Mixing
Calculate probability if an event would have had occured
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I need help in solving the following question:
A company is working on new type of airbags for cars. The old air bags, in case of accident, are known to fail at a rate of 23%. New air bags were tested on 230 cars and 10% of them failed. What is the probability that 10% of the 230 cars would have had failures with old bags?
I am not able to figure out what information is provided and what am I supposed to calculate like for the first piece of information, P(failure|old air bags) is given or P(failure, old air bags). How do you figure from sentences if conditional probability is given or probability of intersection of two things?
probability conditional-probability
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
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add a comment |
$begingroup$
I need help in solving the following question:
A company is working on new type of airbags for cars. The old air bags, in case of accident, are known to fail at a rate of 23%. New air bags were tested on 230 cars and 10% of them failed. What is the probability that 10% of the 230 cars would have had failures with old bags?
I am not able to figure out what information is provided and what am I supposed to calculate like for the first piece of information, P(failure|old air bags) is given or P(failure, old air bags). How do you figure from sentences if conditional probability is given or probability of intersection of two things?
probability conditional-probability
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
$endgroup$
add a comment |
$begingroup$
I need help in solving the following question:
A company is working on new type of airbags for cars. The old air bags, in case of accident, are known to fail at a rate of 23%. New air bags were tested on 230 cars and 10% of them failed. What is the probability that 10% of the 230 cars would have had failures with old bags?
I am not able to figure out what information is provided and what am I supposed to calculate like for the first piece of information, P(failure|old air bags) is given or P(failure, old air bags). How do you figure from sentences if conditional probability is given or probability of intersection of two things?
probability conditional-probability
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
$endgroup$
I need help in solving the following question:
A company is working on new type of airbags for cars. The old air bags, in case of accident, are known to fail at a rate of 23%. New air bags were tested on 230 cars and 10% of them failed. What is the probability that 10% of the 230 cars would have had failures with old bags?
I am not able to figure out what information is provided and what am I supposed to calculate like for the first piece of information, P(failure|old air bags) is given or P(failure, old air bags). How do you figure from sentences if conditional probability is given or probability of intersection of two things?
probability conditional-probability
probability conditional-probability
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
asked Jan 24 at 22:40
SinisterSixSinisterSix
32
32
add a comment |
add a comment |
1 Answer
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You have been asked to find the probability that a count of 23 cars (among the 230) would have had failures when using old bags.
Hint: use binomial distribution as your model.
When X ~ Bin(230, 0.23), find P(X=23)
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
$endgroup$
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You have been asked to find the probability that a count of 23 cars (among the 230) would have had failures when using old bags.
Hint: use binomial distribution as your model.
When X ~ Bin(230, 0.23), find P(X=23)
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
$endgroup$
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
add a comment |
$begingroup$
You have been asked to find the probability that a count of 23 cars (among the 230) would have had failures when using old bags.
Hint: use binomial distribution as your model.
When X ~ Bin(230, 0.23), find P(X=23)
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
$endgroup$
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
add a comment |
$begingroup$
You have been asked to find the probability that a count of 23 cars (among the 230) would have had failures when using old bags.
Hint: use binomial distribution as your model.
When X ~ Bin(230, 0.23), find P(X=23)
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
$endgroup$
You have been asked to find the probability that a count of 23 cars (among the 230) would have had failures when using old bags.
Hint: use binomial distribution as your model.
When X ~ Bin(230, 0.23), find P(X=23)
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
answered Jan 24 at 22:53
Graham KempGraham Kemp
86.8k43579
86.8k43579
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
add a comment |
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
Thanks! So, "New air bags were tested on 230 cars and 10% of them failed" had no useful information in this case, right? I kept thinking that I had to find P(failure|old air bags, new air bags) or something like that.
$endgroup$
– SinisterSix
Jan 24 at 23:16
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
$begingroup$
It is just for comparison. You are basically asked to see how likely would the result of the test would have been if performed using the old bags .
$endgroup$
– Graham Kemp
Jan 24 at 23:46
add a comment |
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