Mixing
Parallel arrows along a curve with tikz
4
I want to draw parallel arrows (for example 10 arrows) from a line to a curve. It is not good idea that dividing the line and curve to 10 parts and then join them to each other because of mathematical reason the resulting arrows are not parallel.
What I have done is the following.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{arrows,positioning}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) --(0,-3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm, minimum width=(10+p)*0.3cm]
(M p){a}
};
foreach p in {5,10,15,...,95} {
draw[-latex,blue] (N p.center) -| (0,0);
}
end{tikzpicture}
end{document}
tikz-pgf tikz-arrows
asked Jan 12 at 8:02
C.F.GC.F.G
582312
add a comment |
4
I want to draw parallel arrows (for example 10 arrows) from a line to a curve. It is not good idea that dividing the line and curve to 10 parts and then join them to each other because of mathematical reason the resulting arrows are not parallel.
What I have done is the following.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{arrows,positioning}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) --(0,-3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm, minimum width=(10+p)*0.3cm]
(M p){a}
};
foreach p in {5,10,15,...,95} {
draw[-latex,blue] (N p.center) -| (0,0);
}
end{tikzpicture}
end{document}
tikz-pgf tikz-arrows
asked Jan 12 at 8:02
C.F.GC.F.G
582312
1
Your code is not compileable.
– AndréC
Jan 12 at 8:26
add a comment |
4
4
4
0
I want to draw parallel arrows (for example 10 arrows) from a line to a curve. It is not good idea that dividing the line and curve to 10 parts and then join them to each other because of mathematical reason the resulting arrows are not parallel.
What I have done is the following.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{arrows,positioning}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) --(0,-3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm, minimum width=(10+p)*0.3cm]
(M p){a}
};
foreach p in {5,10,15,...,95} {
draw[-latex,blue] (N p.center) -| (0,0);
}
end{tikzpicture}
end{document}
tikz-pgf tikz-arrows
asked Jan 12 at 8:02
C.F.GC.F.G
582312
I want to draw parallel arrows (for example 10 arrows) from a line to a curve. It is not good idea that dividing the line and curve to 10 parts and then join them to each other because of mathematical reason the resulting arrows are not parallel.
What I have done is the following.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{arrows,positioning}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) --(0,-3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm, minimum width=(10+p)*0.3cm]
(M p){a}
};
foreach p in {5,10,15,...,95} {
draw[-latex,blue] (N p.center) -| (0,0);
}
end{tikzpicture}
end{document}
tikz-pgf tikz-arrows
tikz-pgf tikz-arrows
asked Jan 12 at 8:02
C.F.GC.F.G
582312
asked Jan 12 at 8:02
C.F.GC.F.G
582312
edited Jan 12 at 10:40
C.F.G
asked Jan 12 at 8:02
C.F.GC.F.G
582312
asked Jan 12 at 8:02
C.F.GC.F.G
582312
asked Jan 12 at 8:02
C.F.GC.F.G
582312
582312
1
Your code is not compileable.
– AndréC
Jan 12 at 8:26
add a comment |
1
Your code is not compileable.
– AndréC
Jan 12 at 8:26
1
1
Your code is not compileable.
– AndréC
Jan 12 at 8:26
Your code is not compileable.
– AndréC
Jan 12 at 8:26
add a comment |
2 Answers
2
active
oldest
votes
6
I do not really know if I understand what you want but a slight modification of your code produces "parallel arrows from a line to a curve".
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) -- (0,-3.5);
foreach p in {5,10,15,...,95} {
draw[latex-,blue] (N p.center) -- (0,0 |- N p.center);
}
end{tikzpicture}
end{document}
ADDENDTUM: To reverse the arrows, you only need to replace draw[latex-,blue]... but draw[-latex,blue]. However, making the distance equal, requires slightly more effort
documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw[name path=arc] (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
foreach p in {-3.25,-3,...,3.25} {
path[name path=line] (0,p) -- (3,p);
draw[latex-,blue,name intersections={of=line and arc}]
(0,p) -- (intersection-1);
}
end{tikzpicture}
end{document}
You do not need intersections in this case, you could just use
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
clip (0,3.5) arc (90:-90:1.75 and 3.5) -- cycle;
foreach p in {-3.25,-3,...,3.25} {
draw[latex-,blue]
(0,p) -- (3,p);
}
end{tikzpicture}
end{document}
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
1
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
add a comment |
2
A PSTricks solution only for fun purposes.
