How to auto-escape a special char in VS Code Snippets?












0















I want to write a snippet for Debugging in TYPO3.



This is my Snippet-Code in php.json file:



"TYPO3 Extbase DebuggerUtility": {
"prefix": "ee",
"body": [
"\TYPO3\CMS\Extbase\Utility\DebuggerUtility::var_dump($1,'$1');",
"$0"
],
"description": "TYPO3 Extbase DebuggerUtility"
},


If I want to debug something liket this : $this->settings['key'] I get this code:



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


But it should looks like this



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


With escaped ' in the second part of that snippet.



EDIT



Thank you, but I think you missunderstood the question.



I don't want to escape a static character. I want to use the snippet and when I type the first $1-content it should be $this->settings['someKey'] but the second $1 (which is near the same) should automatically escape the ' chars I write, that I don't do this manually by hand.



So if i type '
first $1: ' second $1: ' that my Debug looks like this




Debug:



$this->settings['someKey']



contentOfsomeKey




I I don't escape the ' signs inside the "title of the debug" it breaks the string because ' wraps the debug-title.



In other words: I want to escape the content of the second $1 variable not the variable or the '-wrap in the snippet.



I hope I could clarify my issue.










share|improve this question

























  • There are a number of answers already on this; see, e.g., stackoverflow.com/questions/52302768/…

    – Mark
    Nov 21 '18 at 15:34











  • thx @Mark / Bernd - I updated my question, your answers doesn't fit my question

    – MonTea
    Nov 22 '18 at 8:20
















0















I want to write a snippet for Debugging in TYPO3.



This is my Snippet-Code in php.json file:



"TYPO3 Extbase DebuggerUtility": {
"prefix": "ee",
"body": [
"\TYPO3\CMS\Extbase\Utility\DebuggerUtility::var_dump($1,'$1');",
"$0"
],
"description": "TYPO3 Extbase DebuggerUtility"
},


If I want to debug something liket this : $this->settings['key'] I get this code:



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


But it should looks like this



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


With escaped ' in the second part of that snippet.



EDIT



Thank you, but I think you missunderstood the question.



I don't want to escape a static character. I want to use the snippet and when I type the first $1-content it should be $this->settings['someKey'] but the second $1 (which is near the same) should automatically escape the ' chars I write, that I don't do this manually by hand.



So if i type '
first $1: ' second $1: ' that my Debug looks like this




Debug:



$this->settings['someKey']



contentOfsomeKey




I I don't escape the ' signs inside the "title of the debug" it breaks the string because ' wraps the debug-title.



In other words: I want to escape the content of the second $1 variable not the variable or the '-wrap in the snippet.



I hope I could clarify my issue.










share|improve this question

























  • There are a number of answers already on this; see, e.g., stackoverflow.com/questions/52302768/…

    – Mark
    Nov 21 '18 at 15:34











  • thx @Mark / Bernd - I updated my question, your answers doesn't fit my question

    – MonTea
    Nov 22 '18 at 8:20














0












0








0








I want to write a snippet for Debugging in TYPO3.



This is my Snippet-Code in php.json file:



"TYPO3 Extbase DebuggerUtility": {
"prefix": "ee",
"body": [
"\TYPO3\CMS\Extbase\Utility\DebuggerUtility::var_dump($1,'$1');",
"$0"
],
"description": "TYPO3 Extbase DebuggerUtility"
},


If I want to debug something liket this : $this->settings['key'] I get this code:



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


But it should looks like this



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


With escaped ' in the second part of that snippet.



EDIT



Thank you, but I think you missunderstood the question.



I don't want to escape a static character. I want to use the snippet and when I type the first $1-content it should be $this->settings['someKey'] but the second $1 (which is near the same) should automatically escape the ' chars I write, that I don't do this manually by hand.



So if i type '
first $1: ' second $1: ' that my Debug looks like this




Debug:



$this->settings['someKey']



contentOfsomeKey




I I don't escape the ' signs inside the "title of the debug" it breaks the string because ' wraps the debug-title.



