How can i make this mysql query ? If possible at all





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I have this table




itemname property value
------------------------------------------
A size big
A color red

B size big
B color blue

C size small
C color blue

D size small
D color blue

E size small
E color blue


Im creating a list like this: SELECT property,value,COUNT(itemname),GROUP_CONCAT(itemname) FROM table GROUP BY property,value




property value count
---------------------------------
size big 2 (A,B)
size small 3 (C,D,E)
color red 1 (A)
color blue 4 (B,C,D,E)


I want to filter the items which are BIG && SMALL && BLUE, how can i achieve this result ? (I MUST be specific about the property when addressing a value for filtering)




`SELECT
property,value,COUNT(itemname),GROUP_CONCAT(itemname)
FROM
table
GROUP BY
property,value
HAVING
( property IN ('size') && value IN ('big','small') )
&&
( property IN ('color') && value IN ('blue') )`


But this has no result, because it tries to match the row with size and color at the same time ? My desired output in this case is to avoid the item A because it is red, like this:




property value count
---------------------------------
size big 1 (B) A not here, because it is red
size small 3 (C,D,E) no change because all are blue
color red 0 (A) no red is selected, so this row should be 0 or not listed at all
color blue 4 (B,C,D,E) all the 4 are big or small and blue


Please someone help me out in this, i lost 2days wondering on the solution.
I might use CASE combined with HAVING ? Or i should address the WHERE instead somehow ?

Note: This table is actually not real, but if this question can be solved i can use it in my real tables which are a lot more complicated.










share|improve this question

























  • itemname should not be duplicated and field property should be columns.

    – Martin Zeitler
    Jan 3 at 12:58













  • what do you mean ? property is a column already. By the way as i said my goal is not to reorganize the table, just to find a solution to this problem, so i can use it in my real tables.

    – Ninet9
    Jan 3 at 13:01











  • if the idea is not to normalize the data; you will have to suffer from the consequences. the way how the data is represented might suit noSQL, but not really SQL. the way of data-modelling is different there.

    – Martin Zeitler
    Jan 3 at 13:01













  • my real tables like this: ITEMS, PROPERTIES (size,color,and a hundred more), PROPERTYVALUES (black,big,10mm,medium,short,tall etc..) and PROPERTYCONNECTIONS where i connect the item id's to the properties and the values.

    – Ninet9
    Jan 3 at 13:03













  • make size and color columns; then it would be something alike SELECT *, COUNT(itemname) AS amount FROM table WHERE color="blue" AND size IN("big", "small"); (with optinal grouping) if one cannot run a query like this, one can assume the structure is sub-optimal. see studytonight.com/dbms/database-normalization.php

    – Martin Zeitler
    Jan 3 at 13:09




















0















I have this table




itemname property value
------------------------------------------
A size big
A color red

B size big
B color blue

C size small
C color blue

D size small
D color blue

E size small
E color blue


Im creating a list like this: SELECT property,value,COUNT(itemname),GROUP_CONCAT(itemname) FROM table GROUP BY property,value




property value count
---------------------------------
size big 2 (A,B)
size small 3 (C,D,E)
color red 1 (A)
color blue 4 (B,C,D,E)


I want to filter the items which are BIG && SMALL && BLUE, how can i achieve this result ? (I MUST be specific about the property when addressing a value for filtering)




`SELECT
property,value,COUNT(itemname),GROUP_CONCAT(itemname)
FROM
table
GROUP BY
property,value
HAVING
( property IN ('size') && value IN ('big','small') )
&&
( property IN ('color') && value IN ('blue') )`


But this has no result, because it tries to match the row with size and color at the same time ? My desired output in this case is to avoid the item A because it is red, like this:




property value count
---------------------------------
size big 1 (B) A not here, because it is red
size small 3 (C,D,E) no change because all are blue
color red 0 (A) no red is selected, so this row should be 0 or not listed at all
color blue 4 (B,C,D,E) all the 4 are big or small and blue


Please someone help me out in this, i lost 2days wondering on the solution.
I might use CASE combined with HAVING ? Or i should address the WHERE instead somehow ?

