Mixing
simplest approach of dynamically adding components in react
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currently working on react. I have two components lets say ad and home . Inside home components i have one image and on click event of that image i want to render ad inside home component below image. Is there any simples method . thank you!
reactjs react-component
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
add a comment |
0
currently working on react. I have two components lets say ad and home . Inside home components i have one image and on click event of that image i want to render ad inside home component below image. Is there any simples method . thank you!
reactjs react-component
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
Maintain an isOpen state in Home component. Toggle it on click of image and based on this state render the AD conditionally
– Shubham Khatri
Jan 3 at 12:59
add a comment |
0
0
0
currently working on react. I have two components lets say ad and home . Inside home components i have one image and on click event of that image i want to render ad inside home component below image. Is there any simples method . thank you!
reactjs react-component
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
currently working on react. I have two components lets say ad and home . Inside home components i have one image and on click event of that image i want to render ad inside home component below image. Is there any simples method . thank you!
reactjs react-component
reactjs react-component
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
asked Jan 3 at 12:52
AKSHAY SALEKARAKSHAY SALEKAR
102
102
Maintain an isOpen state in Home component. Toggle it on click of image and based on this state render the AD conditionally
– Shubham Khatri
Jan 3 at 12:59
add a comment |
Maintain an isOpen state in Home component. Toggle it on click of image and based on this state render the AD conditionally
– Shubham Khatri
Jan 3 at 12:59
Maintain an isOpen state in Home component. Toggle it on click of image and based on this state render the AD conditionally
– Shubham Khatri
Jan 3 at 12:59
Maintain an isOpen state in Home component. Toggle it on click of image and based on this state render the AD conditionally
– Shubham Khatri
Jan 3 at 12:59
add a comment |
3 Answers
3
active
oldest
votes
0
check this. i think this is what you want
//dynamically generate div
let DynamicDiv=()=>{
return (<div>
<p>i am here</p>
</div>)
}
class App extends Component {
constructor(props){
super(props)
this.state={
visible:false //visibility of Component
}
this.divVisiblity=this.divVisiblity.bind(this) //function is bind when user clicks on pic
}
divVisiblity(){
//this function will get called when user clicks on function
this.setState(()=>{return {visible:!this.state.visible}}) //changes visible state of Component when user clicks
}
render() {
return (
<div>
<div className="App">
{/* onClick is assigned function named divVisiblity */}
<img onClick={this.divVisiblity} src="https://placekitten.com/g/200/300" alt="test"/>
{/*this is ternary if else statement in js */}
{/* if visible = true ,display Component else dont */}
<div>
{this.state.visible && <DynamicDiv/>}
</div>
);
}
}
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
add a comment |
0
I think that will help to you.
export default class HomeComponent extends Component<Props> {
constructor(props) {
super(props);
this.state = {
renderAdComponent: false
};
this.onClickHandler = this.onClickHandler.bind(this);
}
onClickHandler() {
this.setState({renderAdComponent: !this.state.renderAdComponent})
}
render() {
return (
<View>
<Image onClick={this.onClickHandler}/>
{this.state.renderAdComponent ? <AdComponent/> : null}
</View>
);
}
}
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
add a comment |
0
What @sdkcy suggested is okay but the ternary operator isn't really needed. You can do the following
{ this.state.isAdShown && <ComponentToShow /> }
This gets rid of the useless : null result.
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
check this. i think this is what you want
//dynamically generate div
let DynamicDiv=()=>{
return (<div>
<p>i am here</p>
</div>)
}
class App extends Component {
constructor(props){
super(props)
this.state={
visible:false //visibility of Component
}
this.divVisiblity=this.divVisiblity.bind(this) //function is bind when user clicks on pic
}
divVisiblity(){
//this function will get called when user clicks on function
this.setState(()=>{return {visible:!this.state.visible}}) //changes visible state of Component when user clicks
}
render() {
return (
<div>
<div className="App">
{/* onClick is assigned function named divVisiblity */}
<img onClick={this.divVisiblity} src="https://placekitten.com/g/200/300" alt="test"/>
{/*this is ternary if else statement in js */}
{/* if visible = true ,display Component else dont */}
<div>
{this.state.visible && <DynamicDiv/>}
</div>
);
}
}
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
add a comment |
0
check this. i think this is what you want
//dynamically generate div
let DynamicDiv=()=>{
return (<div>
<p>i am here</p>
</div>)
}
class App extends Component {
constructor(props){
super(props)
this.state={
visible:false //visibility of Component
}
this.divVisiblity=this.divVisiblity.bind(this) //function is bind when user clicks on pic
}
divVisiblity(){
//this function will get called when user clicks on function
this.setState(()=>{return {visible:!this.state.visible}}) //changes visible state of Component when user clicks
}
render() {
return (
<div>
<div className="App">
{/* onClick is assigned function named divVisiblity */}
