]{fooloop{#1}{}{counter value is}}

makeatletter

newcommand{fooloop}[3]{%

  ifnum#1>0 stepcounter{mycount}fi

  ifnum#1>1 expandafter@firstoftwoelseexpandafter@secondoftwofi

  {% 

    begingroup

    protected@edef@tempa{themycount}%

    c@mycount=#1relax

    advancec@mycount by -1relax

    expandafterendgroup

    expandafterfooloopexpandafter

    {numberexpandafterc@mycountexpandafter}expandafter

    {romannumeral0expandafterExchangeexpandafter{@tempa}{ #2}, }%

    {counter values are}%

  }{%

    #3 textbf{#2themycount}%

  }%

}%

makeatother



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[4]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter values are textbf{3, 4, 5, 6}



medskip



now using with option to iterate 0 times---counter is unchanged and displayed: foo[0]



medskip



now using with option to iterate -1 times---counter is unchanged and displayed: foo[-1]



end{document}

enter image description here

edited Jan 27 at 5:21

answered Jan 27 at 5:10

Ulrich Diez

4,985618

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

With expl3 it's just a few lines.

documentclass{report}

usepackage{xparse}



newcounter{mycount}

setcounter{mycount}{0}



ExplSyntaxOn

NewDocumentCommand{foo}{O{1}}

 {

  int_compare:nT { #1 > 0 }

   {

    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~

    stepcounter{mycount}

    textbf{themycount}

    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}

   }

 }

ExplSyntaxOff



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



now using with option to iterate: counters are textbf{3,4}



foo[5]



end{document}

The trick is to do the first iteration and then proceed again adding first a comma.

If the number passed is zero or less nothing happens.

enter image description here

edited Jan 19 at 0:03

answered Jan 18 at 23:54

egreg

723k8819163219

Exactly what I need.

– Sigur
Jan 18 at 23:56

Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

– Sigur
Jan 18 at 23:57

2

@Sigur Your wish is my command. Updated.

– egreg
Jan 19 at 0:03

Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

– Sigur
Jan 19 at 0:08

add a comment |

With expl3 it's just a few lines.

documentclass{report}

usepackage{xparse}



newcounter{mycount}

setcounter{mycount}{0}



ExplSyntaxOn

NewDocumentCommand{foo}{O{1}}

 {

  int_compare:nT { #1 > 0 }

   {

    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~

    stepcounter{mycount}

    textbf{themycount}

    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}

   }

 }

ExplSyntaxOff



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



now using with option to iterate: counters are textbf{3,4}



foo[5]



end{document}

The trick is to do the first iteration and then proceed again adding first a comma.

If the number passed is zero or less nothing happens.

enter image description here

edited Jan 19 at 0:03

answered Jan 18 at 23:54

egreg

723k8819163219

Exactly what I need.

– Sigur
Jan 18 at 23:56

Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

– Sigur
Jan 18 at 23:57

2

@Sigur Your wish is my command. Updated.

– egreg
Jan 19 at 0:03

Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

– Sigur
Jan 19 at 0:08

add a comment |

With expl3 it's just a few lines.

documentclass{report}

usepackage{xparse}



newcounter{mycount}

setcounter{mycount}{0}



ExplSyntaxOn

NewDocumentCommand{foo}{O{1}}

 {

  int_compare:nT { #1 > 0 }

   {

    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~

    stepcounter{mycount}

    textbf{themycount}

    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}

   }

 }

ExplSyntaxOff



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



now using with option to iterate: counters are textbf{3,4}



foo[5]



end{document}

The trick is to do the first iteration and then proceed again adding first a comma.

If the number passed is zero or less nothing happens.

enter image description here

edited Jan 19 at 0:03

answered Jan 18 at 23:54

egreg

723k8819163219

With expl3 it's just a few lines.

documentclass{report}

usepackage{xparse}



newcounter{mycount}

setcounter{mycount}{0}



ExplSyntaxOn

NewDocumentCommand{foo}{O{1}}

 {

  int_compare:nT { #1 > 0 }

   {

    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~

    stepcounter{mycount}

    textbf{themycount}

    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}

   }

 }

ExplSyntaxOff



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



now using with option to iterate: counters are textbf{3,4}



foo[5]



end{document}

The trick is to do the first iteration and then proceed again adding first a comma.

