Calculating an average of multiple data sets based on priority.
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First and foremost I'm no mathematician, it may be a case of over complication.
What I'm trying to do is that I have 2 sets of data, I want to calculate one average for both sets but I want the first set to have more 'influence' over the average than the second.
I.e I want an outlier in set A to swing the average more than if that outlier was in set B (If that makes any sense).
I would assume I'd need a value to deem how much of an effect each set would have.
I don't expect a specific answer but if someone could get me started/point me in the right direction I'd be grateful.
Cheers.
data-analysis
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add a comment |
$begingroup$
First and foremost I'm no mathematician, it may be a case of over complication.
What I'm trying to do is that I have 2 sets of data, I want to calculate one average for both sets but I want the first set to have more 'influence' over the average than the second.
I.e I want an outlier in set A to swing the average more than if that outlier was in set B (If that makes any sense).
I would assume I'd need a value to deem how much of an effect each set would have.
I don't expect a specific answer but if someone could get me started/point me in the right direction I'd be grateful.
Cheers.
data-analysis
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You could give each number in the first set a weight of 2, or 17, or anything else bigger than 1.
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– Gerry Myerson
Feb 2 at 7:35
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@GerryMyerson That could work but it would seem a bit 'messy'. I'll try it out thanks.
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– Faraday
Feb 3 at 4:42
add a comment |
$begingroup$
First and foremost I'm no mathematician, it may be a case of over complication.
What I'm trying to do is that I have 2 sets of data, I want to calculate one average for both sets but I want the first set to have more 'influence' over the average than the second.
I.e I want an outlier in set A to swing the average more than if that outlier was in set B (If that makes any sense).
I would assume I'd need a value to deem how much of an effect each set would have.
I don't expect a specific answer but if someone could get me started/point me in the right direction I'd be grateful.
Cheers.
data-analysis
$endgroup$
First and foremost I'm no mathematician, it may be a case of over complication.
What I'm trying to do is that I have 2 sets of data, I want to calculate one average for both sets but I want the first set to have more 'influence' over the average than the second.
I.e I want an outlier in set A to swing the average more than if that outlier was in set B (If that makes any sense).
I would assume I'd need a value to deem how much of an effect each set would have.
I don't expect a specific answer but if someone could get me started/point me in the right direction I'd be grateful.
Cheers.
data-analysis
data-analysis
asked Feb 2 at 6:18
FaradayFaraday
11
11
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You could give each number in the first set a weight of 2, or 17, or anything else bigger than 1.
$endgroup$
– Gerry Myerson
Feb 2 at 7:35
$begingroup$
@GerryMyerson That could work but it would seem a bit 'messy'. I'll try it out thanks.
$endgroup$
– Faraday
Feb 3 at 4:42
add a comment |
$begingroup$
You could give each number in the first set a weight of 2, or 17, or anything else bigger than 1.
$endgroup$
– Gerry Myerson
Feb 2 at 7:35
$begingroup$
@GerryMyerson That could work but it would seem a bit 'messy'. I'll try it out thanks.
$endgroup$
– Faraday
Feb 3 at 4:42
$begingroup$
You could give each number in the first set a weight of 2, or 17, or anything else bigger than 1.
$endgroup$
– Gerry Myerson
Feb 2 at 7:35
$begingroup$
You could give each number in the first set a weight of 2, or 17, or anything else bigger than 1.
$endgroup$
– Gerry Myerson
Feb 2 at 7:35
$begingroup$
@GerryMyerson That could work but it would seem a bit 'messy'. I'll try it out thanks.
$endgroup$
– Faraday
Feb 3 at 4:42
$begingroup$
@GerryMyerson That could work but it would seem a bit 'messy'. I'll try it out thanks.
$endgroup$
– Faraday
Feb 3 at 4:42
add a comment |
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$begingroup$
You could give each number in the first set a weight of 2, or 17, or anything else bigger than 1.
$endgroup$
– Gerry Myerson
Feb 2 at 7:35
$begingroup$
@GerryMyerson That could work but it would seem a bit 'messy'. I'll try it out thanks.
$endgroup$
– Faraday
Feb 3 at 4:42