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What is significance of eigenvector of laplacian matrix?
-1
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The eigenvector of the Laplacian matrix is widely used in partition technique as spectral graph theory. What is the significance of 'K' eigenvector of the Laplacian matrix?
matrices graph-theory eigenvalues-eigenvectors laplacian
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
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add a comment |
-1
$begingroup$
The eigenvector of the Laplacian matrix is widely used in partition technique as spectral graph theory. What is the significance of 'K' eigenvector of the Laplacian matrix?
matrices graph-theory eigenvalues-eigenvectors laplacian
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
$endgroup$
$begingroup$
You need to re-phrase your question. What do you want to understand? An eigenvector is never "by itself". It's linked to an eigenvalue, and part of an eigenspace.
$endgroup$
– Thomas Lesgourgues
Jan 13 at 16:33
add a comment |
-1
-1
-1
$begingroup$
The eigenvector of the Laplacian matrix is widely used in partition technique as spectral graph theory. What is the significance of 'K' eigenvector of the Laplacian matrix?
matrices graph-theory eigenvalues-eigenvectors laplacian
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
$endgroup$
The eigenvector of the Laplacian matrix is widely used in partition technique as spectral graph theory. What is the significance of 'K' eigenvector of the Laplacian matrix?
matrices graph-theory eigenvalues-eigenvectors laplacian
matrices graph-theory eigenvalues-eigenvectors laplacian
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
asked Jan 12 at 13:38
A_GuptaA_Gupta
1
1
$begingroup$
You need to re-phrase your question. What do you want to understand? An eigenvector is never "by itself". It's linked to an eigenvalue, and part of an eigenspace.
$endgroup$
– Thomas Lesgourgues
Jan 13 at 16:33
add a comment |
$begingroup$
You need to re-phrase your question. What do you want to understand? An eigenvector is never "by itself". It's linked to an eigenvalue, and part of an eigenspace.
$endgroup$
– Thomas Lesgourgues
Jan 13 at 16:33
$begingroup$
You need to re-phrase your question. What do you want to understand? An eigenvector is never "by itself". It's linked to an eigenvalue, and part of an eigenspace.
$endgroup$
– Thomas Lesgourgues
Jan 13 at 16:33
$begingroup$
You need to re-phrase your question. What do you want to understand? An eigenvector is never "by itself". It's linked to an eigenvalue, and part of an eigenspace.
$endgroup$
– Thomas Lesgourgues
Jan 13 at 16:33
add a comment |
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$begingroup$
You need to re-phrase your question. What do you want to understand? An eigenvector is never "by itself". It's linked to an eigenvalue, and part of an eigenspace.
$endgroup$
– Thomas Lesgourgues
Jan 13 at 16:33