<img onClick={this.divVisiblity} src="https://placekitten.com/g/200/300" alt="test"/>
{/*this is ternary if else statement in js */}
{/* if visible = true ,display Component else dont */}
<div>
{this.state.visible && <DynamicDiv/>}
</div>
);
}
}
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
add a comment |
0
0
0
check this. i think this is what you want
//dynamically generate div
let DynamicDiv=()=>{
return (<div>
<p>i am here</p>
</div>)
}
class App extends Component {
constructor(props){
super(props)
this.state={
visible:false //visibility of Component
}
this.divVisiblity=this.divVisiblity.bind(this) //function is bind when user clicks on pic
}
divVisiblity(){
//this function will get called when user clicks on function
this.setState(()=>{return {visible:!this.state.visible}}) //changes visible state of Component when user clicks
}
render() {
return (
<div>
<div className="App">
{/* onClick is assigned function named divVisiblity */}
<img onClick={this.divVisiblity} src="https://placekitten.com/g/200/300" alt="test"/>
{/*this is ternary if else statement in js */}
{/* if visible = true ,display Component else dont */}
<div>
{this.state.visible && <DynamicDiv/>}
</div>
);
}
}
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
check this. i think this is what you want
//dynamically generate div
let DynamicDiv=()=>{
return (<div>
<p>i am here</p>
</div>)
}
class App extends Component {
constructor(props){
super(props)
this.state={
visible:false //visibility of Component
}
this.divVisiblity=this.divVisiblity.bind(this) //function is bind when user clicks on pic
}
divVisiblity(){
//this function will get called when user clicks on function
this.setState(()=>{return {visible:!this.state.visible}}) //changes visible state of Component when user clicks
}
render() {
return (
<div>
<div className="App">
{/* onClick is assigned function named divVisiblity */}
<img onClick={this.divVisiblity} src="https://placekitten.com/g/200/300" alt="test"/>
{/*this is ternary if else statement in js */}
{/* if visible = true ,display Component else dont */}
<div>
{this.state.visible && <DynamicDiv/>}
</div>
);
}
}
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
answered Jan 3 at 19:01
Rahul SawantRahul Sawant
2215
2215
add a comment |
add a comment |
0
I think that will help to you.
export default class HomeComponent extends Component<Props> {
constructor(props) {
super(props);
this.state = {
renderAdComponent: false
};
this.onClickHandler = this.onClickHandler.bind(this);
}
onClickHandler() {
this.setState({renderAdComponent: !this.state.renderAdComponent})
}
render() {
return (
<View>
<Image onClick={this.onClickHandler}/>
{this.state.renderAdComponent ? <AdComponent/> : null}
</View>
);
}
}
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
add a comment |
0
I think that will help to you.
export default class HomeComponent extends Component<Props> {
constructor(props) {
super(props);
this.state = {
renderAdComponent: false
};
this.onClickHandler = this.onClickHandler.bind(this);
}
onClickHandler() {
this.setState({renderAdComponent: !this.state.renderAdComponent})
}
render() {
return (
<View>
<Image onClick={this.onClickHandler}/>
{this.state.renderAdComponent ? <AdComponent/> : null}
</View>
);
}
}
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
add a comment |
0
0
0
I think that will help to you.
export default class HomeComponent extends Component<Props> {
constructor(props) {
super(props);
this.state = {
renderAdComponent: false
};
this.onClickHandler = this.onClickHandler.bind(this);
}
onClickHandler() {
this.setState({renderAdComponent: !this.state.renderAdComponent})
}
render() {
return (
<View>
<Image onClick={this.onClickHandler}/>
{this.state.renderAdComponent ? <AdComponent/> : null}
</View>
);
}
}
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
I think that will help to you.
export default class HomeComponent extends Component<Props> {
constructor(props) {
super(props);
this.state = {
renderAdComponent: false
};
this.onClickHandler = this.onClickHandler.bind(this);
}
onClickHandler() {
this.setState({renderAdComponent: !this.state.renderAdComponent})
}
render() {
return (
<View>
<Image onClick={this.onClickHandler}/>
{this.state.renderAdComponent ? <AdComponent/> : null}
</View>
);
}
}
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
answered Jan 3 at 13:10
sdkcysdkcy
1,421612
1,421612
add a comment |
add a comment |
0
What @sdkcy suggested is okay but the ternary operator isn't really needed. You can do the following
{ this.state.isAdShown && <ComponentToShow /> }
This gets rid of the useless : null result.
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
add a comment |
0
What @sdkcy suggested is okay but the ternary operator isn't really needed. You can do the following
{ this.state.isAdShown && <ComponentToShow /> }
This gets rid of the useless : null result.
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
add a comment |
0
0
0
What @sdkcy suggested is okay but the ternary operator isn't really needed. You can do the following
{ this.state.isAdShown && <ComponentToShow /> }
This gets rid of the useless : null result.
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
What @sdkcy suggested is okay but the ternary operator isn't really needed. You can do the following
{ this.state.isAdShown && <ComponentToShow /> }
This gets rid of the useless : null result.
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
answered Jan 3 at 14:10
Bojan IvanacBojan Ivanac
795516
795516
add a comment |
add a comment |
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Maintain an isOpen state in Home component. Toggle it on click of image and based on this state render the AD conditionally
– Shubham Khatri
Jan 3 at 12:59