How do I print elements of a list contained in a dictionary using a for loop

-1

I have a dictionary:

FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}

I want to print certain elements in a for loop:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, elem[0], elem[1], elem[2]

That's my output:

 ROI Cope Mean Stddev Nsamples

FFA House 1.084 0.373 10

FFA Chair 1.084 0.373 10

FFA Shoe 1.084 0.373 10

FFA Bottle 1.084 0.373 10

FFA Face 1.084 0.373 10

However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.

I want my output to be:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe  0.922 0.465 10

FFA Bottle 0.764 0.348 10

FFA Face 1.084 0.373 10

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

asked Jan 2 at 18:21

user10786574

2

I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24

All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26

your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58

Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14

add a comment |

-1

I have a dictionary:

FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}

I want to print certain elements in a for loop:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, elem[0], elem[1], elem[2]

That's my output:

 ROI Cope Mean Stddev Nsamples

FFA House 1.084 0.373 10

FFA Chair 1.084 0.373 10

FFA Shoe 1.084 0.373 10

FFA Bottle 1.084 0.373 10

FFA Face 1.084 0.373 10

However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.

I want my output to be:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe  0.922 0.465 10

FFA Bottle 0.764 0.348 10

FFA Face 1.084 0.373 10

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

asked Jan 2 at 18:21

user10786574

2

I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24

All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26

your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58

Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14

add a comment |

-1

I have a dictionary:

FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}

I want to print certain elements in a for loop:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, elem[0], elem[1], elem[2]

That's my output:

 ROI Cope Mean Stddev Nsamples

FFA House 1.084 0.373 10

FFA Chair 1.084 0.373 10

FFA Shoe 1.084 0.373 10

FFA Bottle 1.084 0.373 10

FFA Face 1.084 0.373 10

However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.

I want my output to be:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe  0.922 0.465 10

FFA Bottle 0.764 0.348 10

FFA Face 1.084 0.373 10

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

asked Jan 2 at 18:21

user10786574

I have a dictionary:

FFA = {'House': ['0.511', '0.374', 10], 'Chair': ['0.704', '0.381', 10], 'Shoe': ['0.922', '0.465', 10], 'Bottle': ['0.764', '0.348', 10], 'Face': ['1.084', '0.373', 10]}

I want to print certain elements in a for loop:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, elem[0], elem[1], elem[2]

That's my output:

 ROI Cope Mean Stddev Nsamples

FFA House 1.084 0.373 10

FFA Chair 1.084 0.373 10

FFA Shoe 1.084 0.373 10

FFA Bottle 1.084 0.373 10

FFA Face 1.084 0.373 10

However, my code is so wrong I can't find a way of iterating over all the keys in the dic so the right values are printed out.

I want my output to be:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe  0.922 0.465 10

FFA Bottle 0.764 0.348 10

FFA Face 1.084 0.373 10

python python-2.7 dictionary for-loop

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

asked Jan 2 at 18:21

user10786574

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

asked Jan 2 at 18:21

user10786574

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

edited Jan 4 at 10:07

jonrsharpe

78.7k11110220

asked Jan 2 at 18:21

user10786574

asked Jan 2 at 18:21

user10786574

asked Jan 2 at 18:21

user10786574

2

I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24

All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26

your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58

Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14

add a comment |

2

I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24

All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26

your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58

Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14

I'm really unclear on what your issue is or what you are trying to accomplish.

– busybear
Jan 2 at 18:24

All the values of Face were printed out as for the other keys (House, Chair, Shoe and Bottle)

– user10786574
Jan 2 at 18:26

your code is unclear. you are referring to elements indexed from a list called elem yet you have no reference to this list in your question. what does elem contain and how is it populated.

– Chris Doyle
Jan 2 at 18:58

Do not continue vandalising your own questions

– jonrsharpe
Jan 4 at 10:14

add a comment |

3 Answers
3

active

oldest

votes

You were close:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    elem = FFA[k]

    print "FFA", k, elem[0], elem[1], elem[2]

or directly:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

– juanpa.arrivillaga
Jan 2 at 18:36

add a comment |

Use items() to iterate over the keys and the values. Since you have multiple values, iterate over the values using the nested for loop over multiple values. For python 2.x it will be print "FFA", k, values,

print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header



for k, v in FFA.items():

    # print ("FFA", k,  end=" ") # For python 3.x

    print "FFA", k,

    for values in v:

        print values,

        # print (values, end=" ") # For python 3.x

    print # To get to print to the new line

    # print ()  # For python 3.x

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10 

FFA Chair 0.704 0.381 10 

FFA Shoe 0.922 0.465 10 

FFA Bottle 0.764 0.348 10 

FFA Face 1.084 0.373 10

edited Jan 2 at 18:41

answered Jan 2 at 18:24

Bazingaa

15.2k21330

remember to end the connecting lines after the for loop finished

– GeeTransit
Jan 2 at 18:26

1

@GeeTransit: I realized it and edited it. Thanks :)