Note: This table is actually not real, but if this question can be solved i can use it in my real tables which are a lot more complicated.










share|improve this question

























  • itemname should not be duplicated and field property should be columns.

    – Martin Zeitler
    Jan 3 at 12:58













  • what do you mean ? property is a column already. By the way as i said my goal is not to reorganize the table, just to find a solution to this problem, so i can use it in my real tables.

    – Ninet9
    Jan 3 at 13:01











  • if the idea is not to normalize the data; you will have to suffer from the consequences. the way how the data is represented might suit noSQL, but not really SQL. the way of data-modelling is different there.

    – Martin Zeitler
    Jan 3 at 13:01













  • my real tables like this: ITEMS, PROPERTIES (size,color,and a hundred more), PROPERTYVALUES (black,big,10mm,medium,short,tall etc..) and PROPERTYCONNECTIONS where i connect the item id's to the properties and the values.

    – Ninet9
    Jan 3 at 13:03













  • make size and color columns; then it would be something alike SELECT *, COUNT(itemname) AS amount FROM table WHERE color="blue" AND size IN("big", "small"); (with optinal grouping) if one cannot run a query like this, one can assume the structure is sub-optimal. see studytonight.com/dbms/database-normalization.php

    – Martin Zeitler
    Jan 3 at 13:09
















0












0








0








I have this table




itemname property value
------------------------------------------
A size big
A color red

B size big
B color blue

C size small
C color blue

D size small
D color blue

E size small
E color blue


Im creating a list like this: SELECT property,value,COUNT(itemname),GROUP_CONCAT(itemname) FROM table GROUP BY property,value




property value count
---------------------------------
size big 2 (A,B)
size small 3 (C,D,E)
color red 1 (A)
color blue 4 (B,C,D,E)


I want to filter the items which are BIG && SMALL && BLUE, how can i achieve this result ? (I MUST be specific about the property when addressing a value for filtering)




`SELECT
property,value,COUNT(itemname),GROUP_CONCAT(itemname)
FROM
table
GROUP BY
property,value
HAVING
( property IN ('size') && value IN ('big','small') )
&&
( property IN ('color') && value IN ('blue') )`


But this has no result, because it tries to match the row with size and color at the same time ? My desired output in this case is to avoid the item A because it is red, like this:




property value count
---------------------------------
size big 1 (B) A not here, because it is red
size small 3 (C,D,E) no change because all are blue
color red 0 (A) no red is selected, so this row should be 0 or not listed at all
color blue 4 (B,C,D,E) all the 4 are big or small and blue


Please someone help me out in this, i lost 2days wondering on the solution.
I might use CASE combined with HAVING ? Or i should address the WHERE instead somehow ?

Note: This table is actually not real, but if this question can be solved i can use it in my real tables which are a lot more complicated.










share|improve this question
















I have this table




itemname property value
------------------------------------------
A size big
A color red

B size big
B color blue

C size small
C color blue

D size small
D color blue

E size small
E color blue


Im creating a list like this: SELECT property,value,COUNT(itemname),GROUP_CONCAT(itemname) FROM table GROUP BY property,value




property value count
---------------------------------
size big 2 (A,B)
size small 3 (C,D,E)
color red 1 (A)
color blue 4 (B,C,D,E)


I want to filter the items which are BIG && SMALL && BLUE, how can i achieve this result ? (I MUST be specific about the property when addressing a value for filtering)




`SELECT
property,value,COUNT(itemname),GROUP_CONCAT(itemname)
FROM
table
GROUP BY
property,value
HAVING
( property IN ('size') && value IN ('big','small') )
&&
( property IN ('color') && value IN ('blue') )`


But this has no result, because it tries to match the row with size and color at the same time ? My desired output in this case is to avoid the item A because it is red, like this:




property value count
---------------------------------
size big 1 (B) A not here, because it is red
size small 3 (C,D,E) no change because all are blue
color red 0 (A) no red is selected, so this row should be 0 or not listed at all
color blue 4 (B,C,D,E) all the 4 are big or small and blue


Please someone help me out in this, i lost 2days wondering on the solution.
I might use CASE combined with HAVING ? Or i should address the WHERE instead somehow ?

