How do I print elements of a list contained in a dictionary using a for loop












-1















I have a dictionary:



FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}


I want to print certain elements in a for loop:



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
for k in FFA:
print "FFA", k, elem[0], elem[1], elem[2]


That's my output:



 ROI Cope Mean Stddev Nsamples
FFA House 1.084 0.373 10
FFA Chair 1.084 0.373 10
FFA Shoe 1.084 0.373 10
FFA Bottle 1.084 0.373 10
FFA Face 1.084 0.373 10


However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.



I want my output to be:



ROI Cope Mean Stddev Nsamples
FFA House 0.511 0.374 10
FFA Chair 0.704 0.381 10
FFA Shoe 0.922 0.465 10
FFA Bottle 0.764 0.348 10
FFA Face 1.084 0.373 10









share|improve this question




















  • 2





    I'm really unclear on what your issue is or what you are trying to accomplish.

    – busybear
    Jan 2 at 18:24











  • All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

    – user10786574
    Jan 2 at 18:26











  • your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

    – Chris Doyle
    Jan 2 at 18:58











  • Do not continue vandalising your own questions

    – jonrsharpe
    Jan 4 at 10:14
















-1















I have a dictionary:



FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}


I want to print certain elements in a for loop:



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
for k in FFA:
print "FFA", k, elem[0], elem[1], elem[2]


That's my output:



 ROI Cope Mean Stddev Nsamples
FFA House 1.084 0.373 10
FFA Chair 1.084 0.373 10
FFA Shoe 1.084 0.373 10
FFA Bottle 1.084 0.373 10
FFA Face 1.084 0.373 10


However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.



I want my output to be:



ROI Cope Mean Stddev Nsamples
FFA House 0.511 0.374 10
FFA Chair 0.704 0.381 10
FFA Shoe 0.922 0.465 10
FFA Bottle 0.764 0.348 10
FFA Face 1.084 0.373 10









share|improve this question




















  • 2





    I'm really unclear on what your issue is or what you are trying to accomplish.

    – busybear
    Jan 2 at 18:24











  • All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

    – user10786574
    Jan 2 at 18:26











  • your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

    – Chris Doyle
    Jan 2 at 18:58











  • Do not continue vandalising your own questions

    – jonrsharpe
    Jan 4 at 10:14














-1












-1








-1








I have a dictionary:



FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}


I want to print certain elements in a for loop:



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
for k in FFA:
print "FFA", k, elem[0], elem[1], elem[2]


That's my output:



 ROI Cope Mean Stddev Nsamples
FFA House 1.084 0.373 10
FFA Chair 1.084 0.373 10
FFA Shoe 1.084 0.373 10
FFA Bottle 1.084 0.373 10
FFA Face 1.084 0.373 10


However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.



I want my output to be:



ROI Cope Mean Stddev Nsamples
FFA House 0.511 0.374 10
FFA Chair 0.704 0.381 10
FFA Shoe 0.922 0.465 10
FFA Bottle 0.764 0.348 10
FFA Face 1.084 0.373 10









share|improve this question
















I have a dictionary:



FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}


I want to print certain elements in a for loop:



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
for k in FFA:
print "FFA", k, elem[0], elem[1], elem[2]


That's my output:



 ROI Cope Mean Stddev Nsamples
FFA House 1.084 0.373 10
FFA Chair 1.084 0.373 10
FFA Shoe 1.084 0.373 10
FFA Bottle 1.084 0.373 10
FFA Face 1.084 0.373 10


However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.



I want my output to be:



ROI Cope Mean Stddev Nsamples
FFA House 0.511 0.374 10
FFA Chair 0.704 0.381 10
FFA Shoe 0.922 0.465 10
FFA Bottle 0.764 0.348 10
FFA Face 1.084 0.373 10






python python-2.7 dictionary for-loop






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 4 at 10:07









jonrsharpe

78.7k11110220




78.7k11110220










asked Jan 2 at 18:21







user10786574















  • 2





    I'm really unclear on what your issue is or what you are trying to accomplish.

    – busybear
    Jan 2 at 18:24











  • All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

    – user10786574
    Jan 2 at 18:26











  • your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

    – Chris Doyle
    Jan 2 at 18:58











  • Do not continue vandalising your own questions

    – jonrsharpe
    Jan 4 at 10:14














  • 2





    I'm really unclear on what your issue is or what you are trying to accomplish.

