Mixing
According to Chebyshev's rule, how many observations should lie within one and a half standard deviations of...
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Using the formula : $p = 1 - k^{-2}$
I calculated that $p = 1 - 1.5^{-2} = 0.56$ , which equals to $56%$.
Because I have $24$ data points I go ahead and solve the number of points is $56%$ of $24$:
begin{equation}
frac{56 * 24}{100} = 13.44
end{equation}
which is approximately 13, which was my final answer.
For some reason this is not the final answer therefore my answer 13 is wrong.
What did I do wrong?
statistics statistical-inference standard-deviation descriptive-statistics stationary-processes
asked Jan 20 '16 at 2:16
chercher
61
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add a comment |
$begingroup$
Using the formula : $p = 1 - k^{-2}$
I calculated that $p = 1 - 1.5^{-2} = 0.56$ , which equals to $56%$.
Because I have $24$ data points I go ahead and solve the number of points is $56%$ of $24$:
begin{equation}
frac{56 * 24}{100} = 13.44
end{equation}
which is approximately 13, which was my final answer.
For some reason this is not the final answer therefore my answer 13 is wrong.
What did I do wrong?
statistics statistical-inference standard-deviation descriptive-statistics stationary-processes
asked Jan 20 '16 at 2:16
chercher
61
$endgroup$
$begingroup$
cher, Welcome to Physics SE! Perhaps consider formatting the question so that your reasoning is a little clearer.
$endgroup$
– Andrea
Jan 20 '16 at 2:24
$begingroup$
What is the alleged "final answer"?
$endgroup$
– BruceET
Mar 23 '16 at 2:57
add a comment |
$begingroup$
Using the formula : $p = 1 - k^{-2}$
I calculated that $p = 1 - 1.5^{-2} = 0.56$ , which equals to $56%$.
Because I have $24$ data points I go ahead and solve the number of points is $56%$ of $24$:
begin{equation}
frac{56 * 24}{100} = 13.44
end{equation}
which is approximately 13, which was my final answer.
For some reason this is not the final answer therefore my answer 13 is wrong.
What did I do wrong?
statistics statistical-inference standard-deviation descriptive-statistics stationary-processes
asked Jan 20 '16 at 2:16
chercher
61
$endgroup$
Using the formula : $p = 1 - k^{-2}$
I calculated that $p = 1 - 1.5^{-2} = 0.56$ , which equals to $56%$.
Because I have $24$ data points I go ahead and solve the number of points is $56%$ of $24$:
begin{equation}
frac{56 * 24}{100} = 13.44
end{equation}
which is approximately 13, which was my final answer.
For some reason this is not the final answer therefore my answer 13 is wrong.
What did I do wrong?
statistics statistical-inference standard-deviation descriptive-statistics stationary-processes
statistics statistical-inference standard-deviation descriptive-statistics stationary-processes
asked Jan 20 '16 at 2:16
chercher
61
asked Jan 20 '16 at 2:16
chercher
61
edited Jan 20 '16 at 4:19
cher
asked Jan 20 '16 at 2:16
chercher
61
asked Jan 20 '16 at 2:16
chercher
61
asked Jan 20 '16 at 2:16
chercher
61
61
$begingroup$
cher, Welcome to Physics SE! Perhaps consider formatting the question so that your reasoning is a little clearer.
$endgroup$
– Andrea
Jan 20 '16 at 2:24
$begingroup$
What is the alleged "final answer"?
$endgroup$
– BruceET
Mar 23 '16 at 2:57
add a comment |
$begingroup$
cher, Welcome to Physics SE! Perhaps consider formatting the question so that your reasoning is a little clearer.
$endgroup$
– Andrea
Jan 20 '16 at 2:24
$begingroup$
What is the alleged "final answer"?
$endgroup$
– BruceET
Mar 23 '16 at 2:57
$begingroup$
cher, Welcome to Physics SE! Perhaps consider formatting the question so that your reasoning is a little clearer.
$endgroup$
– Andrea
Jan 20 '16 at 2:24
$begingroup$
cher, Welcome to Physics SE! Perhaps consider formatting the question so that your reasoning is a little clearer.
$endgroup$
– Andrea
Jan 20 '16 at 2:24
$begingroup$
What is the alleged "final answer"?
$endgroup$
– BruceET
Mar 23 '16 at 2:57
$begingroup$
What is the alleged "final answer"?
$endgroup$
– BruceET
Mar 23 '16 at 2:57
add a comment |
1 Answer
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When you calculate the p do not round up, instead it'll just be (55%*24)/100=13.33 which is the correct answer.
answered May 24 '16 at 14:26
JulsJuls
1
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$begingroup$
Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
add a comment |
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1 Answer
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1 Answer
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When you calculate the p do not round up, instead it'll just be (55%*24)/100=13.33 which is the correct answer.
answered May 24 '16 at 14:26
JulsJuls
1
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Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
add a comment |
$begingroup$
When you calculate the p do not round up, instead it'll just be (55%*24)/100=13.33 which is the correct answer.
answered May 24 '16 at 14:26
JulsJuls
1
$endgroup$
$begingroup$
Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
add a comment |
$begingroup$
When you calculate the p do not round up, instead it'll just be (55%*24)/100=13.33 which is the correct answer.
answered May 24 '16 at 14:26
JulsJuls
1
$endgroup$
When you calculate the p do not round up, instead it'll just be (55%*24)/100=13.33 which is the correct answer.
answered May 24 '16 at 14:26
JulsJuls
1
answered May 24 '16 at 14:26
JulsJuls
1
answered May 24 '16 at 14:26
JulsJuls
1
answered May 24 '16 at 14:26
JulsJuls
1
1
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Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
add a comment |
$begingroup$
Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
$begingroup$
Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
$begingroup$
Hi Juls, welcome to Maths SE. Isn't $p$ = .55 also a rounded value?
$endgroup$
– Andrea
May 24 '16 at 14:39
add a comment |
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cher, Welcome to Physics SE! Perhaps consider formatting the question so that your reasoning is a little clearer.
$endgroup$
– Andrea
Jan 20 '16 at 2:24
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What is the alleged "final answer"?
$endgroup$
– BruceET
Mar 23 '16 at 2:57