Note: This table is actually not real, but if this question can be solved i can use it in my real tables which are a lot more complicated.







mysqli






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 3 at 12:59







Ninet9

















asked Jan 3 at 12:52









Ninet9Ninet9

3817




3817













  • itemname should not be duplicated and field property should be columns.

    – Martin Zeitler
    Jan 3 at 12:58













  • what do you mean ? property is a column already. By the way as i said my goal is not to reorganize the table, just to find a solution to this problem, so i can use it in my real tables.

    – Ninet9
    Jan 3 at 13:01











  • if the idea is not to normalize the data; you will have to suffer from the consequences. the way how the data is represented might suit noSQL, but not really SQL. the way of data-modelling is different there.

    – Martin Zeitler
    Jan 3 at 13:01













  • my real tables like this: ITEMS, PROPERTIES (size,color,and a hundred more), PROPERTYVALUES (black,big,10mm,medium,short,tall etc..) and PROPERTYCONNECTIONS where i connect the item id's to the properties and the values.

    – Ninet9
    Jan 3 at 13:03













  • make size and color columns; then it would be something alike SELECT *, COUNT(itemname) AS amount FROM table WHERE color="blue" AND size IN("big", "small"); (with optinal grouping) if one cannot run a query like this, one can assume the structure is sub-optimal. see studytonight.com/dbms/database-normalization.php

    – Martin Zeitler
    Jan 3 at 13:09





















  • itemname should not be duplicated and field property should be columns.

    – Martin Zeitler
    Jan 3 at 12:58













  • what do you mean ? property is a column already. By the way as i said my goal is not to reorganize the table, just to find a solution to this problem, so i can use it in my real tables.

    – Ninet9
    Jan 3 at 13:01











  • if the idea is not to normalize the data; you will have to suffer from the consequences. the way how the data is represented might suit noSQL, but not really SQL. the way of data-modelling is different there.

    – Martin Zeitler
    Jan 3 at 13:01













  • my real tables like this: ITEMS, PROPERTIES (size,color,and a hundred more), PROPERTYVALUES (black,big,10mm,medium,short,tall etc..) and PROPERTYCONNECTIONS where i connect the item id's to the properties and the values.

    – Ninet9
    Jan 3 at 13:03













  • make size and color columns; then it would be something alike SELECT *, COUNT(itemname) AS amount FROM table WHERE color="blue" AND size IN("big", "small"); (with optinal grouping) if one cannot run a query like this, one can assume the structure is sub-optimal. see studytonight.com/dbms/database-normalization.php

    – Martin Zeitler
    Jan 3 at 13:09



















itemname should not be duplicated and field property should be columns.

– Martin Zeitler
Jan 3 at 12:58







itemname should not be duplicated and field property should be columns.

– Martin Zeitler
Jan 3 at 12:58















what do you mean ? property is a column already. By the way as i said my goal is not to reorganize the table, just to find a solution to this problem, so i can use it in my real tables.

– Ninet9
Jan 3 at 13:01





what do you mean ? property is a column already. By the way as i said my goal is not to reorganize the table, just to find a solution to this problem, so i can use it in my real tables.

– Ninet9
Jan 3 at 13:01













if the idea is not to normalize the data; you will have to suffer from the consequences. the way how the data is represented might suit noSQL, but not really SQL. the way of data-modelling is different there.

– Martin Zeitler
Jan 3 at 13:01







if the idea is not to normalize the data; you will have to suffer from the consequences. the way how the data is represented might suit noSQL, but not really SQL. the way of data-modelling is different there.

– Martin Zeitler
Jan 3 at 13:01















my real tables like this: ITEMS, PROPERTIES (size,color,and a hundred more), PROPERTYVALUES (black,big,10mm,medium,short,tall etc..) and PROPERTYCONNECTIONS where i connect the item id's to the properties and the values.

– Ninet9
Jan 3 at 13:03







my real tables like this: ITEMS, PROPERTIES (size,color,and a hundred more), PROPERTYVALUES (black,big,10mm,medium,short,tall etc..) and PROPERTYCONNECTIONS where i connect the item id's to the properties and the values.

