Does every non-elementary subgroup of the additive group of rationals contain prime multiples of elements in...












1












$begingroup$



Let $H$ be a non-elementary proper subgroup of $(Bbb Q,+)$, the
additive group of rational numbers. Then there exists an element $a$
in $Bbb Qsetminus H$ such that $pcdot a$ is in $H$ for some prime
number $p$.




I have not been able to prove this. I'm looking to see if someone else out there has any advice. Anything would be appreciated.
If it turns out to be false I'd be happy to see a disproof of course.
Thank you.










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$endgroup$












  • $begingroup$
    Where did this problem arise?
    $endgroup$
    – Shaun
    Jan 12 at 15:12










  • $begingroup$
    @Shaun it's in a book on group theory. The author states it without proof, then uses it to prove the additive group of rationals contains only subgroups of infinite index.
    $endgroup$
    – Tim Eller
    Jan 12 at 15:16










  • $begingroup$
    Okay, @TimEller; which book?
    $endgroup$
    – Shaun
    Jan 12 at 15:16










  • $begingroup$
    @Shaun Theory of Groups by A. G. Kurosh
    $endgroup$
    – Tim Eller
    Jan 12 at 15:17










  • $begingroup$
    @Shaun did you edit my post? I have a question about the edit.
    $endgroup$
    – Tim Eller
    Jan 12 at 16:28
















1












$begingroup$



Let $H$ be a non-elementary proper subgroup of $(Bbb Q,+)$, the
additive group of rational numbers. Then there exists an element $a$
in $Bbb Qsetminus H$ such that $pcdot a$ is in $H$ for some prime
number $p$.




I have not been able to prove this. I'm looking to see if someone else out there has any advice. Anything would be appreciated.
If it turns out to be false I'd be happy to see a disproof of course.
Thank you.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Where did this problem arise?
    $endgroup$
    – Shaun
    Jan 12 at 15:12










  • $begingroup$
    @Shaun it's in a book on group theory. The author states it without proof, then uses it to prove the additive group of rationals contains only subgroups of infinite index.
    $endgroup$
    – Tim Eller
    Jan 12 at 15:16










  • $begingroup$
    Okay, @TimEller; which book?
    $endgroup$
    – Shaun
    Jan 12 at 15:16










  • $begingroup$
    @Shaun Theory of Groups by A. G. Kurosh
    $endgroup$
    – Tim Eller
    Jan 12 at 15:17










  • $begingroup$
    @Shaun did you edit my post? I have a question about the edit.
    $endgroup$
    – Tim Eller
    Jan 12 at 16:28














1












1








1





$begingroup$



Let $H$ be a non-elementary proper subgroup of $(Bbb Q,+)$, the
additive group of rational numbers. Then there exists an element $a$
in $Bbb Qsetminus H$ such that $pcdot a$ is in $H$ for some prime
number $p$.




I have not been able to prove this. I'm looking to see if someone else out there has any advice. Anything would be appreciated.
If it turns out to be false I'd be happy to see a disproof of course.
Thank you.










share|cite|improve this question











$endgroup$





Let $H$ be a non-elementary proper subgroup of $(Bbb Q,+)$, the
additive group of rational numbers. Then there exists an element $a$
in $Bbb Qsetminus H$ such that $pcdot a$ is in $H$ for some prime
number $p$.




I have not been able to prove this. I'm looking to see if someone else out there has any advice. Anything would be appreciated.
If it turns out to be false I'd be happy to see a disproof of course.
Thank you.







group-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 12 at 15:04









Thomas Shelby

3,0971523




3,0971523










asked Jan 12 at 14:53









Tim EllerTim Eller

112




112












  • $begingroup$
    Where did this problem arise?
    $endgroup$
    – Shaun
    Jan 12 at 15:12










  • $begingroup$
    @Shaun it's in a book on group theory. The author states it without proof, then uses it to prove the additive group of rationals contains only subgroups of infinite index.
    $endgroup$
    – Tim Eller
    Jan 12 at 15:16










  • $begingroup$
    Okay, @TimEller; which book?
    $endgroup$
    – Shaun
    Jan 12 at 15:16










  • $begingroup$
    @Shaun Theory of Groups by A. G. Kurosh
    $endgroup$
    – Tim Eller
    Jan 12 at 15:17










  • $begingroup$
    @Shaun did you edit my post? I have a question about the edit.
    $endgroup$
    – Tim Eller
    Jan 12 at 16:28


















  • $begingroup$
    Where did this problem arise?
    $endgroup$
    – Shaun
    Jan 12 at 15:12










  • $begingroup$
    @Shaun it's in a book on group theory. The author states it without proof, then uses it to prove the additive group of rationals contains only subgroups of infinite index.
    $endgroup$
    – Tim Eller
    Jan 12 at 15:16










  • $begingroup$
    Okay, @TimEller; which book?
    $endgroup$
    – Shaun
    Jan 12 at 15:16










  • $begingroup$
    @Shaun Theory of Groups by A. G. Kurosh
    $endgroup$
    – Tim Eller
    Jan 12 at 15:17










  • $begingroup$
    @Shaun did you edit my post? I have a question about the edit.
    $endgroup$
    – Tim Eller
    Jan 12 at 16:28
