documentclass[pstricks]{standalone}
usepackage{pst-plot}
begin{document}
begin{pspicture}[algebraic](-4,-4)(4,4)
pscircle{3}psline(0,-3)(0,3)
psellipticarc(0,0)(1,3){-90}{90}
curvepnodes[plotpoints=20]{-3}{3}{sqrt(1-(t/3)^2)|t}{A}
foreach i in {1,...,numexprAnodecount-1}{pcline[nodesepB=.4pt]{<-}(0,0|Ai)(Ai)}
end{pspicture}
end{document}
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
add a comment |
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2 Answers
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2 Answers
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oldest
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6
I do not really know if I understand what you want but a slight modification of your code produces "parallel arrows from a line to a curve".
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) -- (0,-3.5);
foreach p in {5,10,15,...,95} {
draw[latex-,blue] (N p.center) -- (0,0 |- N p.center);
}
end{tikzpicture}
end{document}
ADDENDTUM: To reverse the arrows, you only need to replace draw[latex-,blue]... but draw[-latex,blue]. However, making the distance equal, requires slightly more effort
documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw[name path=arc] (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
foreach p in {-3.25,-3,...,3.25} {
path[name path=line] (0,p) -- (3,p);
draw[latex-,blue,name intersections={of=line and arc}]
(0,p) -- (intersection-1);
}
end{tikzpicture}
end{document}
You do not need intersections in this case, you could just use
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
clip (0,3.5) arc (90:-90:1.75 and 3.5) -- cycle;
foreach p in {-3.25,-3,...,3.25} {
draw[latex-,blue]
(0,p) -- (3,p);
}
end{tikzpicture}
end{document}
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
1
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
add a comment |
6
I do not really know if I understand what you want but a slight modification of your code produces "parallel arrows from a line to a curve".
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) -- (0,-3.5);
foreach p in {5,10,15,...,95} {
draw[latex-,blue] (N p.center) -- (0,0 |- N p.center);
}
end{tikzpicture}
end{document}
ADDENDTUM: To reverse the arrows, you only need to replace draw[latex-,blue]... but draw[-latex,blue]. However, making the distance equal, requires slightly more effort
documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw[name path=arc] (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
foreach p in {-3.25,-3,...,3.25} {
path[name path=line] (0,p) -- (3,p);
draw[latex-,blue,name intersections={of=line and arc}]
(0,p) -- (intersection-1);
}
end{tikzpicture}
end{document}
You do not need intersections in this case, you could just use
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
clip (0,3.5) arc (90:-90:1.75 and 3.5) -- cycle;
foreach p in {-3.25,-3,...,3.25} {
draw[latex-,blue]
(0,p) -- (3,p);
}
end{tikzpicture}
end{document}
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
1
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
add a comment |
6
6
6
I do not really know if I understand what you want but a slight modification of your code produces "parallel arrows from a line to a curve".
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) -- (0,-3.5);
foreach p in {5,10,15,...,95} {
draw[latex-,blue] (N p.center) -- (0,0 |- N p.center);
}
end{tikzpicture}
end{document}
ADDENDTUM: To reverse the arrows, you only need to replace draw[latex-,blue]... but draw[-latex,blue]. However, making the distance equal, requires slightly more effort
documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw[name path=arc] (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
foreach p in {-3.25,-3,...,3.25} {
path[name path=line] (0,p) -- (3,p);
draw[latex-,blue,name intersections={of=line and arc}]
(0,p) -- (intersection-1);
}
end{tikzpicture}
end{document}
You do not need intersections in this case, you could just use
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
clip (0,3.5) arc (90:-90:1.75 and 3.5) -- cycle;
foreach p in {-3.25,-3,...,3.25} {
draw[latex-,blue]
(0,p) -- (3,p);
}
end{tikzpicture}
end{document}
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
I do not really know if I understand what you want but a slight modification of your code produces "parallel arrows from a line to a curve".