– Bazingaa
Jan 2 at 18:27

2

does end="" work with python 2.7 ... doubt it

– Patrick Artner
Jan 2 at 18:27

2

@Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

– glibdud
Jan 2 at 18:28

2

The syntax of the print instruction shows that OP uses Python 2

– Serge Ballesta
Jan 2 at 18:28

|
show 7 more comments

You already loop over the keys, now you simply need to loop over the elements of the values:

FFA = {'House': ['0.511', '0.374', 10], 

       'Chair': ['0.704', '0.381', 10], 

       'Shoe': ['0.922', '0.465', 10], 

       'Bottle': ['0.764', '0.348', 10], 

      'Face': ['1.084', '0.373', 10]} 



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"





for k in FFA:      # loop over keys in dict 

    print "FFA", k,     # , at end == no newline

    for elem in FFA[k]: # loop over values in list of key

        print elem,         # , at end == no newline

    print               # now a newline

Output:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe 0.922 0.465 10

FFA Bottle 0.764 0.348 10

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You were close:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    elem = FFA[k]

    print "FFA", k, elem[0], elem[1], elem[2]

or directly:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

– juanpa.arrivillaga
Jan 2 at 18:36

add a comment |

You were close:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    elem = FFA[k]

    print "FFA", k, elem[0], elem[1], elem[2]

or directly:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

– juanpa.arrivillaga
Jan 2 at 18:36

add a comment |

You were close:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    elem = FFA[k]

    print "FFA", k, elem[0], elem[1], elem[2]

or directly:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

You were close:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    elem = FFA[k]

    print "FFA", k, elem[0], elem[1], elem[2]

or directly:

print "ROI", "Cope", "Mean", "Stddev", "Nsamples"

for k in FFA:

    print "FFA", k, FFA[k][0], FFA[k][1], FFA[k][2]

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

answered Jan 2 at 18:27

Serge Ballesta

81.2k961133

or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

– juanpa.arrivillaga
Jan 2 at 18:36

add a comment |

or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

– juanpa.arrivillaga
Jan 2 at 18:36

or just add elem = FFA[k]. Or use .items(), obviously, but I think it is instructive to show them this way

– juanpa.arrivillaga
Jan 2 at 18:36

add a comment |

print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header



for k, v in FFA.items():

    # print ("FFA", k,  end=" ") # For python 3.x

    print "FFA", k,

    for values in v:

        print values,

        # print (values, end=" ") # For python 3.x

    print # To get to print to the new line

    # print ()  # For python 3.x

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10 

FFA Chair 0.704 0.381 10 

FFA Shoe 0.922 0.465 10 

FFA Bottle 0.764 0.348 10 

FFA Face 1.084 0.373 10

edited Jan 2 at 18:41

answered Jan 2 at 18:24

Bazingaa

15.2k21330

remember to end the connecting lines after the for loop finished

– GeeTransit
Jan 2 at 18:26

1

@GeeTransit: I realized it and edited it. Thanks :)

– Bazingaa
Jan 2 at 18:27

2

does end="" work with python 2.7 ... doubt it

– Patrick Artner
Jan 2 at 18:27

2

@Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

– glibdud
Jan 2 at 18:28

2

The syntax of the print instruction shows that OP uses Python 2

– Serge Ballesta
Jan 2 at 18:28

|
show 7 more comments

print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header



for k, v in FFA.items():

    # print ("FFA", k,  end=" ") # For python 3.x

    print "FFA", k,

    for values in v:

        print values,

        # print (values, end=" ") # For python 3.x

    print # To get to print to the new line

    # print ()  # For python 3.x

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10 

FFA Chair 0.704 0.381 10 

FFA Shoe 0.922 0.465 10 

FFA Bottle 0.764 0.348 10 

FFA Face 1.084 0.373 10

edited Jan 2 at 18:41

answered Jan 2 at 18:24

Bazingaa

15.2k21330

remember to end the connecting lines after the for loop finished

– GeeTransit
Jan 2 at 18:26

1

@GeeTransit: I realized it and edited it. Thanks :)

– Bazingaa
Jan 2 at 18:27

2

does end="" work with python 2.7 ... doubt it

– Patrick Artner
Jan 2 at 18:27

2

@Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

– glibdud
Jan 2 at 18:28

2

The syntax of the print instruction shows that OP uses Python 2

– Serge Ballesta
Jan 2 at 18:28

|
show 7 more comments

print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header



for k, v in FFA.items():

    # print ("FFA", k,  end=" ") # For python 3.x

    print "FFA", k,

    for values in v:

        print values,

        # print (values, end=" ") # For python 3.x

    print # To get to print to the new line

    # print ()  # For python 3.x

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10 

FFA Chair 0.704 0.381 10 

FFA Shoe 0.922 0.465 10 

FFA Bottle 0.764 0.348 10 

FFA Face 1.084 0.373 10

edited Jan 2 at 18:41

answered Jan 2 at 18:24

Bazingaa

15.2k21330

print "ROI", "Cope", "Mean", "Stddev", "Nsamples" # Header



for k, v in FFA.items():

