Trim Leading and trailing Spaces in Awk





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I have a file which contains 1 line like below



 VINOTH                                                                                    |KARTHICK                                                                                       |RAVI


I'm using the below command to remove the leading and trailing spaces , but it's not not working.



awk '{ gsub(/^[ t]+|[ t]+$/, ""); print }' Input_File


Please help.



Required Output.



VINOTH|KARTHICK|RAVI









share|improve this question


















  • 1





    Try sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File

    – Wiktor Stribiżew
    Jan 3 at 13:03











  • It's working. Could you please explain the Statement?

    – Vinoth Karthick
    Jan 3 at 13:06











  • Maybe a stupid question, but you have one word in your input file, and it appears as 3 words with a pipe as the delimiter. ... how come?

    – kvantour
    Jan 3 at 15:27











  • Please use the horizontal scroll bar to see the full Line

    – Vinoth Karthick
    Jan 3 at 17:35


















1















I have a file which contains 1 line like below



 VINOTH                                                                                    |KARTHICK                                                                                       |RAVI


I'm using the below command to remove the leading and trailing spaces , but it's not not working.



awk '{ gsub(/^[ t]+|[ t]+$/, ""); print }' Input_File


Please help.



Required Output.



VINOTH|KARTHICK|RAVI









share|improve this question


















  • 1





    Try sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File

    – Wiktor Stribiżew
    Jan 3 at 13:03











  • It's working. Could you please explain the Statement?

    – Vinoth Karthick
    Jan 3 at 13:06











  • Maybe a stupid question, but you have one word in your input file, and it appears as 3 words with a pipe as the delimiter. ... how come?

    – kvantour
    Jan 3 at 15:27











  • Please use the horizontal scroll bar to see the full Line

    – Vinoth Karthick
    Jan 3 at 17:35














1












1








1


1






I have a file which contains 1 line like below



 VINOTH                                                                                    |KARTHICK                                                                                       |RAVI


I'm using the below command to remove the leading and trailing spaces , but it's not not working.



awk '{ gsub(/^[ t]+|[ t]+$/, ""); print }' Input_File


Please help.



Required Output.



VINOTH|KARTHICK|RAVI









share|improve this question














I have a file which contains 1 line like below



 VINOTH                                                                                    |KARTHICK                                                                                       |RAVI


I'm using the below command to remove the leading and trailing spaces , but it's not not working.



awk '{ gsub(/^[ t]+|[ t]+$/, ""); print }' Input_File


Please help.



Required Output.



VINOTH|KARTHICK|RAVI






unix awk ksh






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 3 at 12:53









Vinoth KarthickVinoth Karthick

164114




164114








  • 1





    Try sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File

    – Wiktor Stribiżew
    Jan 3 at 13:03











  • It's working. Could you please explain the Statement?

    – Vinoth Karthick
    Jan 3 at 13:06











  • Maybe a stupid question, but you have one word in your input file, and it appears as 3 words with a pipe as the delimiter. ... how come?

    – kvantour
    Jan 3 at 15:27











  • Please use the horizontal scroll bar to see the full Line

    – Vinoth Karthick
    Jan 3 at 17:35














  • 1





    Try sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File

    – Wiktor Stribiżew
    Jan 3 at 13:03











  • It's working. Could you please explain the Statement?

    – Vinoth Karthick
    Jan 3 at 13:06











  • Maybe a stupid question, but you have one word in your input file, and it appears as 3 words with a pipe as the delimiter. ... how come?

    – kvantour
    Jan 3 at 15:27











  • Please use the horizontal scroll bar to see the full Line

    – Vinoth Karthick
    Jan 3 at 17:35








1




1





Try sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File

– Wiktor Stribiżew
Jan 3 at 13:03





Try sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File

– Wiktor Stribiżew
Jan 3 at 13:03













It's working. Could you please explain the Statement?

– Vinoth Karthick
Jan 3 at 13:06





It's working. Could you please explain the Statement?

– Vinoth Karthick
Jan 3 at 13:06













Maybe a stupid question, but you have one word in your input file, and it appears as 3 words with a pipe as the delimiter. ... how come?