– Ninet9
Jan 3 at 13:03















make size and color columns; then it would be something alike SELECT *, COUNT(itemname) AS amount FROM table WHERE color="blue" AND size IN("big", "small"); (with optinal grouping) if one cannot run a query like this, one can assume the structure is sub-optimal. see studytonight.com/dbms/database-normalization.php

– Martin Zeitler
Jan 3 at 13:09







make size and color columns; then it would be something alike SELECT *, COUNT(itemname) AS amount FROM table WHERE color="blue" AND size IN("big", "small"); (with optinal grouping) if one cannot run a query like this, one can assume the structure is sub-optimal. see studytonight.com/dbms/database-normalization.php

– Martin Zeitler
Jan 3 at 13:09














1 Answer
1






active

oldest

votes


















0














I figured a solution on my own, of course this example table is nonsense, the point is the way it had been solved.




`
SELECT
property,
value,
COUNT(t.itemname) AS count
FROM (
SELECT
itemname
FROM
table
GROUP BY
itemname
HAVING
COUNT (CASE WHEN property='size' AND value IN ('big','small') THEN 1 END) >=1
&&
COUNT (CASE WHEN property='color' AND value IN ('blue') THEN 1 END) >=1
) t
INNER JOIN
table ON table.itemname=t.itemname
GROUP BY
property,value
`





share|improve this answer
























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54022688%2fhow-can-i-make-this-mysql-query-if-possible-at-all%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    I figured a solution on my own, of course this example table is nonsense, the point is the way it had been solved.




    `
    SELECT
    property,
    value,
    COUNT(t.itemname) AS count
    FROM (
    SELECT
    itemname
    FROM
    table
    GROUP BY
    itemname
    HAVING
    COUNT (CASE WHEN property='size' AND value IN ('big','small') THEN 1 END) >=1
    &&
    COUNT (CASE WHEN property='color' AND value IN ('blue') THEN 1 END) >=1
    ) t
    INNER JOIN
    table ON table.itemname=t.itemname
    GROUP BY
    property,value
    `





    share|improve this answer




























      0














      I figured a solution on my own, of course this example table is nonsense, the point is the way it had been solved.




      `
      SELECT
      property,
      value,
      COUNT(t.itemname) AS count
      FROM (
      SELECT
      itemname
      FROM
      table
      GROUP BY
      itemname
      HAVING
      COUNT (CASE WHEN property='size' AND value IN ('big','small') THEN 1 END) >=1
      &&
      COUNT (CASE WHEN property='color' AND value IN ('blue') THEN 1 END) >=1
      ) t
      INNER JOIN
      table ON table.itemname=t.itemname
      GROUP BY
      property,value
      `





      share|improve this answer


























        0












        0








        0







        I figured a solution on my own, of course this example table is nonsense, the point is the way it had been solved.




        `
        SELECT
        property,
        value,
        COUNT(t.itemname) AS count
        FROM (
        SELECT
        itemname
        FROM
        table
        GROUP BY
        itemname
        HAVING
        COUNT (CASE WHEN property='size' AND value IN ('big','small') THEN 1 END) >=1
        &&
        COUNT (CASE WHEN property='color' AND value IN ('blue') THEN 1 END) >=1
        ) t
        INNER JOIN
        table ON table.itemname=t.itemname
        GROUP BY
        property,value
        `





        share|improve this answer













        I figured a solution on my own, of course this example table is nonsense, the point is the way it had been solved.




        `
        SELECT
        property,
        value,
        COUNT(t.itemname) AS count
        FROM (
        SELECT
        itemname
        FROM
        table
        GROUP BY
        itemname
        HAVING
        COUNT (CASE WHEN property='size' AND value IN ('big','small') THEN 1 END) >=1
        &&
        COUNT (CASE WHEN property='color' AND value IN ('blue') THEN 1 END) >=1
        ) t
        INNER JOIN
        table ON table.itemname=t.itemname
        GROUP BY
        property,value
        `






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 4 at 10:49









        Ninet9Ninet9

        3817




        3817
































            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54022688%2fhow-can-i-make-this-mysql-query-if-possible-at-all%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            android studio warns about leanback feature tag usage required on manifest while using Unity exported app?

            SQL update select statement

            WPF add header to Image with URL pettitions [duplicate]