If the number passed is zero or less nothing happens.

enter image description here

edited Jan 19 at 0:03

answered Jan 18 at 23:54

egreg

723k8819163219

edited Jan 19 at 0:03

answered Jan 18 at 23:54

egreg

723k8819163219

answered Jan 18 at 23:54

egreg

723k8819163219

answered Jan 18 at 23:54

egreg

723k8819163219

Exactly what I need.

– Sigur
Jan 18 at 23:56

Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

– Sigur
Jan 18 at 23:57

2

@Sigur Your wish is my command. Updated.

– egreg
Jan 19 at 0:03

Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

– Sigur
Jan 19 at 0:08

add a comment |

Exactly what I need.

– Sigur
Jan 18 at 23:56

Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

– Sigur
Jan 18 at 23:57

2

@Sigur Your wish is my command. Updated.

– egreg
Jan 19 at 0:03

Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

– Sigur
Jan 19 at 0:08

Exactly what I need.

– Sigur
Jan 18 at 23:56

Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

– Sigur
Jan 18 at 23:57

@Sigur Your wish is my command. Updated.

– egreg
Jan 19 at 0:03

Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

– Sigur
Jan 19 at 0:08

add a comment |

Here is short code with multido, xparse and etoolbox:

documentclass{report}

usepackage{multido}

usepackage{xparse, etoolbox}

newcounter{mycount}

setcounter{mycount}{0}

NewDocumentCommand{foo}{O{1}}{counter is multido{i=1+1}{#1}{stepcounter{mycount}textbf{themycount}ifnumless{multidocount}{#1}{,,}{.}}}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[5]



end{document}

enter image description here

answered Jan 19 at 0:32

Bernard

171k775203

add a comment |

Here is short code with multido, xparse and etoolbox:

documentclass{report}

usepackage{multido}

usepackage{xparse, etoolbox}

newcounter{mycount}

setcounter{mycount}{0}

NewDocumentCommand{foo}{O{1}}{counter is multido{i=1+1}{#1}{stepcounter{mycount}textbf{themycount}ifnumless{multidocount}{#1}{,,}{.}}}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[5]



end{document}

enter image description here

answered Jan 19 at 0:32

Bernard

171k775203

add a comment |

Here is short code with multido, xparse and etoolbox:

documentclass{report}

usepackage{multido}

usepackage{xparse, etoolbox}

newcounter{mycount}

setcounter{mycount}{0}

NewDocumentCommand{foo}{O{1}}{counter is multido{i=1+1}{#1}{stepcounter{mycount}textbf{themycount}ifnumless{multidocount}{#1}{,,}{.}}}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[5]



end{document}

enter image description here

answered Jan 19 at 0:32

Bernard

171k775203

Here is short code with multido, xparse and etoolbox:

documentclass{report}

usepackage{multido}

usepackage{xparse, etoolbox}

newcounter{mycount}

setcounter{mycount}{0}

NewDocumentCommand{foo}{O{1}}{counter is multido{i=1+1}{#1}{stepcounter{mycount}textbf{themycount}ifnumless{multidocount}{#1}{,,}{.}}}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[5]



end{document}

enter image description here

answered Jan 19 at 0:32

Bernard

171k775203

answered Jan 19 at 0:32

Bernard

171k775203

answered Jan 19 at 0:32

Bernard

171k775203

answered Jan 19 at 0:32

Bernard

171k775203

add a comment |

Here is an approach using multido for looping and a delayed delimiter definition:

enter image description here

documentclass{article}



usepackage{multido}



newcounter{mycount}



newcommand{foo}[1][1]{%

  counter%

  ifnum#1>1relax s areelse space isfi

  space

  % https://tex.stackexchange.com/a/89187/5764

  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle

  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%

}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counters are textbf{3, 4}



end{document}

answered Jan 19 at 0:04

Werner

446k699831689

This solution is more understandable to me... but I had never done it by myself. Very nice.

– Sigur
Jan 19 at 0:11

add a comment |

Here is an approach using multido for looping and a delayed delimiter definition:

enter image description here

documentclass{article}



usepackage{multido}



newcounter{mycount}



newcommand{foo}[1][1]{%

  counter%

  ifnum#1>1relax s areelse space isfi

  space

  % https://tex.stackexchange.com/a/89187/5764

  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle

  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%

}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counters are textbf{3, 4}



end{document}

answered Jan 19 at 0:04

Werner

446k699831689

This solution is more understandable to me... but I had never done it by myself. Very nice.