– kvantour
Jan 3 at 15:27





Maybe a stupid question, but you have one word in your input file, and it appears as 3 words with a pipe as the delimiter. ... how come?

– kvantour
Jan 3 at 15:27













Please use the horizontal scroll bar to see the full Line

– Vinoth Karthick
Jan 3 at 17:35





Please use the horizontal scroll bar to see the full Line

– Vinoth Karthick
Jan 3 at 17:35












2 Answers
2






active

oldest

votes


















1














You may use



sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File


There are two regexps here:





  • s/[ t]*|[ t]*/|/g replaces all | enclosed with optional whitespaces with a single | (the | in the regex matches a literal | char as per BRE POSIX standard)


  • s/^[ t]*|[ t]*$//g removes all whitespaces at the start and end of lines. Note that | here is an OR operator (escaped because the BRE POSIX syntax is used).


See the online demo.






share|improve this answer































    1














    Could you please try following(since your sample input and expected output are not clear so didn't test it).



    awk '{gsub(/^[[:space:]]+|[[:space:]]+$/,"")} 1'  Input_file





    share|improve this answer
























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      You may use



      sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File


      There are two regexps here:





      • s/[ t]*|[ t]*/|/g replaces all | enclosed with optional whitespaces with a single | (the | in the regex matches a literal | char as per BRE POSIX standard)


      • s/^[ t]*|[ t]*$//g removes all whitespaces at the start and end of lines. Note that | here is an OR operator (escaped because the BRE POSIX syntax is used).


      See the online demo.






      share|improve this answer




























        1














        You may use



        sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File


        There are two regexps here:





        • s/[ t]*|[ t]*/|/g replaces all | enclosed with optional whitespaces with a single | (the | in the regex matches a literal | char as per BRE POSIX standard)


        • s/^[ t]*|[ t]*$//g removes all whitespaces at the start and end of lines. Note that | here is an OR operator (escaped because the BRE POSIX syntax is used).


        See the online demo.






        share|improve this answer


























          1












          1








          1







          You may use



          sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File


          There are two regexps here:





          • s/[ t]*|[ t]*/|/g replaces all | enclosed with optional whitespaces with a single | (the | in the regex matches a literal | char as per BRE POSIX standard)


          • s/^[ t]*|[ t]*$//g removes all whitespaces at the start and end of lines. Note that | here is an OR operator (escaped because the BRE POSIX syntax is used).


          See the online demo.






          share|improve this answer













          You may use



          sed 's/[ t]*|[ t]*/|/g;s/^[ t]*|[ t]*$//g' Input_File


          There are two regexps here:





          • s/[ t]*|[ t]*/|/g replaces all | enclosed with optional whitespaces with a single | (the | in the regex matches a literal | char as per BRE POSIX standard)


          • s/^[ t]*|[ t]*$//g removes all whitespaces at the start and end of lines. Note that | here is an OR operator (escaped because the BRE POSIX syntax is used).


          See the online demo.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 3 at 13:08









          Wiktor StribiżewWiktor Stribiżew

          330k16149229




          330k16149229

























              1














              Could you please try following(since your sample input and expected output are not clear so didn't test it).



              awk '{gsub(/^[[:space:]]+|[[:space:]]+$/,"")} 1'  Input_file





              share|improve this answer




























                1














                Could you please try following(since your sample input and expected output are not clear so didn't test it).



                awk '{gsub(/^[[:space:]]+|[[:space:]]+$/,"")} 1'  Input_file





                share|improve this answer


























                  1












                  1








                  1







                  Could you please try following(since your sample input and expected output are not clear so didn't test it).



                  awk '{gsub(/^[[:space:]]+|[[:space:]]+$/,"")} 1'  Input_file





                  share|improve this answer













                  Could you please try following(since your sample input and expected output are not clear so didn't test it).



                  awk '{gsub(/^[[:space:]]+|[[:space:]]+$/,"")} 1'  Input_file






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jan 3 at 13:13









                  RavinderSingh13RavinderSingh13

                  30.8k41639




                  30.8k41639






























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