Let $P$ be the group of strictly positive real numbers under multiplication. Prove that $P$ isomorphic to...
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Let $P$ be the group of strictly positive real numbers under multiplication. Prove that $P$ isomorphic to $(mathbb{R}, +)$
group-theory group-isomorphism
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closed as off-topic by M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown Jan 29 at 5:19
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$begingroup$
Let $P$ be the group of strictly positive real numbers under multiplication. Prove that $P$ isomorphic to $(mathbb{R}, +)$
group-theory group-isomorphism
$endgroup$
closed as off-topic by M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown Jan 29 at 5:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Let $P$ be the group of strictly positive real numbers under multiplication. Prove that $P$ isomorphic to $(mathbb{R}, +)$
group-theory group-isomorphism
$endgroup$
Let $P$ be the group of strictly positive real numbers under multiplication. Prove that $P$ isomorphic to $(mathbb{R}, +)$
group-theory group-isomorphism
group-theory group-isomorphism
edited Jan 28 at 16:17


idriskameni
732321
732321
asked Jan 28 at 15:49
Grace3001Grace3001
183
183
closed as off-topic by M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown Jan 29 at 5:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown Jan 29 at 5:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – M. Winter, verret, Gibbs, Lee David Chung Lin, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
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Use $$phi: ,x mapsto e^x$$
which is a group homomorphism thanks to the exponential properties.
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$begingroup$
Okay thank you I think I know how to approach it now !
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– Grace3001
Jan 28 at 15:53
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You're welcome!
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– Harnak
Jan 28 at 16:04
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Hint: Consider the exponential function $e:{Bbb R}rightarrow {Bbb R}_{>0}:xmapsto e^x$ and its inverse $log_e :{Bbb R}_{>0}rightarrow {Bbb R}:xmapsto log_e x$.
We have $log_e(e^x) = x$, $e^{log_e x} = x$, $log_e(xcdot y) = log_e(x) + log_e(y)$ and $e^{x+y} = e^xcdot e^y$.
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Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
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– feynhat
Jan 28 at 16:00
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Use $$phi: ,x mapsto e^x$$
which is a group homomorphism thanks to the exponential properties.
$endgroup$
$begingroup$
Okay thank you I think I know how to approach it now !
$endgroup$
– Grace3001
Jan 28 at 15:53
$begingroup$
You're welcome!
$endgroup$
– Harnak
Jan 28 at 16:04
add a comment |
$begingroup$
Use $$phi: ,x mapsto e^x$$
which is a group homomorphism thanks to the exponential properties.
$endgroup$
$begingroup$
Okay thank you I think I know how to approach it now !
$endgroup$
– Grace3001
Jan 28 at 15:53
$begingroup$
You're welcome!
$endgroup$
– Harnak
Jan 28 at 16:04
add a comment |
$begingroup$
Use $$phi: ,x mapsto e^x$$
which is a group homomorphism thanks to the exponential properties.
$endgroup$
Use $$phi: ,x mapsto e^x$$
which is a group homomorphism thanks to the exponential properties.
answered Jan 28 at 15:53
HarnakHarnak
1,309512
1,309512
$begingroup$
Okay thank you I think I know how to approach it now !
$endgroup$
– Grace3001
Jan 28 at 15:53
$begingroup$
You're welcome!
$endgroup$
– Harnak
Jan 28 at 16:04
add a comment |
$begingroup$
Okay thank you I think I know how to approach it now !
$endgroup$
– Grace3001
Jan 28 at 15:53
$begingroup$
You're welcome!
$endgroup$
– Harnak
Jan 28 at 16:04
$begingroup$
Okay thank you I think I know how to approach it now !
$endgroup$
– Grace3001
Jan 28 at 15:53
$begingroup$
Okay thank you I think I know how to approach it now !
$endgroup$
– Grace3001
Jan 28 at 15:53
$begingroup$
You're welcome!
$endgroup$
– Harnak
Jan 28 at 16:04
$begingroup$
You're welcome!
$endgroup$
– Harnak
Jan 28 at 16:04
add a comment |
$begingroup$
Hint: Consider the exponential function $e:{Bbb R}rightarrow {Bbb R}_{>0}:xmapsto e^x$ and its inverse $log_e :{Bbb R}_{>0}rightarrow {Bbb R}:xmapsto log_e x$.
We have $log_e(e^x) = x$, $e^{log_e x} = x$, $log_e(xcdot y) = log_e(x) + log_e(y)$ and $e^{x+y} = e^xcdot e^y$.
$endgroup$
$begingroup$
Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
$endgroup$
– feynhat
Jan 28 at 16:00
add a comment |
$begingroup$
Hint: Consider the exponential function $e:{Bbb R}rightarrow {Bbb R}_{>0}:xmapsto e^x$ and its inverse $log_e :{Bbb R}_{>0}rightarrow {Bbb R}:xmapsto log_e x$.
We have $log_e(e^x) = x$, $e^{log_e x} = x$, $log_e(xcdot y) = log_e(x) + log_e(y)$ and $e^{x+y} = e^xcdot e^y$.
$endgroup$
$begingroup$
Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
$endgroup$
– feynhat
Jan 28 at 16:00
add a comment |
$begingroup$
Hint: Consider the exponential function $e:{Bbb R}rightarrow {Bbb R}_{>0}:xmapsto e^x$ and its inverse $log_e :{Bbb R}_{>0}rightarrow {Bbb R}:xmapsto log_e x$.
We have $log_e(e^x) = x$, $e^{log_e x} = x$, $log_e(xcdot y) = log_e(x) + log_e(y)$ and $e^{x+y} = e^xcdot e^y$.
$endgroup$
Hint: Consider the exponential function $e:{Bbb R}rightarrow {Bbb R}_{>0}:xmapsto e^x$ and its inverse $log_e :{Bbb R}_{>0}rightarrow {Bbb R}:xmapsto log_e x$.
We have $log_e(e^x) = x$, $e^{log_e x} = x$, $log_e(xcdot y) = log_e(x) + log_e(y)$ and $e^{x+y} = e^xcdot e^y$.
edited Jan 28 at 18:39
answered Jan 28 at 15:52
WuestenfuxWuestenfux
5,3231513
5,3231513
$begingroup$
Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
$endgroup$
– feynhat
Jan 28 at 16:00
add a comment |
$begingroup$
Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
$endgroup$
– feynhat
Jan 28 at 16:00
$begingroup$
Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
$endgroup$
– feynhat
Jan 28 at 16:00
$begingroup$
Are their any other isomorphisms between $(mathbb{R}, +)$ and $(mathbb{R}^+, cdot)$?
$endgroup$
– feynhat
Jan 28 at 16:00
add a comment |