Mixing
using an if statement to determine whether a number is greater than one then directing output to a separate...
I'm writing a program for a grading System. I have got the program practically finished bar one thing. I have to determine the mark in one method and then print the mark and grade awarded using a separate method but how do i get the output from the if statements into the method to print the grade.
here is my code:
/*
Author:
Title: Odds and Evens
Date created: 13/11/18
Version :1.0
*/
import java.util.Scanner;
public class GradeClassifier
{
public static void main (Stringargs)
{
displayTitle();
int mark = getMark();
determineGrade(mark);
}
public static void displayTitle ()// prints title
{
System.out.println ("Grade Classifier");
System.out.println ("****************");
}
public static int getMark()// getting the mark from user
{
Scanner in = new Scanner (System.in);
System.out.print ("Enter a mark :> ");
return in.nextInt();
}
public static int determineGrade(int n1)
{
Scanner in = new Scanner (System.in);
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
in.nextInt();
}
if (n1 < 100 && n1 > 70)
System.out.print("Grade A");
if (n1 < 69 && n1 > 60)
System.out.print("Grade B");
if (n1 < 59 && n1 > 50)
System.out.println("Grade C");
if (n1 < 49 && n1 > 40)
System.out.println("Grade D");
if (n1 < 40)
System.out.println ("Grade F - Fail");
return n1;
}
}
below the last method, I have that is where I need the printResult method
any help is appreciated
thanks.
Also, I do know that using the print statements below the if statements prints out the grade but this is not how I want the program structured
java
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
asked Nov 21 '18 at 17:07
kian5749kian5749
84
add a comment |
I'm writing a program for a grading System. I have got the program practically finished bar one thing. I have to determine the mark in one method and then print the mark and grade awarded using a separate method but how do i get the output from the if statements into the method to print the grade.
here is my code:
/*
Author:
Title: Odds and Evens
Date created: 13/11/18
Version :1.0
*/
import java.util.Scanner;
public class GradeClassifier
{
public static void main (Stringargs)
{
displayTitle();
int mark = getMark();
determineGrade(mark);
}
public static void displayTitle ()// prints title
{
System.out.println ("Grade Classifier");
System.out.println ("****************");
}
public static int getMark()// getting the mark from user
{
Scanner in = new Scanner (System.in);
System.out.print ("Enter a mark :> ");
return in.nextInt();
}
public static int determineGrade(int n1)
{
Scanner in = new Scanner (System.in);
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
in.nextInt();
}
if (n1 < 100 && n1 > 70)
System.out.print("Grade A");
if (n1 < 69 && n1 > 60)
System.out.print("Grade B");
if (n1 < 59 && n1 > 50)
System.out.println("Grade C");
if (n1 < 49 && n1 > 40)
System.out.println("Grade D");
if (n1 < 40)
System.out.println ("Grade F - Fail");
return n1;
}
}
below the last method, I have that is where I need the printResult method
any help is appreciated
thanks.
Also, I do know that using the print statements below the if statements prints out the grade but this is not how I want the program structured
java
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
asked Nov 21 '18 at 17:07
kian5749kian5749
84
4
Side note, the marks of 40, 50, 60, and 70 have no grade attached. Might want to use>=in theifstatements.
– AntonH
Nov 21 '18 at 17:14
You should also consider the case for 100 along with 40,50,60 and 70
– suvojit_007
Nov 21 '18 at 17:22
add a comment |
I'm writing a program for a grading System. I have got the program practically finished bar one thing. I have to determine the mark in one method and then print the mark and grade awarded using a separate method but how do i get the output from the if statements into the method to print the grade.
here is my code:
/*
Author:
Title: Odds and Evens
Date created: 13/11/18
Version :1.0
*/
import java.util.Scanner;
public class GradeClassifier
{
public static void main (Stringargs)
{
displayTitle();
int mark = getMark();
determineGrade(mark);
}
public static void displayTitle ()// prints title
{
System.out.println ("Grade Classifier");
System.out.println ("****************");
}
public static int getMark()// getting the mark from user
{
Scanner in = new Scanner (System.in);
System.out.print ("Enter a mark :> ");
return in.nextInt();
}
public static int determineGrade(int n1)
{
Scanner in = new Scanner (System.in);
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
in.nextInt();
}
if (n1 < 100 && n1 > 70)
System.out.print("Grade A");
if (n1 < 69 && n1 > 60)
System.out.print("Grade B");
if (n1 < 59 && n1 > 50)
System.out.println("Grade C");
if (n1 < 49 && n1 > 40)
System.out.println("Grade D");
if (n1 < 40)
System.out.println ("Grade F - Fail");
return n1;
}
}
below the last method, I have that is where I need the printResult method
any help is appreciated
thanks.
