Two uniformly most powerful unbiased tests and normal distribution












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I'm currently working my way through lectures notes concerning mathematical statistics.



Let's look at the family of normal distributions $N^n(mu,1)$ where $mu$ ranges in the real numbers. Suppose we want to test the null hypothesis $mu=0=:mu_0$ against the alternative $muneq0$ with significance level 50%.



Uniformly most powerful unbiased tests $phi$ are given by tests of the form $phi(x)=mathbb{1}_{(c_1,c_2)}(frac{sum_{i=1}^nX_i}{sqrt{n}})$, where $c_1,c_2$ are chosen so that $$(1):mathbb{E}_{mu_0}phi = alpha = 0.5$$ and $$(2):mathbb{E}_{mu_0}(phi cdot frac{sum_{i=1}^nX_i}{sqrt{n}})=0.5mathbb{E}_{mu_0}frac{sum_{i=1}^nX_i}{sqrt{n}}$$.



That's kind of the main takeaway as I understand it. (See for example the Book by Lehmann Testing statistical hypotheses)



Now since the normal distribution is symmetric I can chose $c_1=c_2$ as the 1-1/4 quantile of a standard normal distribution, right? (that's also in the notes)



Now the professor makes the following case: These best unbiased tests are not unique, because you could also chose $c_1=-infty$ and $c_2=0$.
While I see that (1) holds, I can't figure out why the second euation is supposed to hold as well.



Any ideas on that?



Thanks in advance!










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    0












    $begingroup$


    I'm currently working my way through lectures notes concerning mathematical statistics.



    Let's look at the family of normal distributions $N^n(mu,1)$ where $mu$ ranges in the real numbers. Suppose we want to test the null hypothesis $mu=0=:mu_0$ against the alternative $muneq0$ with significance level 50%.



    Uniformly most powerful unbiased tests $phi$ are given by tests of the form $phi(x)=mathbb{1}_{(c_1,c_2)}(frac{sum_{i=1}^nX_i}{sqrt{n}})$, where $c_1,c_2$ are chosen so that $$(1):mathbb{E}_{mu_0}phi = alpha = 0.5$$ and $$(2):mathbb{E}_{mu_0}(phi cdot frac{sum_{i=1}^nX_i}{sqrt{n}})=0.5mathbb{E}_{mu_0}frac{sum_{i=1}^nX_i}{sqrt{n}}$$.



    That's kind of the main takeaway as I understand it. (See for example the Book by Lehmann Testing statistical hypotheses)



    Now since the normal distribution is symmetric I can chose $c_1=c_2$ as the 1-1/4 quantile of a standard normal distribution, right? (that's also in the notes)



    Now the professor makes the following case: These best unbiased tests are not unique, because you could also chose $c_1=-infty$ and $c_2=0$.
    While I see that (1) holds, I can't figure out why the second euation is supposed to hold as well.



    Any ideas on that?



    Thanks in advance!










    share|cite|improve this question









    $endgroup$















      0












      0








      0


      0



      $begingroup$


      I'm currently working my way through lectures notes concerning mathematical statistics.



      Let's look at the family of normal distributions $N^n(mu,1)$ where $mu$ ranges in the real numbers. Suppose we want to test the null hypothesis $mu=0=:mu_0$ against the alternative $muneq0$ with significance level 50%.



      Uniformly most powerful unbiased tests $phi$ are given by tests of the form $phi(x)=mathbb{1}_{(c_1,c_2)}(frac{sum_{i=1}^nX_i}{sqrt{n}})$, where $c_1,c_2$ are chosen so that $$(1):mathbb{E}_{mu_0}phi = alpha = 0.5$$ and $$(2):mathbb{E}_{mu_0}(phi cdot frac{sum_{i=1}^nX_i}{sqrt{n}})=0.5mathbb{E}_{mu_0}frac{sum_{i=1}^nX_i}{sqrt{n}}$$.



      That's kind of the main takeaway as I understand it. (See for example the Book by Lehmann Testing statistical hypotheses)



      Now since the normal distribution is symmetric I can chose $c_1=c_2$ as the 1-1/4 quantile of a standard normal distribution, right? (that's also in the notes)



      Now the professor makes the following case: These best unbiased tests are not unique, because you could also chose $c_1=-infty$ and $c_2=0$.
      While I see that (1) holds, I can't figure out why the second euation is supposed to hold as well.



      Any ideas on that?



      Thanks in advance!










      share|cite|improve this question









      $endgroup$




      I'm currently working my way through lectures notes concerning mathematical statistics.



      Let's look at the family of normal distributions $N^n(mu,1)$ where $mu$ ranges in the real numbers. Suppose we want to test the null hypothesis $mu=0=:mu_0$ against the alternative $muneq0$ with significance level 50%.



      Uniformly most powerful unbiased tests $phi$ are given by tests of the form $phi(x)=mathbb{1}_{(c_1,c_2)}(frac{sum_{i=1}^nX_i}{sqrt{n}})$, where $c_1,c_2$ are chosen so that $$(1):mathbb{E}_{mu_0}phi = alpha = 0.5$$ and $$(2):mathbb{E}_{mu_0}(phi cdot frac{sum_{i=1}^nX_i}{sqrt{n}})=0.5mathbb{E}_{mu_0}frac{sum_{i=1}^nX_i}{sqrt{n}}$$.



      That's kind of the main takeaway as I understand it. (See for example the Book by Lehmann Testing statistical hypotheses)



      Now since the normal distribution is symmetric I can chose $c_1=c_2$ as the 1-1/4 quantile of a standard normal distribution, right? (that's also in the notes)



      Now the professor makes the following case: These best unbiased tests are not unique, because you could also chose $c_1=-infty$ and $c_2=0$.
      While I see that (1) holds, I can't figure out why the second euation is supposed to hold as well.



      Any ideas on that?



      Thanks in advance!







      probability-theory statistics statistical-inference






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      share|cite|improve this question











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      asked Jan 24 at 22:59









      VanillaThunderVanillaThunder

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