Laravel 5.5 Eloquent groupBy on ManyToMany Relationship












0















For example, I need take tags name and its not duplicate each categories



here my model



Post.php



class Posts extends Model
{
public function category()
{
return $this->belongsTo(Category::class);
}

public function tags() : belongsToMany
{
return $this->belongsToMany(Tag::class, 'post_tag', 'post_id', 'tag_id');
}
}


Category.php



class Category extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


Tag.php



class Tag extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


and here what I do.



Category::with(['posts.tags' => function($query){
$query->groupBy('name'); // i need show tags name and group it, so its will not duplcate
}])->get();


for $query->groupBy('name'); name is tags name.



example



Categpry A
|__Title A
|__Tag A
|__Tag B
|__Tag C
|__Tag D
|__Title B
|__Tag A
|__Tag D
|__Tag E


the result must be Tag A, Tag B, Tag C, Tag D, Tag E i don't have an idea how to right now, any have a solution?...



thank you!










share|improve this question


















  • 1





    What is your current result?

    – Jared Chu
    Nov 21 '18 at 3:50











  • error tagsIlluminate/Database/QueryException with message 'SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'blog.categories.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select categories.*, post_tag.post_id` as pivot_post_id, post_category.category_id as pivot_category_id, post_category.created_at as pivot_created_at, post_category.updated_at as pivot_updated_at ......'`

    – Dicky Raambo
    Nov 21 '18 at 3:55











  • The Title A is post title, right? I think you should get the data and group them by PHP code instead of SQL query.

    – Jared Chu
    Nov 21 '18 at 4:01











  • yes it's post title

    – Dicky Raambo
    Nov 21 '18 at 4:15
















0















For example, I need take tags name and its not duplicate each categories



here my model



Post.php



class Posts extends Model
{
public function category()
{
return $this->belongsTo(Category::class);
}

public function tags() : belongsToMany
{
return $this->belongsToMany(Tag::class, 'post_tag', 'post_id', 'tag_id');
}
}


Category.php



class Category extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


Tag.php



class Tag extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


and here what I do.



Category::with(['posts.tags' => function($query){
$query->groupBy('name'); // i need show tags name and group it, so its will not duplcate
}])->get();


for $query->groupBy('name'); name is tags name.



example



Categpry A
|__Title A
|__Tag A
|__Tag B
|__Tag C
|__Tag D
|__Title B
|__Tag A
|__Tag D
|__Tag E


the result must be Tag A, Tag B, Tag C, Tag D, Tag E i don't have an idea how to right now, any have a solution?...



thank you!










share|improve this question


















  • 1





    What is your current result?

    – Jared Chu
    Nov 21 '18 at 3:50











  • error tagsIlluminate/Database/QueryException with message 'SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'blog.categories.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select categories.*, post_tag.post_id` as pivot_post_id, post_category.category_id as pivot_category_id, post_category.created_at as pivot_created_at, post_category.updated_at as pivot_updated_at ......'`

    – Dicky Raambo
    Nov 21 '18 at 3:55











  • The Title A is post title, right? I think you should get the data and group them by PHP code instead of SQL query.

    – Jared Chu
    Nov 21 '18 at 4:01











  • yes it's post title

    – Dicky Raambo
    Nov 21 '18 at 4:15














0












0








0


0






For example, I need take tags name and its not duplicate each categories



here my model



Post.php



class Posts extends Model
{
public function category()
{
return $this->belongsTo(Category::class);
}

public function tags() : belongsToMany
{
return $this->belongsToMany(Tag::class, 'post_tag', 'post_id', 'tag_id');
}
}


Category.php



class Category extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


Tag.php



class Tag extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


and here what I do.