Also, I do know that using the print statements below the if statements prints out the grade but this is not how I want the program structured
java
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
asked Nov 21 '18 at 17:07
kian5749kian5749
84
I'm writing a program for a grading System. I have got the program practically finished bar one thing. I have to determine the mark in one method and then print the mark and grade awarded using a separate method but how do i get the output from the if statements into the method to print the grade.
here is my code:
/*
Author:
Title: Odds and Evens
Date created: 13/11/18
Version :1.0
*/
import java.util.Scanner;
public class GradeClassifier
{
public static void main (Stringargs)
{
displayTitle();
int mark = getMark();
determineGrade(mark);
}
public static void displayTitle ()// prints title
{
System.out.println ("Grade Classifier");
System.out.println ("****************");
}
public static int getMark()// getting the mark from user
{
Scanner in = new Scanner (System.in);
System.out.print ("Enter a mark :> ");
return in.nextInt();
}
public static int determineGrade(int n1)
{
Scanner in = new Scanner (System.in);
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
in.nextInt();
}
if (n1 < 100 && n1 > 70)
System.out.print("Grade A");
if (n1 < 69 && n1 > 60)
System.out.print("Grade B");
if (n1 < 59 && n1 > 50)
System.out.println("Grade C");
if (n1 < 49 && n1 > 40)
System.out.println("Grade D");
if (n1 < 40)
System.out.println ("Grade F - Fail");
return n1;
}
}
below the last method, I have that is where I need the printResult method
any help is appreciated
thanks.
Also, I do know that using the print statements below the if statements prints out the grade but this is not how I want the program structured
java
java
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
asked Nov 21 '18 at 17:07
kian5749kian5749
84
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
asked Nov 21 '18 at 17:07
kian5749kian5749
84
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
edited Nov 21 '18 at 17:14
suvojit_007
1,3241517
1,3241517
asked Nov 21 '18 at 17:07
kian5749kian5749
84
asked Nov 21 '18 at 17:07
kian5749kian5749
84
asked Nov 21 '18 at 17:07
kian5749kian5749
84
84
4
Side note, the marks of 40, 50, 60, and 70 have no grade attached. Might want to use>=in theifstatements.
– AntonH
Nov 21 '18 at 17:14
You should also consider the case for 100 along with 40,50,60 and 70
– suvojit_007
Nov 21 '18 at 17:22
add a comment |
4
Side note, the marks of 40, 50, 60, and 70 have no grade attached. Might want to use>=in theifstatements.
– AntonH
Nov 21 '18 at 17:14
You should also consider the case for 100 along with 40,50,60 and 70
– suvojit_007
Nov 21 '18 at 17:22
4
4
Side note, the marks of 40, 50, 60, and 70 have no grade attached. Might want to use
>= in the if statements.– AntonH
Nov 21 '18 at 17:14
Side note, the marks of 40, 50, 60, and 70 have no grade attached. Might want to use
>= in the if statements.– AntonH
Nov 21 '18 at 17:14
You should also consider the case for 100 along with 40,50,60 and 70
– suvojit_007
Nov 21 '18 at 17:22
You should also consider the case for 100 along with 40,50,60 and 70
– suvojit_007
Nov 21 '18 at 17:22
add a comment |
2 Answers
2
active
oldest
votes
Right now you're just returning the input parameter.
This modified code will return a String, which contains the grade:
public static String determineGrade(int n1)
{
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
Scanner in = new Scanner (System.in);
int newInput = in.nextInt();
determineGrade(newInput);
}
if (n1 <= 100 && n1 >= 70)
return "Grade A";
if (n1 < 69 && n1 >= 60)
return "Grade B";
if (n1 < 59 && n1 >= 50)
return "Grade C";
if (n1 < 49 && n1 >= 40)
return "Grade D";
if (n1 < 40)
return "Grade F - Fail";
return "";
}
You could also use System.out.println(determineGrade(input)); to directly print the grade.
