Let $S={ mathcal{X_s} ;;|;; sinmathbb{R} }$. It is possible that $ Span(S) = mathbb{R}^{mathbb{R}}$
$begingroup$
Let $S={ mathcal{X_s} ;;|;; sinmathbb{R} }$.
It is possible that $ Span(S)=langle Srangle = mathbb{R}^{mathbb{R}}={f:mathbb{R} rightarrow mathbb{R} ; |;; f;; fuction }$?
I do not think this is possible, but I can not prove it. Can anyone give me a hint on how to prove this or a counter example. I also wanted a hint on how to describe the subspace generated $Span(S)=langle Srangle.$
linear-algebra vector-spaces
$endgroup$
add a comment |
$begingroup$
Let $S={ mathcal{X_s} ;;|;; sinmathbb{R} }$.
It is possible that $ Span(S)=langle Srangle = mathbb{R}^{mathbb{R}}={f:mathbb{R} rightarrow mathbb{R} ; |;; f;; fuction }$?
I do not think this is possible, but I can not prove it. Can anyone give me a hint on how to prove this or a counter example. I also wanted a hint on how to describe the subspace generated $Span(S)=langle Srangle.$
linear-algebra vector-spaces
$endgroup$
add a comment |
$begingroup$
Let $S={ mathcal{X_s} ;;|;; sinmathbb{R} }$.
It is possible that $ Span(S)=langle Srangle = mathbb{R}^{mathbb{R}}={f:mathbb{R} rightarrow mathbb{R} ; |;; f;; fuction }$?
I do not think this is possible, but I can not prove it. Can anyone give me a hint on how to prove this or a counter example. I also wanted a hint on how to describe the subspace generated $Span(S)=langle Srangle.$
linear-algebra vector-spaces
$endgroup$
Let $S={ mathcal{X_s} ;;|;; sinmathbb{R} }$.
It is possible that $ Span(S)=langle Srangle = mathbb{R}^{mathbb{R}}={f:mathbb{R} rightarrow mathbb{R} ; |;; f;; fuction }$?
I do not think this is possible, but I can not prove it. Can anyone give me a hint on how to prove this or a counter example. I also wanted a hint on how to describe the subspace generated $Span(S)=langle Srangle.$
linear-algebra vector-spaces
linear-algebra vector-spaces
edited Jan 18 at 19:02


José Carlos Santos
164k22131234
164k22131234
asked Jan 18 at 17:40


Ricardo FreireRicardo Freire
513210
513210
add a comment |
add a comment |
1 Answer
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$begingroup$
I suppose that $chi_s(x)$ is $0$, unless $x=s$, in which case it is equal to $1$. If that's so, you are right, since every element of $operatorname{span}(S)$ is $0$ outside a finite set.
$endgroup$
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
1
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
add a comment |
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1 Answer
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1 Answer
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$begingroup$
I suppose that $chi_s(x)$ is $0$, unless $x=s$, in which case it is equal to $1$. If that's so, you are right, since every element of $operatorname{span}(S)$ is $0$ outside a finite set.
$endgroup$
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
1
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
add a comment |
$begingroup$
I suppose that $chi_s(x)$ is $0$, unless $x=s$, in which case it is equal to $1$. If that's so, you are right, since every element of $operatorname{span}(S)$ is $0$ outside a finite set.
$endgroup$
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
1
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
add a comment |
$begingroup$
I suppose that $chi_s(x)$ is $0$, unless $x=s$, in which case it is equal to $1$. If that's so, you are right, since every element of $operatorname{span}(S)$ is $0$ outside a finite set.
$endgroup$
I suppose that $chi_s(x)$ is $0$, unless $x=s$, in which case it is equal to $1$. If that's so, you are right, since every element of $operatorname{span}(S)$ is $0$ outside a finite set.
answered Jan 18 at 17:55


José Carlos SantosJosé Carlos Santos
164k22131234
164k22131234
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
1
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
add a comment |
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
1
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
Can you explain to me why outside a finite set $span (S) = { 0 }$?
$endgroup$
– Ricardo Freire
Jan 18 at 18:00
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
I did not write that. Fortunately, since it doesn't make sense.
$endgroup$
– José Carlos Santos
Jan 18 at 18:02
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
$begingroup$
Sorry, I got confused, I wanted to know if you have a way of describing the generated subspace $span(S)$
$endgroup$
– Ricardo Freire
Jan 18 at 18:05
1
1
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
$begingroup$
Sure: it's the space of those functions $fcolonmathbb{R}longrightarrowmathbb{R}$ such that the set ${xinmathbb{R},|,f(x)neq0}$ is finite.
$endgroup$
– José Carlos Santos
Jan 18 at 18:07
add a comment |
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