Is $[0,1]^A$ not sequentially compact for any uncountable $A$?












2












$begingroup$


We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?










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  • 2




    $begingroup$
    Perhaps this is on point.
    $endgroup$
    – David Mitra
    Jan 20 at 7:08
















2












$begingroup$


We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?










share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    Perhaps this is on point.
    $endgroup$
    – David Mitra
    Jan 20 at 7:08














2












2








2





$begingroup$


We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?










share|cite|improve this question









$endgroup$




We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?







compactness product-space






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share|cite|improve this question










asked Jan 20 at 5:33









SmileyCraftSmileyCraft

3,476518




3,476518








  • 2




    $begingroup$
    Perhaps this is on point.
    $endgroup$
    – David Mitra
    Jan 20 at 7:08














  • 2




    $begingroup$
    Perhaps this is on point.
    $endgroup$
    – David Mitra
    Jan 20 at 7:08








2




2




$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08




$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08










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