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5) foreach p in {0,5,...,100} {
node[inner sep=0cm,above,pos=p*0.01,
anchor=center,
minimum height=p*0.03cm,minimum width=(10+p)*0.3cm]
(N p){}
};
draw (0,3.5) -- (0,-3.5);
foreach p in {5,10,15,...,95} {
draw[latex-,blue] (N p.center) -- (0,0 |- N p.center);
}
end{tikzpicture}
end{document}
ADDENDTUM: To reverse the arrows, you only need to replace draw[latex-,blue]... but draw[-latex,blue]. However, making the distance equal, requires slightly more effort
documentclass[tikz,border=3.14mm]{standalone}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw[name path=arc] (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
foreach p in {-3.25,-3,...,3.25} {
path[name path=line] (0,p) -- (3,p);
draw[latex-,blue,name intersections={of=line and arc}]
(0,p) -- (intersection-1);
}
end{tikzpicture}
end{document}
You do not need intersections in this case, you could just use
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[allow upside down]
draw (0,0) circle (3.5);
draw (0,3.5) arc (90:-90:1.75 and 3.5);
draw (0,3.5) -- (0,-3.5);
clip (0,3.5) arc (90:-90:1.75 and 3.5) -- cycle;
foreach p in {-3.25,-3,...,3.25} {
draw[latex-,blue]
(0,p) -- (3,p);
}
end{tikzpicture}
end{document}
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
edited Jan 12 at 15:07
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
answered Jan 12 at 11:25
marmotmarmot
98.8k4113219
98.8k4113219
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
1
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
add a comment |
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
1
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
Is it possible to reverse the arrows and with equal distance?
– C.F.G
Jan 12 at 13:19
1
1
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
@C.F.G Sure. I added a possible way.
– marmot
Jan 12 at 15:08
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
Thank you so much. You are so expert.
– C.F.G
Jan 12 at 15:37
add a comment |
2
A PSTricks solution only for fun purposes.
documentclass[pstricks]{standalone}
usepackage{pst-plot}
begin{document}
begin{pspicture}[algebraic](-4,-4)(4,4)
pscircle{3}psline(0,-3)(0,3)
psellipticarc(0,0)(1,3){-90}{90}
curvepnodes[plotpoints=20]{-3}{3}{sqrt(1-(t/3)^2)|t}{A}
foreach i in {1,...,numexprAnodecount-1}{pcline[nodesepB=.4pt]{<-}(0,0|Ai)(Ai)}
end{pspicture}
end{document}
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
add a comment |
2
A PSTricks solution only for fun purposes.
documentclass[pstricks]{standalone}
usepackage{pst-plot}
begin{document}
begin{pspicture}[algebraic](-4,-4)(4,4)
pscircle{3}psline(0,-3)(0,3)
psellipticarc(0,0)(1,3){-90}{90}
curvepnodes[plotpoints=20]{-3}{3}{sqrt(1-(t/3)^2)|t}{A}
foreach i in {1,...,numexprAnodecount-1}{pcline[nodesepB=.4pt]{<-}(0,0|Ai)(Ai)}
end{pspicture}
end{document}
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
add a comment |
2
2
2
A PSTricks solution only for fun purposes.
documentclass[pstricks]{standalone}
usepackage{pst-plot}
begin{document}
begin{pspicture}[algebraic](-4,-4)(4,4)
pscircle{3}psline(0,-3)(0,3)
psellipticarc(0,0)(1,3){-90}{90}
curvepnodes[plotpoints=20]{-3}{3}{sqrt(1-(t/3)^2)|t}{A}
foreach i in {1,...,numexprAnodecount-1}{pcline[nodesepB=.4pt]{<-}(0,0|Ai)(Ai)}
end{pspicture}
end{document}
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
A PSTricks solution only for fun purposes.
documentclass[pstricks]{standalone}
usepackage{pst-plot}
begin{document}
begin{pspicture}[algebraic](-4,-4)(4,4)
pscircle{3}psline(0,-3)(0,3)
psellipticarc(0,0)(1,3){-90}{90}
curvepnodes[plotpoints=20]{-3}{3}{sqrt(1-(t/3)^2)|t}{A}
foreach i in {1,...,numexprAnodecount-1}{pcline[nodesepB=.4pt]{<-}(0,0|Ai)(Ai)}
end{pspicture}
end{document}
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
answered Jan 12 at 16:03
Artificial StupidityArtificial Stupidity
5,55511040
5,55511040
add a comment |
add a comment |
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Your code is not compileable.
– AndréC
Jan 12 at 8:26