find vector equation of a hyperplane in $mathbb R^4$ from scalar equation
$begingroup$
How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$
I know I need to find 3 vectors and another vector that shifts from the origin in the form
$$rvec{a}+svec{b}+tvec{c}+vec{d}$$
linear-algebra vectors
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add a comment |
$begingroup$
How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$
I know I need to find 3 vectors and another vector that shifts from the origin in the form
$$rvec{a}+svec{b}+tvec{c}+vec{d}$$
linear-algebra vectors
$endgroup$
add a comment |
$begingroup$
How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$
I know I need to find 3 vectors and another vector that shifts from the origin in the form
$$rvec{a}+svec{b}+tvec{c}+vec{d}$$
linear-algebra vectors
$endgroup$
How would I go about finding a vector equation of a hyperplane $$3x_1+x_2-2x_3+4x_4=5$$
I know I need to find 3 vectors and another vector that shifts from the origin in the form
$$rvec{a}+svec{b}+tvec{c}+vec{d}$$
linear-algebra vectors
linear-algebra vectors
edited Jan 28 at 20:32
J. W. Tanner
4,0461320
4,0461320
asked Jan 28 at 19:34
Jerry W.Jerry W.
535
535
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1 Answer
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$begingroup$
Hint: Take $x_1,x_3,x_4$ to be free variables. Then,
$$x_1=x_1$$
$$x_2=5-3x_1+2x_3-4x_4$$
$$x_3=x_3$$
$$x_4=x_4$$
Now write this in vector notation.
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint: Take $x_1,x_3,x_4$ to be free variables. Then,
$$x_1=x_1$$
$$x_2=5-3x_1+2x_3-4x_4$$
$$x_3=x_3$$
$$x_4=x_4$$
Now write this in vector notation.
$endgroup$
add a comment |
$begingroup$
Hint: Take $x_1,x_3,x_4$ to be free variables. Then,
$$x_1=x_1$$
$$x_2=5-3x_1+2x_3-4x_4$$
$$x_3=x_3$$
$$x_4=x_4$$
Now write this in vector notation.
$endgroup$
add a comment |
$begingroup$
Hint: Take $x_1,x_3,x_4$ to be free variables. Then,
$$x_1=x_1$$
$$x_2=5-3x_1+2x_3-4x_4$$
$$x_3=x_3$$
$$x_4=x_4$$
Now write this in vector notation.
$endgroup$
Hint: Take $x_1,x_3,x_4$ to be free variables. Then,
$$x_1=x_1$$
$$x_2=5-3x_1+2x_3-4x_4$$
$$x_3=x_3$$
$$x_4=x_4$$
Now write this in vector notation.
answered Jan 28 at 19:39
Ahmed S. AttaallaAhmed S. Attaalla
14.9k12151
14.9k12151
add a comment |
add a comment |
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