Is $[0,1]^A$ not sequentially compact for any uncountable $A$?
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We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?
compactness product-space
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add a comment |
$begingroup$
We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?
compactness product-space
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2
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Perhaps this is on point.
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– David Mitra
Jan 20 at 7:08
add a comment |
$begingroup$
We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?
compactness product-space
$endgroup$
We know ${0,1}^mathbb{N}$ is sequentially compact, but ${0,1}^mathbb{R}$ is not. The proof I have seen that the second is not sequentially compact heavily relies on the fact that we have a continuum. So not assuming the continuum hypothesis, is it still true that ${0,1}^A$ is not sequentially compact for any uncountable $A$?
compactness product-space
compactness product-space
asked Jan 20 at 5:33
SmileyCraftSmileyCraft
3,476518
3,476518
2
$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08
add a comment |
2
$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08
2
2
$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08
$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08
add a comment |
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$begingroup$
Perhaps this is on point.
$endgroup$
– David Mitra
Jan 20 at 7:08