Category::with(['posts.tags' => function($query){
$query->groupBy('name'); // i need show tags name and group it, so its will not duplcate
}])->get();


for $query->groupBy('name'); name is tags name.



example



Categpry A
|__Title A
|__Tag A
|__Tag B
|__Tag C
|__Tag D
|__Title B
|__Tag A
|__Tag D
|__Tag E


the result must be Tag A, Tag B, Tag C, Tag D, Tag E i don't have an idea how to right now, any have a solution?...



thank you!










share|improve this question














For example, I need take tags name and its not duplicate each categories



here my model



Post.php



class Posts extends Model
{
public function category()
{
return $this->belongsTo(Category::class);
}

public function tags() : belongsToMany
{
return $this->belongsToMany(Tag::class, 'post_tag', 'post_id', 'tag_id');
}
}


Category.php



class Category extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


Tag.php



class Tag extends Model
{
public function posts()
{
return $this->hasMany(Post::class);
}
}


and here what I do.



Category::with(['posts.tags' => function($query){
$query->groupBy('name'); // i need show tags name and group it, so its will not duplcate
}])->get();


for $query->groupBy('name'); name is tags name.



example



Categpry A
|__Title A
|__Tag A
|__Tag B
|__Tag C
|__Tag D
|__Title B
|__Tag A
|__Tag D
|__Tag E


the result must be Tag A, Tag B, Tag C, Tag D, Tag E i don't have an idea how to right now, any have a solution?...



thank you!







php laravel






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 '18 at 3:43









Dicky RaamboDicky Raambo

14811




14811








  • 1





    What is your current result?

    – Jared Chu
    Nov 21 '18 at 3:50











  • error tagsIlluminate/Database/QueryException with message 'SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'blog.categories.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select categories.*, post_tag.post_id` as pivot_post_id, post_category.category_id as pivot_category_id, post_category.created_at as pivot_created_at, post_category.updated_at as pivot_updated_at ......'`

    – Dicky Raambo
    Nov 21 '18 at 3:55











  • The Title A is post title, right? I think you should get the data and group them by PHP code instead of SQL query.

    – Jared Chu
    Nov 21 '18 at 4:01











  • yes it's post title

    – Dicky Raambo
    Nov 21 '18 at 4:15














  • 1





    What is your current result?

    – Jared Chu
    Nov 21 '18 at 3:50











  • error tagsIlluminate/Database/QueryException with message 'SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'blog.categories.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select categories.*, post_tag.post_id` as pivot_post_id, post_category.category_id as pivot_category_id, post_category.created_at as pivot_created_at, post_category.updated_at as pivot_updated_at ......'`

    – Dicky Raambo
    Nov 21 '18 at 3:55











  • The Title A is post title, right? I think you should get the data and group them by PHP code instead of SQL query.

    – Jared Chu
    Nov 21 '18 at 4:01











  • yes it's post title

    – Dicky Raambo
    Nov 21 '18 at 4:15








1




1





What is your current result?

– Jared Chu
Nov 21 '18 at 3:50





What is your current result?

– Jared Chu
Nov 21 '18 at 3:50













error tagsIlluminate/Database/QueryException with message 'SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'blog.categories.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select categories.*, post_tag.post_id` as pivot_post_id, post_category.category_id as pivot_category_id, post_category.created_at as pivot_created_at, post_category.updated_at as pivot_updated_at ......'`

– Dicky Raambo
Nov 21 '18 at 3:55





error tagsIlluminate/Database/QueryException with message 'SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'blog.categories.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select categories.*, post_tag.post_id` as pivot_post_id, post_category.category_id as pivot_category_id, post_category.created_at as pivot_created_at, post_category.updated_at as pivot_updated_at ......'`

– Dicky Raambo
Nov 21 '18 at 3:55













The Title A is post title, right? I think you should get the data and group them by PHP code instead of SQL query.

– Jared Chu
Nov 21 '18 at 4:01





The Title A is post title, right? I think you should get the data and group them by PHP code instead of SQL query.

– Jared Chu
Nov 21 '18 at 4:01













yes it's post title

– Dicky Raambo
Nov 21 '18 at 4:15





yes it's post title

– Dicky Raambo
Nov 21 '18 at 4:15












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