Why won't ruby-mcrypt accept an array as a key?

Hello I am having trouble encrypting using an array as the key and the value with the ruby-mcrypt gem. The gem lets me use an array for the key fine, cipher = Mcrypt.new("rijndael-256", :ecb, secret) works. But it will give me an error when I try to encrypt. I've tried many things but no luck. Does anyone know if Mcrypt just doesn't like encrypting with an array?

require 'mcrypt'



def encrypt(plain, secret)

  cipher = Mcrypt.new("rijndael-256", :ecb, secret)

  cipher.padding = :zeros



  encrypted = cipher.encrypt(plain)

  p encrypted

  encrypted.unpack("H*").first.to_s.upcase

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(array_to_encrypt, key_array)

p "RESULT IS #{result}"

The output is as follows:

Mcrypt::RuntimeError: Could not initialize mcrypt: Key length is not legal.

I traced this error to here in the ruby-mcrypt gem but don't understand it enough to figure out why I am getting the error message. Any help or insights would be amazing. Thanks!

edited Jan 8 at 22:40

asked Jan 2 at 18:09

Gabriel

310314

Try key_array.map(&:to_s)? key_array.map(&:size).inject(:+) => 128 whereas key_array.map(&:to_s).map(&:size).inject(:+) => 32. If Mcrypt is not changing the ints to strings it may be giving it a 128byte / 1024bit key instead of 32byte / 256bit

– Tom
Jan 2 at 18:39

Thanks for the suggestion. Unfortunately I am still getting the same error. I was hoping that would work cause that makes sense.

– Gabriel
Jan 2 at 18:45

Try doubling the length of the array [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56, 65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]`. That would match up with this suggestion where their hex array is twice as long for a 256 rijndael.

– Tom
Jan 2 at 19:41

Judging by the fact that the key accessor returns a String and reading between the lines of the documentation for key=, I would guess that the key needs to be a String in Encoding::BINARY encoding.

– Jörg W Mittag
Jan 2 at 19:46

@Tom I did try that and still got the same error

– Gabriel
Jan 2 at 19:53

|
show 1 more comment

require 'mcrypt'



def encrypt(plain, secret)

  cipher = Mcrypt.new("rijndael-256", :ecb, secret)

  cipher.padding = :zeros



  encrypted = cipher.encrypt(plain)

  p encrypted

  encrypted.unpack("H*").first.to_s.upcase

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(array_to_encrypt, key_array)

p "RESULT IS #{result}"

The output is as follows:

Mcrypt::RuntimeError: Could not initialize mcrypt: Key length is not legal.

I traced this error to here in the ruby-mcrypt gem but don't understand it enough to figure out why I am getting the error message. Any help or insights would be amazing. Thanks!

edited Jan 8 at 22:40

asked Jan 2 at 18:09

Gabriel

310314

Try key_array.map(&:to_s)? key_array.map(&:size).inject(:+) => 128 whereas key_array.map(&:to_s).map(&:size).inject(:+) => 32. If Mcrypt is not changing the ints to strings it may be giving it a 128byte / 1024bit key instead of 32byte / 256bit

– Tom
Jan 2 at 18:39

Thanks for the suggestion. Unfortunately I am still getting the same error. I was hoping that would work cause that makes sense.

– Gabriel
Jan 2 at 18:45

Try doubling the length of the array [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56, 65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]`. That would match up with this suggestion where their hex array is twice as long for a 256 rijndael.

– Tom
Jan 2 at 19:41

Judging by the fact that the key accessor returns a String and reading between the lines of the documentation for key=, I would guess that the key needs to be a String in Encoding::BINARY encoding.

– Jörg W Mittag
Jan 2 at 19:46

@Tom I did try that and still got the same error

– Gabriel
Jan 2 at 19:53

|
show 1 more comment

require 'mcrypt'



def encrypt(plain, secret)

  cipher = Mcrypt.new("rijndael-256", :ecb, secret)

  cipher.padding = :zeros



  encrypted = cipher.encrypt(plain)

  p encrypted

  encrypted.unpack("H*").first.to_s.upcase

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(array_to_encrypt, key_array)

p "RESULT IS #{result}"

The output is as follows:

Mcrypt::RuntimeError: Could not initialize mcrypt: Key length is not legal.

I traced this error to here in the ruby-mcrypt gem but don't understand it enough to figure out why I am getting the error message. Any help or insights would be amazing. Thanks!

edited Jan 8 at 22:40

asked Jan 2 at 18:09

Gabriel

310314

require 'mcrypt'



def encrypt(plain, secret)

  cipher = Mcrypt.new("rijndael-256", :ecb, secret)

  cipher.padding = :zeros



  encrypted = cipher.encrypt(plain)

  p encrypted

  encrypted.unpack("H*").first.to_s.upcase

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(array_to_encrypt, key_array)

p "RESULT IS #{result}"

The output is as follows:

Mcrypt::RuntimeError: Could not initialize mcrypt: Key length is not legal.