– Sigur
Jan 19 at 0:11

add a comment |

Here is an approach using multido for looping and a delayed delimiter definition:

enter image description here

documentclass{article}



usepackage{multido}



newcounter{mycount}



newcommand{foo}[1][1]{%

  counter%

  ifnum#1>1relax s areelse space isfi

  space

  % https://tex.stackexchange.com/a/89187/5764

  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle

  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%

}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counters are textbf{3, 4}



end{document}

answered Jan 19 at 0:04

Werner

446k699831689

Here is an approach using multido for looping and a delayed delimiter definition:

enter image description here

documentclass{article}



usepackage{multido}



newcounter{mycount}



newcommand{foo}[1][1]{%

  counter%

  ifnum#1>1relax s areelse space isfi

  space

  % https://tex.stackexchange.com/a/89187/5764

  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle

  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%

}



begin{document}



first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counters are textbf{3, 4}



end{document}

answered Jan 19 at 0:04

Werner

446k699831689

answered Jan 19 at 0:04

Werner

446k699831689

answered Jan 19 at 0:04

Werner

446k699831689

answered Jan 19 at 0:04

Werner

446k699831689

This solution is more understandable to me... but I had never done it by myself. Very nice.

– Sigur
Jan 19 at 0:11

add a comment |

This solution is more understandable to me... but I had never done it by myself. Very nice.

– Sigur
Jan 19 at 0:11

This solution is more understandable to me... but I had never done it by myself. Very nice.

– Sigur
Jan 19 at 0:11

add a comment |

With pgffor it is even less lines.

documentclass{report}

usepackage{pgffor}

newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}[1][1]{counter is foreach X [count=Y] in

{1,...,#1}{stepcounter{mycount}%

textbf{themycount}ifnumY=#1%

else%

,fi}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



end{document}

enter image description here

edited Jan 19 at 0:31

answered Jan 19 at 0:26

marmot

104k4124236

add a comment |

With pgffor it is even less lines.

documentclass{report}

usepackage{pgffor}

newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}[1][1]{counter is foreach X [count=Y] in

{1,...,#1}{stepcounter{mycount}%

textbf{themycount}ifnumY=#1%

else%

,fi}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



end{document}

enter image description here

edited Jan 19 at 0:31

answered Jan 19 at 0:26

marmot

104k4124236

add a comment |

With pgffor it is even less lines.

documentclass{report}

usepackage{pgffor}

newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}[1][1]{counter is foreach X [count=Y] in

{1,...,#1}{stepcounter{mycount}%

textbf{themycount}ifnumY=#1%

else%

,fi}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



end{document}

enter image description here

edited Jan 19 at 0:31

answered Jan 19 at 0:26

marmot

104k4124236

With pgffor it is even less lines.

documentclass{report}

usepackage{pgffor}

newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}[1][1]{counter is foreach X [count=Y] in

{1,...,#1}{stepcounter{mycount}%

textbf{themycount}ifnumY=#1%

else%

,fi}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



end{document}

enter image description here

edited Jan 19 at 0:31

answered Jan 19 at 0:26

marmot

104k4124236

edited Jan 19 at 0:31

answered Jan 19 at 0:26

marmot

104k4124236

answered Jan 19 at 0:26

marmot

104k4124236

answered Jan 19 at 0:26

marmot

104k4124236

add a comment |

A bit more code but without additional packages:

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}



newcommandExchange[2]{#2#1}%

newcommand{foo}[1][1]{fooloop{#1}{}{counter value is}}

makeatletter

newcommand{fooloop}[3]{%

  ifnum#1>0 stepcounter{mycount}fi

  ifnum#1>1 expandafter@firstoftwoelseexpandafter@secondoftwofi

  {% 

    begingroup

    protected@edef@tempa{themycount}%

    c@mycount=#1relax

    advancec@mycount by -1relax

    expandafterendgroup

    expandafterfooloopexpandafter

    {numberexpandafterc@mycountexpandafter}expandafter

    {romannumeral0expandafterExchangeexpandafter{@tempa}{ #2}, }%

    {counter values are}%

  }{%

    #3 textbf{#2themycount}%

  }%

}%

makeatother



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[4]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter values are textbf{3, 4, 5, 6}



medskip



now using with option to iterate 0 times---counter is unchanged and displayed: foo[0]



medskip



now using with option to iterate -1 times---counter is unchanged and displayed: foo[-1]



end{document}

enter image description here

edited Jan 27 at 5:21

answered Jan 27 at 5:10

Ulrich Diez

4,985618

add a comment |

A bit more code but without additional packages:

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}



newcommandExchange[2]{#2#1}%

newcommand{foo}[1][1]{fooloop{#1}{}{counter value is}}

makeatletter

newcommand{fooloop}[3]{%

  ifnum#1>0 stepcounter{mycount}fi

  ifnum#1>1 expandafter@firstoftwoelseexpandafter@secondoftwofi

  {% 

    begingroup

    protected@edef@tempa{themycount}%

    c@mycount=#1relax

    advancec@mycount by -1relax

    expandafterendgroup

    expandafterfooloopexpandafter

    {numberexpandafterc@mycountexpandafter}expandafter

    {romannumeral0expandafterExchangeexpandafter{@tempa}{ #2}, }%

    {counter values are}%

  }{%

    #3 textbf{#2themycount}%

  }%

}%

makeatother



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[4]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter values are textbf{3, 4, 5, 6}



medskip



now using with option to iterate 0 times---counter is unchanged and displayed: foo[0]



medskip



now using with option to iterate -1 times---counter is unchanged and displayed: foo[-1]



end{document}

enter image description here

edited Jan 27 at 5:21

answered Jan 27 at 5:10

Ulrich Diez

4,985618

add a comment |

A bit more code but without additional packages:

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}



newcommandExchange[2]{#2#1}%

newcommand{foo}[1][1]{fooloop{#1}{}{counter value is}}

makeatletter

newcommand{fooloop}[3]{%

  ifnum#1>0 stepcounter{mycount}fi

  ifnum#1>1 expandafter@firstoftwoelseexpandafter@secondoftwofi

  {% 

    begingroup

    protected@edef@tempa{themycount}%

    c@mycount=#1relax

    advancec@mycount by -1relax

    expandafterendgroup

    expandafterfooloopexpandafter

    {numberexpandafterc@mycountexpandafter}expandafter

    {romannumeral0expandafterExchangeexpandafter{@tempa}{ #2}, }%

    {counter values are}%

  }{%

    #3 textbf{#2themycount}%

  }%

}%

makeatother



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[4]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter values are textbf{3, 4, 5, 6}



medskip



now using with option to iterate 0 times---counter is unchanged and displayed: foo[0]



medskip



now using with option to iterate -1 times---counter is unchanged and displayed: foo[-1]



end{document}

enter image description here

edited Jan 27 at 5:21

answered Jan 27 at 5:10

Ulrich Diez

4,985618

A bit more code but without additional packages:

documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}



newcommandExchange[2]{#2#1}%

newcommand{foo}[1][1]{fooloop{#1}{}{counter value is}}

makeatletter

newcommand{fooloop}[3]{%

  ifnum#1>0 stepcounter{mycount}fi

  ifnum#1>1 expandafter@firstoftwoelseexpandafter@secondoftwofi

  {% 

    begingroup

    protected@edef@tempa{themycount}%

    c@mycount=#1relax

    advancec@mycount by -1relax

    expandafterendgroup

    expandafterfooloopexpandafter

    {numberexpandafterc@mycountexpandafter}expandafter

    {romannumeral0expandafterExchangeexpandafter{@tempa}{ #2}, }%

    {counter values are}%

  }{%

    #3 textbf{#2themycount}%

  }%

}%

makeatother



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[4]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter values are textbf{3, 4, 5, 6}



medskip



now using with option to iterate 0 times---counter is unchanged and displayed: foo[0]



medskip



now using with option to iterate -1 times---counter is unchanged and displayed: foo[-1]



end{document}

enter image description here

edited Jan 27 at 5:21

answered Jan 27 at 5:10

Ulrich Diez

4,985618

edited Jan 27 at 5:21

answered Jan 27 at 5:10

Ulrich Diez

4,985618

answered Jan 27 at 5:10

Ulrich Diez

4,985618

answered Jan 27 at 5:10

Ulrich Diez

4,985618

add a comment |

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