Mixing
How to click a random link from google search results through Selenium and Python
0
Currently using Selenium+ Python and this code:
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("how to search the internet")
search.send_keys(Keys.RETURN) # hit return after you enter search text
time.sleep(5) # sleep for 5 seconds so you can see the results
browser.execute_script("window.scrollTo(0, 873)")
time.sleep(2)
browser.find_element(By.XPATH, '(//h3)[3]/a').click()`
as my code.
What Happens: Goes to Google and types in the words and hits search. Scrolls down a bit and then it clicks the first link
What I want: I want to be able to click a random link from the search result page
How to do this?
Edit: This is what I meant when I said unnecessary:
Unnecessary 1: https://imgur.com/a/70qz89x
Unnecessary 2: https://imgur.com/a/8WWvcnC
These are the only results I want:
This: https://imgur.com/a/eTatFV9
python selenium selenium-webdriver xpath webdriver
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
add a comment |
0
Currently using Selenium+ Python and this code:
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("how to search the internet")
search.send_keys(Keys.RETURN) # hit return after you enter search text
time.sleep(5) # sleep for 5 seconds so you can see the results
browser.execute_script("window.scrollTo(0, 873)")
time.sleep(2)
browser.find_element(By.XPATH, '(//h3)[3]/a').click()`
as my code.
What Happens: Goes to Google and types in the words and hits search. Scrolls down a bit and then it clicks the first link
What I want: I want to be able to click a random link from the search result page
How to do this?
Edit: This is what I meant when I said unnecessary:
Unnecessary 1: https://imgur.com/a/70qz89x
Unnecessary 2: https://imgur.com/a/8WWvcnC
These are the only results I want:
This: https://imgur.com/a/eTatFV9
python selenium selenium-webdriver xpath webdriver
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
1
You'll need to collect the links from the page and then make a random choice from that list. See therandompackage documentation for thechoicemethod.
– Prune
Aug 22 '18 at 22:57
Thanks for the help. I figured out how to do collect all the links from the page. However there are some links that are unnecessary. Is it possible to exclude them?
– Kunwar Sodhi
Aug 23 '18 at 2:39
If you got unnecessary links then your selector is not perfect. Use more specific selector to get rid of them
– Andersson
Aug 23 '18 at 4:58
Hi @KunwarSodhi, what exactly do you mean by unnecessary links? Do you want to edit your post and give us an example of what exactly you need - which links exactly, and we could provide a detailed solution.
– Shlomi Bazel
Aug 23 '18 at 8:21
add a comment |
0
0
0
Currently using Selenium+ Python and this code:
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("how to search the internet")
search.send_keys(Keys.RETURN) # hit return after you enter search text
time.sleep(5) # sleep for 5 seconds so you can see the results
browser.execute_script("window.scrollTo(0, 873)")
time.sleep(2)
browser.find_element(By.XPATH, '(//h3)[3]/a').click()`
as my code.
What Happens: Goes to Google and types in the words and hits search. Scrolls down a bit and then it clicks the first link
What I want: I want to be able to click a random link from the search result page
How to do this?
Edit: This is what I meant when I said unnecessary:
Unnecessary 1: https://imgur.com/a/70qz89x
Unnecessary 2: https://imgur.com/a/8WWvcnC
These are the only results I want:
This: https://imgur.com/a/eTatFV9
python selenium selenium-webdriver xpath webdriver
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
Currently using Selenium+ Python and this code:
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("how to search the internet")
search.send_keys(Keys.RETURN) # hit return after you enter search text
time.sleep(5) # sleep for 5 seconds so you can see the results
browser.execute_script("window.scrollTo(0, 873)")
time.sleep(2)
browser.find_element(By.XPATH, '(//h3)[3]/a').click()`
as my code.
What Happens: Goes to Google and types in the words and hits search. Scrolls down a bit and then it clicks the first link
What I want: I want to be able to click a random link from the search result page
How to do this?