I traced this error to here in the ruby-mcrypt gem but don't understand it enough to figure out why I am getting the error message. Any help or insights would be amazing. Thanks!

ruby encryption

edited Jan 8 at 22:40

asked Jan 2 at 18:09

Gabriel

310314

edited Jan 8 at 22:40

asked Jan 2 at 18:09

Gabriel

310314

edited Jan 8 at 22:40

asked Jan 2 at 18:09

Gabriel

310314

asked Jan 2 at 18:09

Gabriel

310314

asked Jan 2 at 18:09

Gabriel

310314

Try key_array.map(&:to_s)? key_array.map(&:size).inject(:+) => 128 whereas key_array.map(&:to_s).map(&:size).inject(:+) => 32. If Mcrypt is not changing the ints to strings it may be giving it a 128byte / 1024bit key instead of 32byte / 256bit

– Tom
Jan 2 at 18:39

Thanks for the suggestion. Unfortunately I am still getting the same error. I was hoping that would work cause that makes sense.

– Gabriel
Jan 2 at 18:45

Try doubling the length of the array [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56, 65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]`. That would match up with this suggestion where their hex array is twice as long for a 256 rijndael.

– Tom
Jan 2 at 19:41

Judging by the fact that the key accessor returns a String and reading between the lines of the documentation for key=, I would guess that the key needs to be a String in Encoding::BINARY encoding.

– Jörg W Mittag
Jan 2 at 19:46

@Tom I did try that and still got the same error

– Gabriel
Jan 2 at 19:53

|
show 1 more comment

Try key_array.map(&:to_s)? key_array.map(&:size).inject(:+) => 128 whereas key_array.map(&:to_s).map(&:size).inject(:+) => 32. If Mcrypt is not changing the ints to strings it may be giving it a 128byte / 1024bit key instead of 32byte / 256bit

– Tom
Jan 2 at 18:39

Thanks for the suggestion. Unfortunately I am still getting the same error. I was hoping that would work cause that makes sense.

– Gabriel
Jan 2 at 18:45

Try doubling the length of the array [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56, 65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]`. That would match up with this suggestion where their hex array is twice as long for a 256 rijndael.

– Tom
Jan 2 at 19:41

Judging by the fact that the key accessor returns a String and reading between the lines of the documentation for key=, I would guess that the key needs to be a String in Encoding::BINARY encoding.

– Jörg W Mittag
Jan 2 at 19:46

@Tom I did try that and still got the same error

– Gabriel
Jan 2 at 19:53

Try key_array.map(&:to_s)? key_array.map(&:size).inject(:+) => 128 whereas key_array.map(&:to_s).map(&:size).inject(:+) => 32. If Mcrypt is not changing the ints to strings it may be giving it a 128byte / 1024bit key instead of 32byte / 256bit

– Tom
Jan 2 at 18:39

Thanks for the suggestion. Unfortunately I am still getting the same error. I was hoping that would work cause that makes sense.

– Gabriel
Jan 2 at 18:45

Try doubling the length of the array [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56, 65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]`. That would match up with this suggestion where their hex array is twice as long for a 256 rijndael.

– Tom
Jan 2 at 19:41

Judging by the fact that the key accessor returns a String and reading between the lines of the documentation for key=, I would guess that the key needs to be a String in Encoding::BINARY encoding.

– Jörg W Mittag
Jan 2 at 19:46

@Tom I did try that and still got the same error

– Gabriel
Jan 2 at 19:53

|
show 1 more comment

1 Answer
1

active

oldest

votes

The library doesn't support arrays. You'll need to use Strings instead:

def binary(byte_array)

  byte_array.pack('C*')

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(binary(array_to_encrypt), binary(key_array))

p "RESULT IS #{result}"

answered Jan 7 at 19:44

KingPong

9621118

add a comment |

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1 Answer
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active

oldest

votes

1 Answer
1

active

oldest

votes

The library doesn't support arrays. You'll need to use Strings instead:

def binary(byte_array)

  byte_array.pack('C*')

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(binary(array_to_encrypt), binary(key_array))

p "RESULT IS #{result}"

answered Jan 7 at 19:44

KingPong

9621118

add a comment |

The library doesn't support arrays. You'll need to use Strings instead:

def binary(byte_array)

  byte_array.pack('C*')

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(binary(array_to_encrypt), binary(key_array))

p "RESULT IS #{result}"

answered Jan 7 at 19:44

KingPong

9621118

add a comment |

The library doesn't support arrays. You'll need to use Strings instead:

def binary(byte_array)

  byte_array.pack('C*')

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(binary(array_to_encrypt), binary(key_array))

p "RESULT IS #{result}"

answered Jan 7 at 19:44

KingPong

9621118

The library doesn't support arrays. You'll need to use Strings instead:

def binary(byte_array)

  byte_array.pack('C*')

end



array_to_encrypt = [16, 0, 0, 0, 50, 48, 49, 55, 47, 48, 50, 47, 48, 55, 32, 50, 50, 58, 52, 54, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

key_array = [65, 66, 67, 68, 49, 50, 51, 52, 70, 71, 72, 73, 53, 54, 55, 56]



result = encrypt(binary(array_to_encrypt), binary(key_array))

p "RESULT IS #{result}"

answered Jan 7 at 19:44

KingPong

9621118

answered Jan 7 at 19:44

KingPong

9621118

answered Jan 7 at 19:44

KingPong

9621118

answered Jan 7 at 19:44

KingPong

9621118

add a comment |

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