Mixing
properties of periodic function
$begingroup$
If $f$ is a continuous periodic function of period $2π$, then is there a point c such that $f(c+π/2)=f(c)$ and a point x such that $f(x+π/4)=f(x)$? domain of $f$ is $mathbb{R}$ and $f$ is real valued.
real-analysis
edited Jan 20 at 5:51
Macrophage
1,191115
asked Jan 20 at 5:31
jjjjjj
1094
$endgroup$
add a comment |
$begingroup$
If $f$ is a continuous periodic function of period $2π$, then is there a point c such that $f(c+π/2)=f(c)$ and a point x such that $f(x+π/4)=f(x)$? domain of $f$ is $mathbb{R}$ and $f$ is real valued.
real-analysis
edited Jan 20 at 5:51
Macrophage
1,191115
asked Jan 20 at 5:31
jjjjjj
1094
$endgroup$
$begingroup$
$g(x)= f(x)-f(x+pi/2)$ is $2pi$-periodic and continuous. If it is strictly positive then so is $sum_{n=0}^3 g(x+npi/2) =...$
$endgroup$
– reuns
Jan 20 at 6:39
add a comment |
$begingroup$
If $f$ is a continuous periodic function of period $2π$, then is there a point c such that $f(c+π/2)=f(c)$ and a point x such that $f(x+π/4)=f(x)$? domain of $f$ is $mathbb{R}$ and $f$ is real valued.
real-analysis
edited Jan 20 at 5:51
Macrophage
1,191115
asked Jan 20 at 5:31
jjjjjj
1094
$endgroup$
If $f$ is a continuous periodic function of period $2π$, then is there a point c such that $f(c+π/2)=f(c)$ and a point x such that $f(x+π/4)=f(x)$? domain of $f$ is $mathbb{R}$ and $f$ is real valued.
real-analysis
real-analysis
edited Jan 20 at 5:51
Macrophage
1,191115
asked Jan 20 at 5:31
jjjjjj
1094
edited Jan 20 at 5:51
Macrophage
1,191115
asked Jan 20 at 5:31
jjjjjj
1094
edited Jan 20 at 5:51
Macrophage
1,191115
edited Jan 20 at 5:51
Macrophage
1,191115
edited Jan 20 at 5:51
Macrophage
1,191115
1,191115
asked Jan 20 at 5:31
jjjjjj
1094
asked Jan 20 at 5:31
jjjjjj
1094
asked Jan 20 at 5:31
jjjjjj
1094
1094
$begingroup$
$g(x)= f(x)-f(x+pi/2)$ is $2pi$-periodic and continuous. If it is strictly positive then so is $sum_{n=0}^3 g(x+npi/2) =...$
$endgroup$
– reuns
Jan 20 at 6:39
add a comment |
$begingroup$
$g(x)= f(x)-f(x+pi/2)$ is $2pi$-periodic and continuous. If it is strictly positive then so is $sum_{n=0}^3 g(x+npi/2) =...$
$endgroup$
– reuns
Jan 20 at 6:39
$begingroup$
$g(x)= f(x)-f(x+pi/2)$ is $2pi$-periodic and continuous. If it is strictly positive then so is $sum_{n=0}^3 g(x+npi/2) =...$
$endgroup$
– reuns
Jan 20 at 6:39
$begingroup$
$g(x)= f(x)-f(x+pi/2)$ is $2pi$-periodic and continuous. If it is strictly positive then so is $sum_{n=0}^3 g(x+npi/2) =...$
$endgroup$
– reuns
Jan 20 at 6:39
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3080225%2fproperties-of-periodic-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3080225%2fproperties-of-periodic-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
$g(x)= f(x)-f(x+pi/2)$ is $2pi$-periodic and continuous. If it is strictly positive then so is $sum_{n=0}^3 g(x+npi/2) =...$
$endgroup$
– reuns
Jan 20 at 6:39