Edit: This is what I meant when I said unnecessary:
Unnecessary 1: https://imgur.com/a/70qz89x
Unnecessary 2: https://imgur.com/a/8WWvcnC
These are the only results I want:
This: https://imgur.com/a/eTatFV9
python selenium selenium-webdriver xpath webdriver
python selenium selenium-webdriver xpath webdriver
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
edited Aug 24 '18 at 15:14
DebanjanB
43.3k104384
43.3k104384
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
asked Aug 22 '18 at 22:54
Kunwar SodhiKunwar Sodhi
8817
8817
1
You'll need to collect the links from the page and then make a random choice from that list. See therandompackage documentation for thechoicemethod.
– Prune
Aug 22 '18 at 22:57
Thanks for the help. I figured out how to do collect all the links from the page. However there are some links that are unnecessary. Is it possible to exclude them?
– Kunwar Sodhi
Aug 23 '18 at 2:39
If you got unnecessary links then your selector is not perfect. Use more specific selector to get rid of them
– Andersson
Aug 23 '18 at 4:58
Hi @KunwarSodhi, what exactly do you mean by unnecessary links? Do you want to edit your post and give us an example of what exactly you need - which links exactly, and we could provide a detailed solution.
– Shlomi Bazel
Aug 23 '18 at 8:21
add a comment |
1
You'll need to collect the links from the page and then make a random choice from that list. See therandompackage documentation for thechoicemethod.
– Prune
Aug 22 '18 at 22:57
Thanks for the help. I figured out how to do collect all the links from the page. However there are some links that are unnecessary. Is it possible to exclude them?
– Kunwar Sodhi
Aug 23 '18 at 2:39
If you got unnecessary links then your selector is not perfect. Use more specific selector to get rid of them
– Andersson
Aug 23 '18 at 4:58
Hi @KunwarSodhi, what exactly do you mean by unnecessary links? Do you want to edit your post and give us an example of what exactly you need - which links exactly, and we could provide a detailed solution.
– Shlomi Bazel
Aug 23 '18 at 8:21
1
1
You'll need to collect the links from the page and then make a random choice from that list. See the
random package documentation for the choice method.– Prune
Aug 22 '18 at 22:57
You'll need to collect the links from the page and then make a random choice from that list. See the
random package documentation for the choice method.– Prune
Aug 22 '18 at 22:57
Thanks for the help. I figured out how to do collect all the links from the page. However there are some links that are unnecessary. Is it possible to exclude them?
– Kunwar Sodhi
Aug 23 '18 at 2:39
Thanks for the help. I figured out how to do collect all the links from the page. However there are some links that are unnecessary. Is it possible to exclude them?
– Kunwar Sodhi
Aug 23 '18 at 2:39
If you got unnecessary links then your selector is not perfect. Use more specific selector to get rid of them
– Andersson
Aug 23 '18 at 4:58
If you got unnecessary links then your selector is not perfect. Use more specific selector to get rid of them
– Andersson
Aug 23 '18 at 4:58
Hi @KunwarSodhi, what exactly do you mean by unnecessary links? Do you want to edit your post and give us an example of what exactly you need - which links exactly, and we could provide a detailed solution.
– Shlomi Bazel
Aug 23 '18 at 8:21
Hi @KunwarSodhi, what exactly do you mean by unnecessary links? Do you want to edit your post and give us an example of what exactly you need - which links exactly, and we could provide a detailed solution.
– Shlomi Bazel
Aug 23 '18 at 8:21
add a comment |
1 Answer
1
active
oldest
votes
1
As per your question to click() on a random link from google search results, as per your code trial if you invoke window.scrollTo(0, 873) and then invoke click() as in:
find_element(By.XPATH, '(//h3)[3]/a').click()`
Selenium will still try to attempt click() on the first match, which may not be your desired usecase.
