Mixing
Getting first element of a JSON Array with Alamofire/SwiftyJSON
I have an Alamofire request, which gives me JSON as a result. Here is my JSON:
"user" : {
"field_first_name" : {
"und" : [
{
"value" : "Christopher",
"format" : null,
"safe_value" : "Christopher"
}
]
},
The "und" value is an array, which usually only has one value in it. I'd like to grab the first element of this array at all times, as occasionally this field will have multiple elements, but the first is always the correct result.
The code below works, until I get to the ".first". This returns a value of type (String, JSON) and I cannot figure out how to get this item "firstValue" back into usable format. Whenever I try to use
Alamofire.request(url, method: .post, parameters:parameters, headers: headers)
.responseJSON { response in
if let data = response.result.value {
let json = JSON(json: data)
let firstValue = json["user"]["field_first_name"]["und"].first
print(firstValue!)
}
}
firstValue then becomes of type (String, JSON) and I have no idea how to handle this. What I'd like to get is the value for key "value" out of "firstValue.
This is what "firstValue" prints out:
("0", {
"safe_value" : "Christopher",
"value" : "Christopher",
"format" : null
})
Is this approach salvageable? I could do a for in loop, get the first result, and tell it to ignore the rest, but that doesn't seem right. Thanks for any help.
json swift alamofire swifty-json
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
add a comment |
I have an Alamofire request, which gives me JSON as a result. Here is my JSON:
"user" : {
"field_first_name" : {
"und" : [
{
"value" : "Christopher",
"format" : null,
"safe_value" : "Christopher"
}
]
},
The "und" value is an array, which usually only has one value in it. I'd like to grab the first element of this array at all times, as occasionally this field will have multiple elements, but the first is always the correct result.
The code below works, until I get to the ".first". This returns a value of type (String, JSON) and I cannot figure out how to get this item "firstValue" back into usable format. Whenever I try to use
Alamofire.request(url, method: .post, parameters:parameters, headers: headers)
.responseJSON { response in
if let data = response.result.value {
let json = JSON(json: data)
let firstValue = json["user"]["field_first_name"]["und"].first
print(firstValue!)
}
}
firstValue then becomes of type (String, JSON) and I have no idea how to handle this. What I'd like to get is the value for key "value" out of "firstValue.
This is what "firstValue" prints out:
("0", {
"safe_value" : "Christopher",
"value" : "Christopher",
"format" : null
})
Is this approach salvageable? I could do a for in loop, get the first result, and tell it to ignore the rest, but that doesn't seem right. Thanks for any help.
json swift alamofire swifty-json
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
Try this answer, instead of using first use array and then first and let me know if it works
– carlos salzar
Jun 9 '17 at 16:19
I found a solution to this: firstValue is a tuple, of type (String, JSON), and I only need the second part of the tuple. So, if I do print(firstValue.1["value"]) it works
– cdeangelus
Jun 9 '17 at 18:01
add a comment |
I have an Alamofire request, which gives me JSON as a result. Here is my JSON:
"user" : {
"field_first_name" : {
"und" : [
{
"value" : "Christopher",
"format" : null,
"safe_value" : "Christopher"
}
]
},
The "und" value is an array, which usually only has one value in it. I'd like to grab the first element of this array at all times, as occasionally this field will have multiple elements, but the first is always the correct result.
The code below works, until I get to the ".first". This returns a value of type (String, JSON) and I cannot figure out how to get this item "firstValue" back into usable format. Whenever I try to use
Alamofire.request(url, method: .post, parameters:parameters, headers: headers)
.responseJSON { response in
if let data = response.result.value {
let json = JSON(json: data)
let firstValue = json["user"]["field_first_name"]["und"].first
print(firstValue!)
}
}
firstValue then becomes of type (String, JSON) and I have no idea how to handle this. What I'd like to get is the value for key "value" out of "firstValue.
This is what "firstValue" prints out:
("0", {
"safe_value" : "Christopher",
"value" : "Christopher",
"format" : null
})
Is this approach salvageable? I could do a for in loop, get the first result, and tell it to ignore the rest, but that doesn't seem right. Thanks for any help.
json swift alamofire swifty-json
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
I have an Alamofire request, which gives me JSON as a result. Here is my JSON:
"user" : {
"field_first_name" : {
"und" : [
{
"value" : "Christopher",
"format" : null,
"safe_value" : "Christopher"
}
]
},
The "und" value is an array, which usually only has one value in it. I'd like to grab the first element of this array at all times, as occasionally this field will have multiple elements, but the first is always the correct result.
The code below works, until I get to the ".first". This returns a value of type (String, JSON) and I cannot figure out how to get this item "firstValue" back into usable format. Whenever I try to use
Alamofire.request(url, method: .post, parameters:parameters, headers: headers)
.responseJSON { response in
if let data = response.result.value {
let json = JSON(json: data)
let firstValue = json["user"]["field_first_name"]["und"].first
print(firstValue!)