    – busybear
    Jan 2 at 18:24











  • All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

    – user10786574
    Jan 2 at 18:26











  • your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

    – Chris Doyle
    Jan 2 at 18:58











  • Do not continue vandalising your own questions

    – jonrsharpe
    Jan 4 at 10:14








2




2





I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24





I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24













All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26





All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26













your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58





your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58













Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14





Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14












3 Answers
3






active

oldest

votes


















2














You were close:



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
for k in FFA:
elem = FFA[k]
print "FFA", k, elem[0], elem[1], elem[2]


or directly:



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
for k in FFA:
print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]





share|improve this answer
























  • or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

    – juanpa.arrivillaga
    Jan 2 at 18:36



















1














Use items() to iterate over the keys and the values. Since you have multiple values, iterate over the values using the nested for loop over multiple values. For python 2.x it will be print "FFA", k, values,



print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header

for k, v in FFA.items():
# print ("FFA", k, end=" ") # For python 3.x
print "FFA", k,
for values in v:
print values,
# print (values, end=" ") # For python 3.x
print # To get to print to the new line
# print () # For python 3.x




ROI Cope Mean Stddev Nsamples
FFA House 0.511 0.374 10
FFA Chair 0.704 0.381 10
FFA Shoe 0.922 0.465 10
FFA Bottle 0.764 0.348 10
FFA Face 1.084 0.373 10





share|improve this answer


























  • remember to end the connecting lines after the for loop finished

    – GeeTransit
    Jan 2 at 18:26






  • 1





    @GeeTransit: I realized it and edited it. Thanks :)

    – Bazingaa
    Jan 2 at 18:27








  • 2





    does end="" work with python 2.7 ... doubt it

    – Patrick Artner
    Jan 2 at 18:27






  • 2





    @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

    – glibdud
    Jan 2 at 18:28






  • 2





    The syntax of the print instruction shows that OP uses Python 2

    – Serge Ballesta
    Jan 2 at 18:28



















0














You already loop over the keys, now you simply need to loop over the elements of the values:



FFA = {'House': ['0.511', '0.374', 10], 
'Chair': ['0.704', '0.381', 10],
'Shoe': ['0.922', '0.465', 10],
'Bottle': ['0.764', '0.348', 10],
'Face': ['1.084', '0.373', 10]}

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"


for k in FFA: # loop over keys in dict
print "FFA", k, # , at end == no newline
for elem in FFA[k]: # loop over values in list of key
print elem, # , at end == no newline
print # now a newline


Output:



ROI Cope Mean Stddev Nsamples
FFA House 0.511 0.374 10
FFA Chair 0.704 0.381 10
FFA Shoe 0.922 0.465 10
FFA Bottle 0.764 0.348 10





share|improve this answer
























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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    You were close:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    elem = FFA[k]
    print "FFA", k, elem[0], elem[1], elem[2]


    or directly:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]





    share|improve this answer
























    • or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

      – juanpa.arrivillaga
      Jan 2 at 18:36
















    2














    You were close:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    elem = FFA[k]
    print "FFA", k, elem[0], elem[1], elem[2]


    or directly:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]





    share|improve this answer
























    • or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

      – juanpa.arrivillaga
      Jan 2 at 18:36














    2












    2








    2







    You were close:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    elem = FFA[k]
    print "FFA", k, elem[0], elem[1], elem[2]


    or directly:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]





    share|improve this answer













    You were close:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    elem = FFA[k]
    print "FFA", k, elem[0], elem[1], elem[2]


    or directly:



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"
    for k in FFA:
    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jan 2 at 18:27









    Serge BallestaSerge Ballesta

    81.2k961133




    81.2k961133













    • or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

      – juanpa.arrivillaga
      Jan 2 at 18:36



















    • or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

      – juanpa.arrivillaga
      Jan 2 at 18:36

















    or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

    – juanpa.arrivillaga
    Jan 2 at 18:36





    or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

    – juanpa.arrivillaga
    Jan 2 at 18:36













    1














    Use items() to iterate over the keys and the values. Since you have multiple values, iterate over the values using the nested for loop over multiple values. For python 2.x it will be print "FFA", k, values,



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header

    for k, v in FFA.items():
    # print ("FFA", k, end=" ") # For python 3.x
    print "FFA", k,
    for values in v:
    print values,
    # print (values, end=" ") # For python 3.x
    print # To get to print to the new line
    # print () # For python 3.x




    ROI Cope Mean Stddev Nsamples
    FFA House 0.511 0.374 10
    FFA Chair 0.704 0.381 10
    FFA Shoe 0.922 0.465 10
    FFA Bottle 0.764 0.348 10
    FFA Face 1.084 0.373 10





    share|improve this answer


























    • remember to end the connecting lines after the for loop finished

      – GeeTransit
      Jan 2 at 18:26






    • 1





      @GeeTransit: I realized it and edited it. Thanks :)