    # print ("FFA", k,  end=" ") # For python 3.x

    print "FFA", k,

    for values in v:

        print values,

        # print (values, end=" ") # For python 3.x

    print # To get to print to the new line

    # print ()  # For python 3.x

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10 

FFA Chair 0.704 0.381 10 

FFA Shoe 0.922 0.465 10 

FFA Bottle 0.764 0.348 10 

FFA Face 1.084 0.373 10

edited Jan 2 at 18:41

answered Jan 2 at 18:24

Bazingaa

15.2k21330

edited Jan 2 at 18:41

answered Jan 2 at 18:24

Bazingaa

15.2k21330

answered Jan 2 at 18:24

Bazingaa

15.2k21330

answered Jan 2 at 18:24

Bazingaa

15.2k21330

remember to end the connecting lines after the for loop finished

– GeeTransit
Jan 2 at 18:26

1

@GeeTransit: I realized it and edited it. Thanks :)

– Bazingaa
Jan 2 at 18:27

2

does end="" work with python 2.7 ... doubt it

– Patrick Artner
Jan 2 at 18:27

2

@Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

– glibdud
Jan 2 at 18:28

2

The syntax of the print instruction shows that OP uses Python 2

– Serge Ballesta
Jan 2 at 18:28

|
show 7 more comments

remember to end the connecting lines after the for loop finished

– GeeTransit
Jan 2 at 18:26

1

@GeeTransit: I realized it and edited it. Thanks :)

– Bazingaa
Jan 2 at 18:27

2

does end="" work with python 2.7 ... doubt it

– Patrick Artner
Jan 2 at 18:27

2

@Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

– glibdud
Jan 2 at 18:28

2

The syntax of the print instruction shows that OP uses Python 2

– Serge Ballesta
Jan 2 at 18:28

remember to end the connecting lines after the for loop finished

– GeeTransit
Jan 2 at 18:26

@GeeTransit: I realized it and edited it. Thanks :)

– Bazingaa
Jan 2 at 18:27

does end="" work with python 2.7 ... doubt it

– Patrick Artner
Jan 2 at 18:27

@Bazingaa Judging from the print statement in the asker's code, I'd say python 2 is accurate.

– glibdud
Jan 2 at 18:28

The syntax of the print instruction shows that OP uses Python 2

– Serge Ballesta
Jan 2 at 18:28

|
show 7 more comments

You already loop over the keys, now you simply need to loop over the elements of the values:

FFA = {'House': ['0.511', '0.374', 10], 

       'Chair': ['0.704', '0.381', 10], 

       'Shoe': ['0.922', '0.465', 10], 

       'Bottle': ['0.764', '0.348', 10], 

      'Face': ['1.084', '0.373', 10]} 



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"





for k in FFA:      # loop over keys in dict 

    print "FFA", k,     # , at end == no newline

    for elem in FFA[k]: # loop over values in list of key

        print elem,         # , at end == no newline

    print               # now a newline

Output:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe 0.922 0.465 10

FFA Bottle 0.764 0.348 10

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

add a comment |

You already loop over the keys, now you simply need to loop over the elements of the values:

FFA = {'House': ['0.511', '0.374', 10], 

       'Chair': ['0.704', '0.381', 10], 

       'Shoe': ['0.922', '0.465', 10], 

       'Bottle': ['0.764', '0.348', 10], 

      'Face': ['1.084', '0.373', 10]} 



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"





for k in FFA:      # loop over keys in dict 

    print "FFA", k,     # , at end == no newline

    for elem in FFA[k]: # loop over values in list of key

        print elem,         # , at end == no newline

    print               # now a newline

Output:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe 0.922 0.465 10

FFA Bottle 0.764 0.348 10

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

add a comment |

You already loop over the keys, now you simply need to loop over the elements of the values:

FFA = {'House': ['0.511', '0.374', 10], 

       'Chair': ['0.704', '0.381', 10], 

       'Shoe': ['0.922', '0.465', 10], 

       'Bottle': ['0.764', '0.348', 10], 

      'Face': ['1.084', '0.373', 10]} 



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"





for k in FFA:      # loop over keys in dict 

    print "FFA", k,     # , at end == no newline

    for elem in FFA[k]: # loop over values in list of key

        print elem,         # , at end == no newline

    print               # now a newline

Output:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe 0.922 0.465 10

FFA Bottle 0.764 0.348 10

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

You already loop over the keys, now you simply need to loop over the elements of the values:

FFA = {'House': ['0.511', '0.374', 10], 

       'Chair': ['0.704', '0.381', 10], 

       'Shoe': ['0.922', '0.465', 10], 

       'Bottle': ['0.764', '0.348', 10], 

      'Face': ['1.084', '0.373', 10]} 



print "ROI", "Cope", "Mean", "Stddev", "Nsamples"





for k in FFA:      # loop over keys in dict 

    print "FFA", k,     # , at end == no newline

    for elem in FFA[k]: # loop over values in list of key

        print elem,         # , at end == no newline

    print               # now a newline

Output:

ROI Cope Mean Stddev Nsamples

FFA House 0.511 0.374 10

FFA Chair 0.704 0.381 10

FFA Shoe 0.922 0.465 10

FFA Bottle 0.764 0.348 10

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

answered Jan 2 at 18:28

Patrick Artner

25.9k62544

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