Why do the graphs of $y=operatorname{arccot}(x)$ and $y=arctan(1/x)$ only agree for $x>0$?
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When trying to plot a graph of $y=operatorname{arccot}(x)$, a function which I do not know the appearance of, I would try and get it in terms of something I do know:
$$y=operatorname{arccot}(x)$$
$$x=cot(y)$$
$$frac1x=tan(y)$$
$$y=arctanleft(frac1xright)$$
However, when using an online graph plotter, only the $x>0$ region is correct. Why would this be?
functions
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add a comment |
$begingroup$
When trying to plot a graph of $y=operatorname{arccot}(x)$, a function which I do not know the appearance of, I would try and get it in terms of something I do know:
$$y=operatorname{arccot}(x)$$
$$x=cot(y)$$
$$frac1x=tan(y)$$
$$y=arctanleft(frac1xright)$$
However, when using an online graph plotter, only the $x>0$ region is correct. Why would this be?
functions
$endgroup$
1
$begingroup$
See math.stackexchange.com/questions/304399/…
$endgroup$
– lab bhattacharjee
Jan 19 at 14:05
add a comment |
$begingroup$
When trying to plot a graph of $y=operatorname{arccot}(x)$, a function which I do not know the appearance of, I would try and get it in terms of something I do know:
$$y=operatorname{arccot}(x)$$
$$x=cot(y)$$
$$frac1x=tan(y)$$
$$y=arctanleft(frac1xright)$$
However, when using an online graph plotter, only the $x>0$ region is correct. Why would this be?
functions
$endgroup$
When trying to plot a graph of $y=operatorname{arccot}(x)$, a function which I do not know the appearance of, I would try and get it in terms of something I do know:
$$y=operatorname{arccot}(x)$$
$$x=cot(y)$$
$$frac1x=tan(y)$$
$$y=arctanleft(frac1xright)$$
However, when using an online graph plotter, only the $x>0$ region is correct. Why would this be?
functions
functions
edited Jan 19 at 13:21
Blue
48.6k870156
48.6k870156
asked Jan 19 at 13:17
Henry LeeHenry Lee
2,054219
2,054219
1
$begingroup$
See math.stackexchange.com/questions/304399/…
$endgroup$
– lab bhattacharjee
Jan 19 at 14:05
add a comment |
1
$begingroup$
See math.stackexchange.com/questions/304399/…
$endgroup$
– lab bhattacharjee
Jan 19 at 14:05
1
1
$begingroup$
See math.stackexchange.com/questions/304399/…
$endgroup$
– lab bhattacharjee
Jan 19 at 14:05
$begingroup$
See math.stackexchange.com/questions/304399/…
$endgroup$
– lab bhattacharjee
Jan 19 at 14:05
add a comment |
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$begingroup$
See math.stackexchange.com/questions/304399/…
$endgroup$
– lab bhattacharjee
Jan 19 at 14:05