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
add a comment |
You could set the grade string as the value of a class property, then you can have a method that simply prints whatever value is in the class property at the time it's called
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Right now you're just returning the input parameter.
This modified code will return a String, which contains the grade:
public static String determineGrade(int n1)
{
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
Scanner in = new Scanner (System.in);
int newInput = in.nextInt();
determineGrade(newInput);
}
if (n1 <= 100 && n1 >= 70)
return "Grade A";
if (n1 < 69 && n1 >= 60)
return "Grade B";
if (n1 < 59 && n1 >= 50)
return "Grade C";
if (n1 < 49 && n1 >= 40)
return "Grade D";
if (n1 < 40)
return "Grade F - Fail";
return "";
}
You could also use System.out.println(determineGrade(input)); to directly print the grade.
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
add a comment |
Right now you're just returning the input parameter.
This modified code will return a String, which contains the grade:
public static String determineGrade(int n1)
{
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
Scanner in = new Scanner (System.in);
int newInput = in.nextInt();
determineGrade(newInput);
}
if (n1 <= 100 && n1 >= 70)
return "Grade A";
if (n1 < 69 && n1 >= 60)
return "Grade B";
if (n1 < 59 && n1 >= 50)
return "Grade C";
if (n1 < 49 && n1 >= 40)
return "Grade D";
if (n1 < 40)
return "Grade F - Fail";
return "";
}
You could also use System.out.println(determineGrade(input)); to directly print the grade.
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
add a comment |
Right now you're just returning the input parameter.
This modified code will return a String, which contains the grade:
public static String determineGrade(int n1)
{
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
Scanner in = new Scanner (System.in);
int newInput = in.nextInt();
determineGrade(newInput);
}
if (n1 <= 100 && n1 >= 70)
return "Grade A";
if (n1 < 69 && n1 >= 60)
return "Grade B";
if (n1 < 59 && n1 >= 50)
return "Grade C";
if (n1 < 49 && n1 >= 40)
return "Grade D";
if (n1 < 40)
return "Grade F - Fail";
return "";
}
You could also use System.out.println(determineGrade(input)); to directly print the grade.
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
Right now you're just returning the input parameter.
This modified code will return a String, which contains the grade:
public static String determineGrade(int n1)
{
if (n1 > 100){
System.out.println ("INVALID MARK PLEASE TRY AGAIN");
Scanner in = new Scanner (System.in);
int newInput = in.nextInt();
determineGrade(newInput);
}
if (n1 <= 100 && n1 >= 70)
return "Grade A";
if (n1 < 69 && n1 >= 60)
return "Grade B";
if (n1 < 59 && n1 >= 50)
return "Grade C";
if (n1 < 49 && n1 >= 40)
return "Grade D";
if (n1 < 40)
return "Grade F - Fail";
return "";
}
You could also use System.out.println(determineGrade(input)); to directly print the grade.
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
edited Nov 21 '18 at 17:30
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
answered Nov 21 '18 at 17:14
dnsivdnsiv
322116
322116
add a comment |
add a comment |
You could set the grade string as the value of a class property, then you can have a method that simply prints whatever value is in the class property at the time it's called
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
add a comment |
You could set the grade string as the value of a class property, then you can have a method that simply prints whatever value is in the class property at the time it's called
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
add a comment |
You could set the grade string as the value of a class property, then you can have a method that simply prints whatever value is in the class property at the time it's called
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
You could set the grade string as the value of a class property, then you can have a method that simply prints whatever value is in the class property at the time it's called
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
answered Nov 21 '18 at 17:18
JmJJmJ
4951633
4951633
add a comment |
add a comment |
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4
Side note, the marks of 40, 50, 60, and 70 have no grade attached. Might want to use
>=in theifstatements.– AntonH
Nov 21 '18 at 17:14
You should also consider the case for 100 along with 40,50,60 and 70
– suvojit_007
Nov 21 '18 at 17:22