In other words: I want to escape the content of the second $1 variable not the variable or the '-wrap in the snippet.



I hope I could clarify my issue.










share|improve this question
















I want to write a snippet for Debugging in TYPO3.



This is my Snippet-Code in php.json file:



"TYPO3 Extbase DebuggerUtility": {
"prefix": "ee",
"body": [
"\TYPO3\CMS\Extbase\Utility\DebuggerUtility::var_dump($1,'$1');",
"$0"
],
"description": "TYPO3 Extbase DebuggerUtility"
},


If I want to debug something liket this : $this->settings['key'] I get this code:



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


But it should looks like this



TYPO3CMSExtbaseUtilityDebuggerUtility::var_dump($this->settings['key'],'$this->settings['key']');


With escaped ' in the second part of that snippet.



EDIT



Thank you, but I think you missunderstood the question.



I don't want to escape a static character. I want to use the snippet and when I type the first $1-content it should be $this->settings['someKey'] but the second $1 (which is near the same) should automatically escape the ' chars I write, that I don't do this manually by hand.



So if i type '
first $1: ' second $1: ' that my Debug looks like this




Debug:



$this->settings['someKey']



contentOfsomeKey




I I don't escape the ' signs inside the "title of the debug" it breaks the string because ' wraps the debug-title.



In other words: I want to escape the content of the second $1 variable not the variable or the '-wrap in the snippet.



I hope I could clarify my issue.







visual-studio-code code-snippets






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share|improve this question








edited Nov 21 '18 at 15:45







MonTea

















asked Nov 21 '18 at 10:50









MonTeaMonTea

288315




288315













  • There are a number of answers already on this; see, e.g., stackoverflow.com/questions/52302768/…

    – Mark
    Nov 21 '18 at 15:34











  • thx @Mark / Bernd - I updated my question, your answers doesn't fit my question

    – MonTea
    Nov 22 '18 at 8:20



















  • There are a number of answers already on this; see, e.g., stackoverflow.com/questions/52302768/…

    – Mark
    Nov 21 '18 at 15:34











  • thx @Mark / Bernd - I updated my question, your answers doesn't fit my question

    – MonTea
    Nov 22 '18 at 8:20

















There are a number of answers already on this; see, e.g., stackoverflow.com/questions/52302768/…

– Mark
Nov 21 '18 at 15:34





There are a number of answers already on this; see, e.g., stackoverflow.com/questions/52302768/…

– Mark
Nov 21 '18 at 15:34













thx @Mark / Bernd - I updated my question, your answers doesn't fit my question

– MonTea
Nov 22 '18 at 8:20





thx @Mark / Bernd - I updated my question, your answers doesn't fit my question

– MonTea
Nov 22 '18 at 8:20












1 Answer
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If you want escape characters in your output you need to insert escaped escape characters: \ this should result in single escape characters.

You might need an additional escape character if the following character needs an additional escaping: one backslash before quote ' = \+ ' = \'



`






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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    If you want escape characters in your output you need to insert escaped escape characters: \ this should result in single escape characters.

    You might need an additional escape character if the following character needs an additional escaping: one backslash before quote ' = \+ ' = \'



    `






    share|improve this answer




























      0














      If you want escape characters in your output you need to insert escaped escape characters: \ this should result in single escape characters.

      You might need an additional escape character if the following character needs an additional escaping: one backslash before quote ' = \+ ' = \'



      `






      share|improve this answer


























        0












        0








        0







        If you want escape characters in your output you need to insert escaped escape characters: \ this should result in single escape characters.

        You might need an additional escape character if the following character needs an additional escaping: one backslash before quote ' = \+ ' = \'



        `






        share|improve this answer













        If you want escape characters in your output you need to insert escaped escape characters: \ this should result in single escape characters.

        You might need an additional escape character if the following character needs an additional escaping: one backslash before quote ' = \+ ' = \'



        `







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 14:03









        Bernd Wilke πφBernd Wilke πφ

        5,0671824




        5,0671824
































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