$begingroup$
Where did this problem arise?
$endgroup$
– Shaun
Jan 12 at 15:12




$begingroup$
Where did this problem arise?
$endgroup$
– Shaun
Jan 12 at 15:12












$begingroup$
@Shaun it's in a book on group theory. The author states it without proof, then uses it to prove the additive group of rationals contains only subgroups of infinite index.
$endgroup$
– Tim Eller
Jan 12 at 15:16




$begingroup$
@Shaun it's in a book on group theory. The author states it without proof, then uses it to prove the additive group of rationals contains only subgroups of infinite index.
$endgroup$
– Tim Eller
Jan 12 at 15:16












$begingroup$
Okay, @TimEller; which book?
$endgroup$
– Shaun
Jan 12 at 15:16




$begingroup$
Okay, @TimEller; which book?
$endgroup$
– Shaun
Jan 12 at 15:16












$begingroup$
@Shaun Theory of Groups by A. G. Kurosh
$endgroup$
– Tim Eller
Jan 12 at 15:17




$begingroup$
@Shaun Theory of Groups by A. G. Kurosh
$endgroup$
– Tim Eller
Jan 12 at 15:17












$begingroup$
@Shaun did you edit my post? I have a question about the edit.
$endgroup$
– Tim Eller
Jan 12 at 16:28




$begingroup$
@Shaun did you edit my post? I have a question about the edit.
$endgroup$
– Tim Eller
Jan 12 at 16:28










1 Answer
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$begingroup$

Suppose $frac mnin mathbb Q/H$ with $gcd(m,n)=1$ and let $n=prod p_i^{a_i}$ be the prime factorization of $n$. We multiply by one of the $p_i$ after another. If we get to an element in $H$ we are done, otherwise we can assume that this process leads to an integer $r in mathbb Q/H$.



Let $sin Hcap mathbb Z$. (Note: if $frac lkin H$ then $lin Hcap mathbb Z$.) Then of course $srin H$. If $s=prod q_i^{b_i}$ is the prime factorization of $s$, then we divide $sr$ by each $q_i$ in turn until we get to an element not in $H$.






share|cite|improve this answer











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  • $begingroup$
    Thanks for answering
    $endgroup$
    – Tim Eller
    Jan 13 at 15:47











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Suppose $frac mnin mathbb Q/H$ with $gcd(m,n)=1$ and let $n=prod p_i^{a_i}$ be the prime factorization of $n$. We multiply by one of the $p_i$ after another. If we get to an element in $H$ we are done, otherwise we can assume that this process leads to an integer $r in mathbb Q/H$.



Let $sin Hcap mathbb Z$. (Note: if $frac lkin H$ then $lin Hcap mathbb Z$.) Then of course $srin H$. If $s=prod q_i^{b_i}$ is the prime factorization of $s$, then we divide $sr$ by each $q_i$ in turn until we get to an element not in $H$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thanks for answering
    $endgroup$
    – Tim Eller
    Jan 13 at 15:47
















2












$begingroup$

Suppose $frac mnin mathbb Q/H$ with $gcd(m,n)=1$ and let $n=prod p_i^{a_i}$ be the prime factorization of $n$. We multiply by one of the $p_i$ after another. If we get to an element in $H$ we are done, otherwise we can assume that this process leads to an integer $r in mathbb Q/H$.



Let $sin Hcap mathbb Z$. (Note: if $frac lkin H$ then $lin Hcap mathbb Z$.) Then of course $srin H$. If $s=prod q_i^{b_i}$ is the prime factorization of $s$, then we divide $sr$ by each $q_i$ in turn until we get to an element not in $H$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thanks for answering
    $endgroup$
    – Tim Eller
    Jan 13 at 15:47














2












2








2





$begingroup$

Suppose $frac mnin mathbb Q/H$ with $gcd(m,n)=1$ and let $n=prod p_i^{a_i}$ be the prime factorization of $n$. We multiply by one of the $p_i$ after another. If we get to an element in $H$ we are done, otherwise we can assume that this process leads to an integer $r in mathbb Q/H$.



Let $sin Hcap mathbb Z$. (Note: if $frac lkin H$ then $lin Hcap mathbb Z$.) Then of course $srin H$. If $s=prod q_i^{b_i}$ is the prime factorization of $s$, then we divide $sr$ by each $q_i$ in turn until we get to an element not in $H$.






share|cite|improve this answer











$endgroup$



Suppose $frac mnin mathbb Q/H$ with $gcd(m,n)=1$ and let $n=prod p_i^{a_i}$ be the prime factorization of $n$. We multiply by one of the $p_i$ after another. If we get to an element in $H$ we are done, otherwise we can assume that this process leads to an integer $r in mathbb Q/H$.



Let $sin Hcap mathbb Z$. (Note: if $frac lkin H$ then $lin Hcap mathbb Z$.) Then of course $srin H$. If $s=prod q_i^{b_i}$ is the prime factorization of $s$, then we divide $sr$ by each $q_i$ in turn until we get to an element not in $H$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Jan 13 at 15:47









amWhy

1




1










answered Jan 12 at 15:16









lulululu

41.3k24979




41.3k24979












  • $begingroup$
    Thanks for answering
    $endgroup$
    – Tim Eller
    Jan 13 at 15:47


















  • $begingroup$
    Thanks for answering
    $endgroup$
    – Tim Eller
    Jan 13 at 15:47
















$begingroup$
Thanks for answering
$endgroup$
– Tim Eller
Jan 13 at 15:47




$begingroup$
Thanks for answering
$endgroup$
– Tim Eller
Jan 13 at 15:47


















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