find vector equation of a hyperplane in $mathbb R^4$ from scalar equation












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How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$



I know I need to find 3 vectors and another vector that shifts from the origin in the form
$$rvec{a}+svec{b}+tvec{c}+vec{d}$$










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    0












    $begingroup$


    How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$



    I know I need to find 3 vectors and another vector that shifts from the origin in the form
    $$rvec{a}+svec{b}+tvec{c}+vec{d}$$










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$



      I know I need to find 3 vectors and another vector that shifts from the origin in the form
      $$rvec{a}+svec{b}+tvec{c}+vec{d}$$










      share|cite|improve this question











      $endgroup$




      How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$



      I know I need to find 3 vectors and another vector that shifts from the origin in the form
      $$rvec{a}+svec{b}+tvec{c}+vec{d}$$







      linear-algebra vectors






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      share|cite|improve this question













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      share|cite|improve this question








      edited Jan 28 at 20:32









      J. W. Tanner

      4,0461320




      4,0461320










      asked Jan 28 at 19:34









      Jerry W.Jerry W.

      535




      535






















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          $begingroup$

          Hint: Take $x_1,x_3,x_4$ to be free variables. Then,



          $$x_1=x_1$$



          $$x_2=5-3x_1+2x_3-4x_4$$



          $$x_3=x_3$$



          $$x_4=x_4$$



          Now write this in vector notation.






          share|cite|improve this answer









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            1 Answer
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            1 Answer
            1






            active

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            active

            oldest

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            active

            oldest

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            0












            $begingroup$

            Hint: Take $x_1,x_3,x_4$ to be free variables. Then,



            $$x_1=x_1$$



            $$x_2=5-3x_1+2x_3-4x_4$$



            $$x_3=x_3$$



            $$x_4=x_4$$



            Now write this in vector notation.






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              Hint: Take $x_1,x_3,x_4$ to be free variables. Then,



              $$x_1=x_1$$



              $$x_2=5-3x_1+2x_3-4x_4$$



              $$x_3=x_3$$



              $$x_4=x_4$$



              Now write this in vector notation.






              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                Hint: Take $x_1,x_3,x_4$ to be free variables. Then,



                $$x_1=x_1$$



                $$x_2=5-3x_1+2x_3-4x_4$$



                $$x_3=x_3$$



                $$x_4=x_4$$



                Now write this in vector notation.






                share|cite|improve this answer









                $endgroup$



                Hint: Take $x_1,x_3,x_4$ to be free variables. Then,



                $$x_1=x_1$$



                $$x_2=5-3x_1+2x_3-4x_4$$



                $$x_3=x_3$$



                $$x_4=x_4$$



                Now write this in vector notation.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 28 at 19:39









                Ahmed S. AttaallaAhmed S. Attaalla

                14.9k12151




                14.9k12151






























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