Mixing
Sequence term and series
$begingroup$
- Generate the first five terms of the sequence given as 4n - 3
- Find the tenth term of each of these sequences :
A) 7n +1
B) 10 - 2n
C) n squared - 3n
sequences-and-series
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
$endgroup$
add a comment |
$begingroup$
- Generate the first five terms of the sequence given as 4n - 3
- Find the tenth term of each of these sequences :
A) 7n +1
B) 10 - 2n
C) n squared - 3n
sequences-and-series
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
$endgroup$
$begingroup$
Welcome to MSE. Your post would be easier to read if you used Mathjax
$endgroup$
– J. W. Tanner
Jan 28 at 22:04
add a comment |
$begingroup$
- Generate the first five terms of the sequence given as 4n - 3
- Find the tenth term of each of these sequences :
A) 7n +1
B) 10 - 2n
C) n squared - 3n
sequences-and-series
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
$endgroup$
- Generate the first five terms of the sequence given as 4n - 3
- Find the tenth term of each of these sequences :
A) 7n +1
B) 10 - 2n
C) n squared - 3n
sequences-and-series
sequences-and-series
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
asked Jan 28 at 20:10
Pewdiepie_fanPewdiepie_fan
41
41
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Welcome to MSE. Your post would be easier to read if you used Mathjax
$endgroup$
– J. W. Tanner
Jan 28 at 22:04
add a comment |
$begingroup$
Welcome to MSE. Your post would be easier to read if you used Mathjax
$endgroup$
– J. W. Tanner
Jan 28 at 22:04
$begingroup$
Welcome to MSE. Your post would be easier to read if you used Mathjax
$endgroup$
– J. W. Tanner
Jan 28 at 22:04
$begingroup$
Welcome to MSE. Your post would be easier to read if you used Mathjax
$endgroup$
– J. W. Tanner
Jan 28 at 22:04
add a comment |
1 Answer
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$begingroup$
Here you replaced the value of n with 1,2,3,4 and 5
So the first 5 terms would be 1,5,9,13,17
For the second question you have to put n=10 for each one.
So a) $$7*10+1 = 71 $$
b)$$10-2*10=-10$$
c) $$10^2-3*10=70$$
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Here you replaced the value of n with 1,2,3,4 and 5
So the first 5 terms would be 1,5,9,13,17
For the second question you have to put n=10 for each one.
So a) $$7*10+1 = 71 $$
b)$$10-2*10=-10$$
c) $$10^2-3*10=70$$
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
$endgroup$
add a comment |
$begingroup$
Here you replaced the value of n with 1,2,3,4 and 5
So the first 5 terms would be 1,5,9,13,17
For the second question you have to put n=10 for each one.
So a) $$7*10+1 = 71 $$
b)$$10-2*10=-10$$
c) $$10^2-3*10=70$$
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
$endgroup$
add a comment |
$begingroup$
Here you replaced the value of n with 1,2,3,4 and 5
So the first 5 terms would be 1,5,9,13,17
For the second question you have to put n=10 for each one.
So a) $$7*10+1 = 71 $$
b)$$10-2*10=-10$$
c) $$10^2-3*10=70$$
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
$endgroup$
Here you replaced the value of n with 1,2,3,4 and 5
So the first 5 terms would be 1,5,9,13,17
For the second question you have to put n=10 for each one.
So a) $$7*10+1 = 71 $$
b)$$10-2*10=-10$$
c) $$10^2-3*10=70$$
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
answered Jan 28 at 20:14
Neo DarwinNeo Darwin
1194
1194
add a comment |
add a comment |
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$begingroup$
Welcome to MSE. Your post would be easier to read if you used Mathjax
$endgroup$
– J. W. Tanner
Jan 28 at 22:04