      – Bazingaa
      Jan 2 at 18:27








    • 2





      does end="" work with python 2.7 ... doubt it

      – Patrick Artner
      Jan 2 at 18:27






    • 2





      @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

      – glibdud
      Jan 2 at 18:28






    • 2





      The syntax of the print instruction shows that OP uses Python 2

      – Serge Ballesta
      Jan 2 at 18:28
















    1














    Use items() to iterate over the keys and the values. Since you have multiple values, iterate over the values using the nested for loop over multiple values. For python 2.x it will be print "FFA", k, values,



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header

    for k, v in FFA.items():
    # print ("FFA", k, end=" ") # For python 3.x
    print "FFA", k,
    for values in v:
    print values,
    # print (values, end=" ") # For python 3.x
    print # To get to print to the new line
    # print () # For python 3.x




    ROI Cope Mean Stddev Nsamples
    FFA House 0.511 0.374 10
    FFA Chair 0.704 0.381 10
    FFA Shoe 0.922 0.465 10
    FFA Bottle 0.764 0.348 10
    FFA Face 1.084 0.373 10





    share|improve this answer


























    • remember to end the connecting lines after the for loop finished

      – GeeTransit
      Jan 2 at 18:26






    • 1





      @GeeTransit: I realized it and edited it. Thanks :)

      – Bazingaa
      Jan 2 at 18:27








    • 2





      does end="" work with python 2.7 ... doubt it

      – Patrick Artner
      Jan 2 at 18:27






    • 2





      @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

      – glibdud
      Jan 2 at 18:28






    • 2





      The syntax of the print instruction shows that OP uses Python 2

      – Serge Ballesta
      Jan 2 at 18:28














    1












    1








    1







    Use items() to iterate over the keys and the values. Since you have multiple values, iterate over the values using the nested for loop over multiple values. For python 2.x it will be print "FFA", k, values,



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header

    for k, v in FFA.items():
    # print ("FFA", k, end=" ") # For python 3.x
    print "FFA", k,
    for values in v:
    print values,
    # print (values, end=" ") # For python 3.x
    print # To get to print to the new line
    # print () # For python 3.x




    ROI Cope Mean Stddev Nsamples
    FFA House 0.511 0.374 10
    FFA Chair 0.704 0.381 10
    FFA Shoe 0.922 0.465 10
    FFA Bottle 0.764 0.348 10
    FFA Face 1.084 0.373 10





    share|improve this answer















    Use items() to iterate over the keys and the values. Since you have multiple values, iterate over the values using the nested for loop over multiple values. For python 2.x it will be print "FFA", k, values,



    print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header

    for k, v in FFA.items():
    # print ("FFA", k, end=" ") # For python 3.x
    print "FFA", k,
    for values in v:
    print values,
    # print (values, end=" ") # For python 3.x
    print # To get to print to the new line
    # print () # For python 3.x




    ROI Cope Mean Stddev Nsamples
    FFA House 0.511 0.374 10
    FFA Chair 0.704 0.381 10
    FFA Shoe 0.922 0.465 10
    FFA Bottle 0.764 0.348 10
    FFA Face 1.084 0.373 10






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 2 at 18:41

























    answered Jan 2 at 18:24









    BazingaaBazingaa

    15.2k21330




    15.2k21330













    • remember to end the connecting lines after the for loop finished

      – GeeTransit
      Jan 2 at 18:26






    • 1





      @GeeTransit: I realized it and edited it. Thanks :)

      – Bazingaa
      Jan 2 at 18:27








    • 2





      does end="" work with python 2.7 ... doubt it

      – Patrick Artner
      Jan 2 at 18:27






    • 2





      @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

      – glibdud
      Jan 2 at 18:28






    • 2





      The syntax of the print instruction shows that OP uses Python 2

      – Serge Ballesta
      Jan 2 at 18:28



















    • remember to end the connecting lines after the for loop finished

      – GeeTransit
      Jan 2 at 18:26






    • 1





      @GeeTransit: I realized it and edited it. Thanks :)

      – Bazingaa
      Jan 2 at 18:27








    • 2





      does end="" work with python 2.7 ... doubt it

      – Patrick Artner
      Jan 2 at 18:27






    • 2





      @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

      – glibdud
      Jan 2 at 18:28






    • 2





      The syntax of the print instruction shows that OP uses Python 2

      – Serge Ballesta
      Jan 2 at 18:28

















    remember to end the connecting lines after the for loop finished

    – GeeTransit
    Jan 2 at 18:26





    remember to end the connecting lines after the for loop finished

    – GeeTransit
    Jan 2 at 18:26




    1




    1





    @GeeTransit: I realized it and edited it. Thanks :)

