Quickest way to find the eigenvalues of a binary hermitian matrix?












2












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I have an 11x11 matrix and need to find its charactaristic polynomial (or eigenvalues). I would like to do this analytically but was wondering if there's any tricks that can be used due to its hermitian and binary nature.






linear-algebra eigenvalues-eigenvectors







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  • 1




    $begingroup$
    When you say "binary", do you mean that you want to work over the field with two elements, or do you just mean that all entries are zeroes and ones?
    $endgroup$
    – John Hughes
    Jan 19 at 12:54










  • $begingroup$
    @JohnHughes i meant that all entries are zeroes and ones
    $endgroup$
    – James
    Jan 19 at 15:46
















2












$begingroup$


I have an 11x11 matrix and need to find its charactaristic polynomial (or eigenvalues). I would like to do this analytically but was wondering if there's any tricks that can be used due to its hermitian and binary nature.






linear-algebra eigenvalues-eigenvectors







share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    When you say "binary", do you mean that you want to work over the field with two elements, or do you just mean that all entries are zeroes and ones?
    $endgroup$
    – John Hughes
    Jan 19 at 12:54










  • $begingroup$
    @JohnHughes i meant that all entries are zeroes and ones
    $endgroup$
    – James
    Jan 19 at 15:46














2












2








2





$begingroup$


I have an 11x11 matrix and need to find its charactaristic polynomial (or eigenvalues). I would like to do this analytically but was wondering if there's any tricks that can be used due to its hermitian and binary nature.






linear-algebra eigenvalues-eigenvectors







share|cite|improve this question









$endgroup$




I have an 11x11 matrix and need to find its charactaristic polynomial (or eigenvalues). I would like to do this analytically but was wondering if there's any tricks that can be used due to its hermitian and binary nature.






linear-algebra eigenvalues-eigenvectors




linear-algebra eigenvalues-eigenvectors






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 19 at 12:21









JamesJames

15310




15310








  • 1




    $begingroup$
    When you say "binary", do you mean that you want to work over the field with two elements, or do you just mean that all entries are zeroes and ones?
    $endgroup$
    – John Hughes
    Jan 19 at 12:54










  • $begingroup$
    @JohnHughes i meant that all entries are zeroes and ones
    $endgroup$
    – James
    Jan 19 at 15:46














  • 1




    $begingroup$
    When you say "binary", do you mean that you want to work over the field with two elements, or do you just mean that all entries are zeroes and ones?
    $endgroup$
    – John Hughes
    Jan 19 at 12:54










  • $begingroup$
    @JohnHughes i meant that all entries are zeroes and ones
    $endgroup$
    – James
    Jan 19 at 15:46








1




1




$begingroup$
When you say "binary", do you mean that you want to work over the field with two elements, or do you just mean that all entries are zeroes and ones?
$endgroup$
– John Hughes
Jan 19 at 12:54




$begingroup$
When you say "binary", do you mean that you want to work over the field with two elements, or do you just mean that all entries are zeroes and ones?
$endgroup$
– John Hughes
Jan 19 at 12:54












$begingroup$
@JohnHughes i meant that all entries are zeroes and ones
$endgroup$
– James
Jan 19 at 15:46




$begingroup$
@JohnHughes i meant that all entries are zeroes and ones
$endgroup$
– James
Jan 19 at 15:46










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