Mixing
How to perform wild card search in a vector of strings using cloudant selector query
There are different documents consisting of the following structure:
1."dev": {
"urls": ["https://text.com/00a51073"]
}
2. "dev": {
"urls": ["https://text.com/410578c1","https://text.com/00a51073"]
}
How do I perform a wild card search so that a search for "00a51073" should return both the above documents?
{
"selector": {
"$and": [
{
"$or": [
{
"dev": {
"urls": {
"$regex": ".*00a51073"
}
}
}
]
}
]
}
}
wildcard cloudant
asked Jan 2 at 18:07
Pratap DPratap D
46111
add a comment |
There are different documents consisting of the following structure:
1."dev": {
"urls": ["https://text.com/00a51073"]
}
2. "dev": {
"urls": ["https://text.com/410578c1","https://text.com/00a51073"]
}
How do I perform a wild card search so that a search for "00a51073" should return both the above documents?
{
"selector": {
"$and": [
{
"$or": [
{
"dev": {
"urls": {
"$regex": ".*00a51073"
}
}
}
]
}
]
}
}
wildcard cloudant
asked Jan 2 at 18:07
Pratap DPratap D
46111
add a comment |
There are different documents consisting of the following structure:
1."dev": {
"urls": ["https://text.com/00a51073"]
}
2. "dev": {
"urls": ["https://text.com/410578c1","https://text.com/00a51073"]
}
How do I perform a wild card search so that a search for "00a51073" should return both the above documents?
{
"selector": {
"$and": [
{
"$or": [
{
"dev": {
"urls": {
"$regex": ".*00a51073"
}
}
}
]
}
]
}
}
wildcard cloudant
asked Jan 2 at 18:07
Pratap DPratap D
46111
There are different documents consisting of the following structure:
1."dev": {
"urls": ["https://text.com/00a51073"]
}
2. "dev": {
"urls": ["https://text.com/410578c1","https://text.com/00a51073"]
}
How do I perform a wild card search so that a search for "00a51073" should return both the above documents?
{
"selector": {
"$and": [
{
"$or": [
{
"dev": {
"urls": {
"$regex": ".*00a51073"
}
}
}
]
}
]
}
}
wildcard cloudant
wildcard cloudant
asked Jan 2 at 18:07
Pratap DPratap D
46111
asked Jan 2 at 18:07
Pratap DPratap D
46111
asked Jan 2 at 18:07
Pratap DPratap D
46111
asked Jan 2 at 18:07
Pratap DPratap D
46111
asked Jan 2 at 18:07
Pratap DPratap D
46111
46111
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
How about using a vanilla map-reduce view instead? Just use the last bit of each url as the key, and you can retrieve all docs as a range query. A map might look like
function(doc) {
if (doc && doc.dev && doc.dev.urls) {
doc.dev.urls.forEach(function(url) {
var data = url.split("/");
emit(data[data.len-1], 1);
});
}
}
and then you can query it something like
curl 'https://...cloudant.com/DB/_design/DD/_view/by_url?startkey="00a51073"&endkey="00a51073."&include_docs=true'
answered Jan 3 at 17:42
xpqzxpqz
1,50257
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
How about using a vanilla map-reduce view instead? Just use the last bit of each url as the key, and you can retrieve all docs as a range query. A map might look like
function(doc) {
if (doc && doc.dev && doc.dev.urls) {
doc.dev.urls.forEach(function(url) {
var data = url.split("/");
emit(data[data.len-1], 1);
});
}
}
and then you can query it something like
curl 'https://...cloudant.com/DB/_design/DD/_view/by_url?startkey="00a51073"&endkey="00a51073."&include_docs=true'
answered Jan 3 at 17:42
xpqzxpqz
1,50257
add a comment |
How about using a vanilla map-reduce view instead? Just use the last bit of each url as the key, and you can retrieve all docs as a range query. A map might look like
function(doc) {
if (doc && doc.dev && doc.dev.urls) {
doc.dev.urls.forEach(function(url) {
var data = url.split("/");
emit(data[data.len-1], 1);
});
}
}
and then you can query it something like
curl 'https://...cloudant.com/DB/_design/DD/_view/by_url?startkey="00a51073"&endkey="00a51073."&include_docs=true'
answered Jan 3 at 17:42
xpqzxpqz
1,50257
add a comment |
How about using a vanilla map-reduce view instead? Just use the last bit of each url as the key, and you can retrieve all docs as a range query. A map might look like
function(doc) {
if (doc && doc.dev && doc.dev.urls) {
doc.dev.urls.forEach(function(url) {
var data = url.split("/");
emit(data[data.len-1], 1);
});
}
}
and then you can query it something like
curl 'https://...cloudant.com/DB/_design/DD/_view/by_url?startkey="00a51073"&endkey="00a51073."&include_docs=true'
answered Jan 3 at 17:42
xpqzxpqz
1,50257
How about using a vanilla map-reduce view instead? Just use the last bit of each url as the key, and you can retrieve all docs as a range query. A map might look like
function(doc) {
if (doc && doc.dev && doc.dev.urls) {
doc.dev.urls.forEach(function(url) {
var data = url.split("/");
emit(data[data.len-1], 1);
});
}
}
and then you can query it something like
curl 'https://...cloudant.com/DB/_design/DD/_view/by_url?startkey="00a51073"&endkey="00a51073."&include_docs=true'
answered Jan 3 at 17:42
xpqzxpqz
1,50257
answered Jan 3 at 17:42
xpqzxpqz
1,50257
answered Jan 3 at 17:42
xpqzxpqz
1,50257
answered Jan 3 at 17:42
xpqzxpqz
1,50257
1,50257
add a comment |
add a comment |
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