}
}
firstValue then becomes of type (String, JSON) and I have no idea how to handle this. What I'd like to get is the value for key "value" out of "firstValue.
This is what "firstValue" prints out:
("0", {
"safe_value" : "Christopher",
"value" : "Christopher",
"format" : null
})
Is this approach salvageable? I could do a for in loop, get the first result, and tell it to ignore the rest, but that doesn't seem right. Thanks for any help.
json swift alamofire swifty-json
json swift alamofire swifty-json
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
asked Jun 9 '17 at 14:29
cdeangeluscdeangelus
9114
9114
Try this answer, instead of using first use array and then first and let me know if it works
– carlos salzar
Jun 9 '17 at 16:19
I found a solution to this: firstValue is a tuple, of type (String, JSON), and I only need the second part of the tuple. So, if I do print(firstValue.1["value"]) it works
– cdeangelus
Jun 9 '17 at 18:01
add a comment |
Try this answer, instead of using first use array and then first and let me know if it works
– carlos salzar
Jun 9 '17 at 16:19
I found a solution to this: firstValue is a tuple, of type (String, JSON), and I only need the second part of the tuple. So, if I do print(firstValue.1["value"]) it works
– cdeangelus
Jun 9 '17 at 18:01
Try this answer, instead of using first use array and then first and let me know if it works
– carlos salzar
Jun 9 '17 at 16:19
Try this answer, instead of using first use array and then first and let me know if it works
– carlos salzar
Jun 9 '17 at 16:19
I found a solution to this: firstValue is a tuple, of type (String, JSON), and I only need the second part of the tuple. So, if I do print(firstValue.1["value"]) it works
– cdeangelus
Jun 9 '17 at 18:01
I found a solution to this: firstValue is a tuple, of type (String, JSON), and I only need the second part of the tuple. So, if I do print(firstValue.1["value"]) it works
– cdeangelus
Jun 9 '17 at 18:01
add a comment |
2 Answers
2
active
oldest
votes
I know this is over a year late, but this should work with your particular data. It's quite a long line of code though. I would break it up to make it more readable.
if let firstValue = json["user"]["field_first_name"] ["und"].arrayValue[0]["value"].string {
print(firstValue)
{
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
add a comment |
I believe you should be able to do something like this
if let firstValue = json["user"]["field_first_name"]["und"].first?.1 {
print(firstValue)
}
answered Jan 1 at 21:58
BrianBrian
858
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I know this is over a year late, but this should work with your particular data. It's quite a long line of code though. I would break it up to make it more readable.
if let firstValue = json["user"]["field_first_name"] ["und"].arrayValue[0]["value"].string {
print(firstValue)
{
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
add a comment |
I know this is over a year late, but this should work with your particular data. It's quite a long line of code though. I would break it up to make it more readable.
if let firstValue = json["user"]["field_first_name"] ["und"].arrayValue[0]["value"].string {
print(firstValue)
{
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
add a comment |
I know this is over a year late, but this should work with your particular data. It's quite a long line of code though. I would break it up to make it more readable.
if let firstValue = json["user"]["field_first_name"] ["und"].arrayValue[0]["value"].string {
print(firstValue)
{
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
I know this is over a year late, but this should work with your particular data. It's quite a long line of code though. I would break it up to make it more readable.
if let firstValue = json["user"]["field_first_name"] ["und"].arrayValue[0]["value"].string {
print(firstValue)
{
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
answered Oct 2 '18 at 16:26
skymookskymook
1,7962028
1,7962028
add a comment |
add a comment |
I believe you should be able to do something like this
if let firstValue = json["user"]["field_first_name"]["und"].first?.1 {
print(firstValue)
}
answered Jan 1 at 21:58
BrianBrian
858
add a comment |
I believe you should be able to do something like this
if let firstValue = json["user"]["field_first_name"]["und"].first?.1 {
print(firstValue)
}
answered Jan 1 at 21:58
BrianBrian
858
add a comment |
I believe you should be able to do something like this
if let firstValue = json["user"]["field_first_name"]["und"].first?.1 {
print(firstValue)
}
answered Jan 1 at 21:58
BrianBrian
858
I believe you should be able to do something like this
if let firstValue = json["user"]["field_first_name"]["und"].first?.1 {
print(firstValue)
}
answered Jan 1 at 21:58
BrianBrian
858
answered Jan 1 at 21:58
BrianBrian
858
answered Jan 1 at 21:58
BrianBrian
858
answered Jan 1 at 21:58
BrianBrian
858
858
add a comment |
add a comment |
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Try this answer, instead of using first use array and then first and let me know if it works
– carlos salzar
Jun 9 '17 at 16:19
I found a solution to this: firstValue is a tuple, of type (String, JSON), and I only need the second part of the tuple. So, if I do print(firstValue.1["value"]) it works
– cdeangelus
Jun 9 '17 at 18:01