Solution
Inorder to click() on a random link from google search results, you can create a List out of the search results and then generate a Random Number and invoke click() through an index as follows:
Code Block:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.keys import Keys
from random import randint
options = webdriver.ChromeOptions()
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
browser=webdriver.Chrome(chrome_options=options, executable_path=r'C:UtilityBrowserDriverschromedriver.exe')
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("selenium")
search.send_keys(Keys.RETURN)
my_search_list = WebDriverWait(browser, 10).until(EC.visibility_of_all_elements_located((By.XPATH, "//h3[@class='r']/a[not(ancestor::div[@class='xIleA'])]")))
myRandomNumber = randint(0, len(my_search_list))
print(myRandomNumber)
my_search_list[myRandomNumber].click()
Console Output:
4
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Can you ensure you are accessinghttp://www.google.comas your program might be accessing the local google server instance which is probhably not ending with.com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.
– DebanjanB
Aug 23 '18 at 14:30
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
1
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
|
show 10 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
As per your question to click() on a random link from google search results, as per your code trial if you invoke window.scrollTo(0, 873) and then invoke click() as in:
find_element(By.XPATH, '(//h3)[3]/a').click()`
Selenium will still try to attempt click() on the first match, which may not be your desired usecase.
Solution
Inorder to click() on a random link from google search results, you can create a List out of the search results and then generate a Random Number and invoke click() through an index as follows:
Code Block:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.keys import Keys
from random import randint
options = webdriver.ChromeOptions()
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
browser=webdriver.Chrome(chrome_options=options, executable_path=r'C:UtilityBrowserDriverschromedriver.exe')
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("selenium")
search.send_keys(Keys.RETURN)
my_search_list = WebDriverWait(browser, 10).until(EC.visibility_of_all_elements_located((By.XPATH, "//h3[@class='r']/a[not(ancestor::div[@class='xIleA'])]")))
myRandomNumber = randint(0, len(my_search_list))
print(myRandomNumber)
my_search_list[myRandomNumber].click()
Console Output:
4
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Can you ensure you are accessinghttp://www.google.comas your program might be accessing the local google server instance which is probhably not ending with.com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.
– DebanjanB
Aug 23 '18 at 14:30
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
1
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
|
show 10 more comments
1
As per your question to click() on a random link from google search results, as per your code trial if you invoke window.scrollTo(0, 873) and then invoke click() as in:
find_element(By.XPATH, '(//h3)[3]/a').click()`
Selenium will still try to attempt click() on the first match, which may not be your desired usecase.
Solution
Inorder to click() on a random link from google search results, you can create a List out of the search results and then generate a Random Number and invoke click() through an index as follows:
Code Block:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.keys import Keys
from random import randint
options = webdriver.ChromeOptions()
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
browser=webdriver.Chrome(chrome_options=options, executable_path=r'C:UtilityBrowserDriverschromedriver.exe')
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("selenium")
search.send_keys(Keys.RETURN)
my_search_list = WebDriverWait(browser, 10).until(EC.visibility_of_all_elements_located((By.XPATH, "//h3[@class='r']/a[not(ancestor::div[@class='xIleA'])]")))
myRandomNumber = randint(0, len(my_search_list))
print(myRandomNumber)
my_search_list[myRandomNumber].click()
Console Output:
4
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Can you ensure you are accessinghttp://www.google.comas your program might be accessing the local google server instance which is probhably not ending with.com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.
– DebanjanB
Aug 23 '18 at 14:30
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
1
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
|
show 10 more comments
1
1
1
As per your question to click() on a random link from google search results, as per your code trial if you invoke window.scrollTo(0, 873) and then invoke click() as in:
find_element(By.XPATH, '(//h3)[3]/a').click()`
Selenium will still try to attempt click() on the first match, which may not be your desired usecase.