    – Bazingaa
    Jan 2 at 18:27







    @GeeTransit: I realized it and edited it. Thanks :)

    – Bazingaa
    Jan 2 at 18:27






    2




    2





    does end="" work with python 2.7 ... doubt it

    – Patrick Artner
    Jan 2 at 18:27





    does end="" work with python 2.7 ... doubt it

    – Patrick Artner
    Jan 2 at 18:27




    2




    2





    @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

    – glibdud
    Jan 2 at 18:28





    @Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

    – glibdud
    Jan 2 at 18:28




    2




    2





    The syntax of the print instruction shows that OP uses Python 2

    – Serge Ballesta
    Jan 2 at 18:28





    The syntax of the print instruction shows that OP uses Python 2

    – Serge Ballesta
    Jan 2 at 18:28











    0














    You already loop over the keys, now you simply need to loop over the elements of the values:



    FFA = {'House': ['0.511', '0.374', 10], 
    'Chair': ['0.704', '0.381', 10],
    'Shoe': ['0.922', '0.465', 10],
    'Bottle': ['0.764', '0.348', 10],
    'Face': ['1.084', '0.373', 10]}

    print "ROI", "Cope", "Mean", "Stddev", "Nsamples"


    for k in FFA: # loop over keys in dict
    print "FFA", k, # , at end == no newline
    for elem in FFA[k]: # loop over values in list of key
    print elem, # , at end == no newline
    print # now a newline


    Output:



    ROI Cope Mean Stddev Nsamples
    FFA House 0.511 0.374 10
    FFA Chair 0.704 0.381 10
    FFA Shoe 0.922 0.465 10
    FFA Bottle 0.764 0.348 10





    share|improve this answer




























      0














      You already loop over the keys, now you simply need to loop over the elements of the values:



      FFA = {'House': ['0.511', '0.374', 10], 
      'Chair': ['0.704', '0.381', 10],
      'Shoe': ['0.922', '0.465', 10],
      'Bottle': ['0.764', '0.348', 10],
      'Face': ['1.084', '0.373', 10]}

      print "ROI", "Cope", "Mean", "Stddev", "Nsamples"


      for k in FFA: # loop over keys in dict
      print "FFA", k, # , at end == no newline
      for elem in FFA[k]: # loop over values in list of key
      print elem, # , at end == no newline
      print # now a newline


      Output:



      ROI Cope Mean Stddev Nsamples
      FFA House 0.511 0.374 10
      FFA Chair 0.704 0.381 10
      FFA Shoe 0.922 0.465 10
      FFA Bottle 0.764 0.348 10





      share|improve this answer


























        0












        0








        0







        You already loop over the keys, now you simply need to loop over the elements of the values:



        FFA = {'House': ['0.511', '0.374', 10], 
        'Chair': ['0.704', '0.381', 10],
        'Shoe': ['0.922', '0.465', 10],
        'Bottle': ['0.764', '0.348', 10],
        'Face': ['1.084', '0.373', 10]}

        print "ROI", "Cope", "Mean", "Stddev", "Nsamples"


        for k in FFA: # loop over keys in dict
        print "FFA", k, # , at end == no newline
        for elem in FFA[k]: # loop over values in list of key
        print elem, # , at end == no newline
        print # now a newline


        Output:



        ROI Cope Mean Stddev Nsamples
        FFA House 0.511 0.374 10
        FFA Chair 0.704 0.381 10
        FFA Shoe 0.922 0.465 10
        FFA Bottle 0.764 0.348 10





        share|improve this answer













        You already loop over the keys, now you simply need to loop over the elements of the values:



        FFA = {'House': ['0.511', '0.374', 10], 
        'Chair': ['0.704', '0.381', 10],
        'Shoe': ['0.922', '0.465', 10],
        'Bottle': ['0.764', '0.348', 10],
        'Face': ['1.084', '0.373', 10]}

        print "ROI", "Cope", "Mean", "Stddev", "Nsamples"


        for k in FFA: # loop over keys in dict
        print "FFA", k, # , at end == no newline
        for elem in FFA[k]: # loop over values in list of key
        print elem, # , at end == no newline
        print # now a newline


        Output:



        ROI Cope Mean Stddev Nsamples
        FFA House 0.511 0.374 10
        FFA Chair 0.704 0.381 10
        FFA Shoe 0.922 0.465 10
        FFA Bottle 0.764 0.348 10






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 2 at 18:28









        Patrick ArtnerPatrick Artner

        25.9k62544




        25.9k62544






























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