Is Pull back of Lie group a Lie group?












0












$begingroup$


Suppose $f:Mrightarrow N$ is a submersion. Then, $Mtimes_NM$ is a smooth manifold from Transversal theorem.




Suppose $theta:Grightarrow H$ is a morphism of Lie groups. Assume that it is a submersion. Does it imply $Gtimes_H G$ is a Lie group?




As $Grightarrow H$ is submersion, $Gtimes_H G $ is a smooth manifold. Does it have to be Lie group?



When will $Gtimes_H G$ is a Lie group?










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$endgroup$

















    0












    $begingroup$


    Suppose $f:Mrightarrow N$ is a submersion. Then, $Mtimes_NM$ is a smooth manifold from Transversal theorem.




    Suppose $theta:Grightarrow H$ is a morphism of Lie groups. Assume that it is a submersion. Does it imply $Gtimes_H G$ is a Lie group?




    As $Grightarrow H$ is submersion, $Gtimes_H G $ is a smooth manifold. Does it have to be Lie group?



    When will $Gtimes_H G$ is a Lie group?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Suppose $f:Mrightarrow N$ is a submersion. Then, $Mtimes_NM$ is a smooth manifold from Transversal theorem.




      Suppose $theta:Grightarrow H$ is a morphism of Lie groups. Assume that it is a submersion. Does it imply $Gtimes_H G$ is a Lie group?




      As $Grightarrow H$ is submersion, $Gtimes_H G $ is a smooth manifold. Does it have to be Lie group?



      When will $Gtimes_H G$ is a Lie group?










      share|cite|improve this question









      $endgroup$




      Suppose $f:Mrightarrow N$ is a submersion. Then, $Mtimes_NM$ is a smooth manifold from Transversal theorem.




      Suppose $theta:Grightarrow H$ is a morphism of Lie groups. Assume that it is a submersion. Does it imply $Gtimes_H G$ is a Lie group?




      As $Grightarrow H$ is submersion, $Gtimes_H G $ is a smooth manifold. Does it have to be Lie group?



      When will $Gtimes_H G$ is a Lie group?







      differential-geometry lie-groups smooth-manifolds






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 20 at 4:24









      Praphulla KoushikPraphulla Koushik

      17419




      17419






















          1 Answer
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          $begingroup$

          Yes it’s always a Lie group.



          Closure under multiplication and inverses you can check, so it’s a group. For smoothness, note $Mtimes_NM$ isn’t just a manifold, but an embedded submanifold of $Mtimes M$. The multiplication and inversion for $Gtimes_HG$ are restricted from $Gtimes G$ to the submanifold, hence smooth.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 5:35










          • $begingroup$
            @PraphullaKoushik No problem!
            $endgroup$
            – Ben
            Jan 20 at 6:00










          • $begingroup$
            I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 9:21













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          1 Answer
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          1 Answer
          1






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          active

          oldest

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          active

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          2












          $begingroup$

          Yes it’s always a Lie group.



          Closure under multiplication and inverses you can check, so it’s a group. For smoothness, note $Mtimes_NM$ isn’t just a manifold, but an embedded submanifold of $Mtimes M$. The multiplication and inversion for $Gtimes_HG$ are restricted from $Gtimes G$ to the submanifold, hence smooth.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 5:35










          • $begingroup$
            @PraphullaKoushik No problem!
            $endgroup$
            – Ben
            Jan 20 at 6:00










          • $begingroup$
            I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 9:21


















          2












          $begingroup$

          Yes it’s always a Lie group.



          Closure under multiplication and inverses you can check, so it’s a group. For smoothness, note $Mtimes_NM$ isn’t just a manifold, but an embedded submanifold of $Mtimes M$. The multiplication and inversion for $Gtimes_HG$ are restricted from $Gtimes G$ to the submanifold, hence smooth.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 5:35










          • $begingroup$
            @PraphullaKoushik No problem!
            $endgroup$
            – Ben
            Jan 20 at 6:00










          • $begingroup$
            I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 9:21
















          2












          2








          2





          $begingroup$

          Yes it’s always a Lie group.



          Closure under multiplication and inverses you can check, so it’s a group. For smoothness, note $Mtimes_NM$ isn’t just a manifold, but an embedded submanifold of $Mtimes M$. The multiplication and inversion for $Gtimes_HG$ are restricted from $Gtimes G$ to the submanifold, hence smooth.






          share|cite|improve this answer









          $endgroup$



          Yes it’s always a Lie group.



          Closure under multiplication and inverses you can check, so it’s a group. For smoothness, note $Mtimes_NM$ isn’t just a manifold, but an embedded submanifold of $Mtimes M$. The multiplication and inversion for $Gtimes_HG$ are restricted from $Gtimes G$ to the submanifold, hence smooth.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 20 at 4:57









          BenBen

          4,198617




          4,198617












          • $begingroup$
            Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 5:35










          • $begingroup$
            @PraphullaKoushik No problem!
            $endgroup$
            – Ben
            Jan 20 at 6:00










          • $begingroup$
            I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 9:21




















          • $begingroup$
            Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 5:35










          • $begingroup$
            @PraphullaKoushik No problem!
            $endgroup$
            – Ben
            Jan 20 at 6:00










          • $begingroup$
            I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
            $endgroup$
            – Praphulla Koushik
            Jan 20 at 9:21


















          $begingroup$
          Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
          $endgroup$
          – Praphulla Koushik
          Jan 20 at 5:35




          $begingroup$
          Ok. Restriction of smooth map to embeded submanifold is smooth.. So, it i the case.. Thanks
          $endgroup$
          – Praphulla Koushik
          Jan 20 at 5:35












          $begingroup$
          @PraphullaKoushik No problem!
          $endgroup$
          – Ben
          Jan 20 at 6:00




          $begingroup$
          @PraphullaKoushik No problem!
          $endgroup$
          – Ben
          Jan 20 at 6:00












          $begingroup$
          I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
          $endgroup$
          – Praphulla Koushik
          Jan 20 at 9:21






          $begingroup$
          I have added more details as a community wiki answer. Let me know if I am missing something. Thank you :)
          $endgroup$
          – Praphulla Koushik
          Jan 20 at 9:21




















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