Dynamical system with $f(x)leq f(Tx) leq f(T^2 x) leq …$
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Let $(X,mathcal{F},mu,T)$ be a measure preserving system and $fin L^1(X,mathcal{F},mu)$.
Problem: show that if $f(x)leq f(Tx)$ $forall xin X$ then $f(x)=f(Tx)$ $mu$-a.e.
It seems to be useful to have it about $C:=lbrace x: f(x)= crbrace$, then by measure preservingness we get $mulbrace x: f(x)= crbrace = mu(C)=mu(T^{-1}C) = mulbrace x: f(Tx)= crbrace$. Or maybe inequalities are more useful.
For the rest I have really no idea what to do. Is there anyone who can give a solution? Thanks in advance.
ergodic-theory
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add a comment |
$begingroup$
Let $(X,mathcal{F},mu,T)$ be a measure preserving system and $fin L^1(X,mathcal{F},mu)$.
Problem: show that if $f(x)leq f(Tx)$ $forall xin X$ then $f(x)=f(Tx)$ $mu$-a.e.
It seems to be useful to have it about $C:=lbrace x: f(x)= crbrace$, then by measure preservingness we get $mulbrace x: f(x)= crbrace = mu(C)=mu(T^{-1}C) = mulbrace x: f(Tx)= crbrace$. Or maybe inequalities are more useful.
For the rest I have really no idea what to do. Is there anyone who can give a solution? Thanks in advance.
ergodic-theory
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3
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Consider the function $g(x):=f(Tx)-f(x)$. Note that $g$ is non-negative but has integral $0$.
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– Blackbird
Jan 19 at 0:37
add a comment |
$begingroup$
Let $(X,mathcal{F},mu,T)$ be a measure preserving system and $fin L^1(X,mathcal{F},mu)$.
Problem: show that if $f(x)leq f(Tx)$ $forall xin X$ then $f(x)=f(Tx)$ $mu$-a.e.
It seems to be useful to have it about $C:=lbrace x: f(x)= crbrace$, then by measure preservingness we get $mulbrace x: f(x)= crbrace = mu(C)=mu(T^{-1}C) = mulbrace x: f(Tx)= crbrace$. Or maybe inequalities are more useful.
For the rest I have really no idea what to do. Is there anyone who can give a solution? Thanks in advance.
ergodic-theory
$endgroup$
Let $(X,mathcal{F},mu,T)$ be a measure preserving system and $fin L^1(X,mathcal{F},mu)$.
Problem: show that if $f(x)leq f(Tx)$ $forall xin X$ then $f(x)=f(Tx)$ $mu$-a.e.
It seems to be useful to have it about $C:=lbrace x: f(x)= crbrace$, then by measure preservingness we get $mulbrace x: f(x)= crbrace = mu(C)=mu(T^{-1}C) = mulbrace x: f(Tx)= crbrace$. Or maybe inequalities are more useful.
For the rest I have really no idea what to do. Is there anyone who can give a solution? Thanks in advance.
ergodic-theory
ergodic-theory
edited Jan 18 at 20:32
Rocco van Vreumingen
asked Jan 18 at 16:55
Rocco van VreumingenRocco van Vreumingen
928
928
3
$begingroup$
Consider the function $g(x):=f(Tx)-f(x)$. Note that $g$ is non-negative but has integral $0$.
$endgroup$
– Blackbird
Jan 19 at 0:37
add a comment |
3
$begingroup$
Consider the function $g(x):=f(Tx)-f(x)$. Note that $g$ is non-negative but has integral $0$.
$endgroup$
– Blackbird
Jan 19 at 0:37
3
3
$begingroup$
Consider the function $g(x):=f(Tx)-f(x)$. Note that $g$ is non-negative but has integral $0$.
$endgroup$
– Blackbird
Jan 19 at 0:37
$begingroup$
Consider the function $g(x):=f(Tx)-f(x)$. Note that $g$ is non-negative but has integral $0$.
$endgroup$
– Blackbird
Jan 19 at 0:37
add a comment |
0
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3
$begingroup$
Consider the function $g(x):=f(Tx)-f(x)$. Note that $g$ is non-negative but has integral $0$.
$endgroup$
– Blackbird
Jan 19 at 0:37