Solution
Inorder to click() on a random link from google search results, you can create a List out of the search results and then generate a Random Number and invoke click() through an index as follows:
Code Block:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.keys import Keys
from random import randint
options = webdriver.ChromeOptions()
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
browser=webdriver.Chrome(chrome_options=options, executable_path=r'C:UtilityBrowserDriverschromedriver.exe')
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("selenium")
search.send_keys(Keys.RETURN)
my_search_list = WebDriverWait(browser, 10).until(EC.visibility_of_all_elements_located((By.XPATH, "//h3[@class='r']/a[not(ancestor::div[@class='xIleA'])]")))
myRandomNumber = randint(0, len(my_search_list))
print(myRandomNumber)
my_search_list[myRandomNumber].click()
Console Output:
4
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
As per your question to click() on a random link from google search results, as per your code trial if you invoke window.scrollTo(0, 873) and then invoke click() as in:
find_element(By.XPATH, '(//h3)[3]/a').click()`
Selenium will still try to attempt click() on the first match, which may not be your desired usecase.
Solution
Inorder to click() on a random link from google search results, you can create a List out of the search results and then generate a Random Number and invoke click() through an index as follows:
Code Block:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.keys import Keys
from random import randint
options = webdriver.ChromeOptions()
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
browser=webdriver.Chrome(chrome_options=options, executable_path=r'C:UtilityBrowserDriverschromedriver.exe')
browser.get('http://www.google.com')
search = browser.find_element_by_name('q')
search.send_keys("selenium")
search.send_keys(Keys.RETURN)
my_search_list = WebDriverWait(browser, 10).until(EC.visibility_of_all_elements_located((By.XPATH, "//h3[@class='r']/a[not(ancestor::div[@class='xIleA'])]")))
myRandomNumber = randint(0, len(my_search_list))
print(myRandomNumber)
my_search_list[myRandomNumber].click()
Console Output:
4
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
answered Aug 23 '18 at 14:06
DebanjanBDebanjanB
43.3k104384
43.3k104384
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Can you ensure you are accessinghttp://www.google.comas your program might be accessing the local google server instance which is probhably not ending with.com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.
– DebanjanB
Aug 23 '18 at 14:30
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
1
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
|
show 10 more comments
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Can you ensure you are accessinghttp://www.google.comas your program might be accessing the local google server instance which is probhably not ending with.com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.
– DebanjanB
Aug 23 '18 at 14:30
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
1
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Gives list index error
– Kunwar Sodhi
Aug 23 '18 at 14:27
Can you ensure you are accessing
http://www.google.com as your program might be accessing the local google server instance which is probhably not ending with .com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.– DebanjanB
Aug 23 '18 at 14:30
Can you ensure you are accessing
http://www.google.com as your program might be accessing the local google server instance which is probhably not ending with .com. In that case you may require to tweak the xpath but the logic remains the same. In this run I got an output as 6.– DebanjanB
Aug 23 '18 at 14:30
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
It works!. In this case I got a output of 2. However the first time I ran I got a output of 10 and it didn't work then. Maybe the 10th link isn't on the webpage at the time?
– Kunwar Sodhi
Aug 23 '18 at 14:36
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
Yup I just got 10 as a output and it didn't work and said List Index out of range
– Kunwar Sodhi
Aug 23 '18 at 14:37
1
1
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
Sorry I just got enough rep to upvote.
– Kunwar Sodhi
Aug 24 '18 at 12:42
|
show 10 more comments
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1
You'll need to collect the links from the page and then make a random choice from that list. See the
randompackage documentation for thechoicemethod.– Prune
Aug 22 '18 at 22:57
Thanks for the help. I figured out how to do collect all the links from the page. However there are some links that are unnecessary. Is it possible to exclude them?
– Kunwar Sodhi
Aug 23 '18 at 2:39
If you got unnecessary links then your selector is not perfect. Use more specific selector to get rid of them
– Andersson
Aug 23 '18 at 4:58
Hi @KunwarSodhi, what exactly do you mean by unnecessary links? Do you want to edit your post and give us an example of what exactly you need - which links exactly, and we could provide a detailed solution.
– Shlomi Bazel
Aug 23 '18 at 8:21