Mixing
How to create a for loop to filter within a specific row and to save the output in a new document using R?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I have different data sets that all have several thousand rows and that all have the same structure with 5 columns. A subset of my data looks like this:
INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12
I now have to filter this data frame for all the different values of TM whicha are always a combination of a letter and a number from 1 to 12 (e.g. A1, B2, B3, C4, D6, F8,...). However, not all the letters and not all the numbers are always present as also shown in the table above, where A1 to A12 and B1 are missing.
To filter and save the data, I have already coded a short script that works perfectly fine, but in this way, I have to adapt the parameter for the sorting and the resulting output file every time:
library(tidyverse)
df %>%
filter(TM == "B2") %>%
write.csv(file = "C:/Users/Desktop/B2.csv", row.names = FALSE)
I am sure that there would be a possibility to solve this problem with a for loop but as I am not yet that experienced with the use of loops, I would like to ask you, if you could help me with this issue.
Thank you very much!
r for-loop filter save export-to-csv
asked Jan 3 at 12:58
HotshotHotshot
7111
add a comment |
I have different data sets that all have several thousand rows and that all have the same structure with 5 columns. A subset of my data looks like this:
INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12
I now have to filter this data frame for all the different values of TM whicha are always a combination of a letter and a number from 1 to 12 (e.g. A1, B2, B3, C4, D6, F8,...). However, not all the letters and not all the numbers are always present as also shown in the table above, where A1 to A12 and B1 are missing.
To filter and save the data, I have already coded a short script that works perfectly fine, but in this way, I have to adapt the parameter for the sorting and the resulting output file every time:
library(tidyverse)
df %>%
filter(TM == "B2") %>%
write.csv(file = "C:/Users/Desktop/B2.csv", row.names = FALSE)
I am sure that there would be a possibility to solve this problem with a for loop but as I am not yet that experienced with the use of loops, I would like to ask you, if you could help me with this issue.
Thank you very much!
r for-loop filter save export-to-csv
asked Jan 3 at 12:58
HotshotHotshot
7111
4
Possible duplicate of Split dataframe into multiple output files
– Niek
Jan 3 at 13:04
add a comment |
I have different data sets that all have several thousand rows and that all have the same structure with 5 columns. A subset of my data looks like this:
INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12
I now have to filter this data frame for all the different values of TM whicha are always a combination of a letter and a number from 1 to 12 (e.g. A1, B2, B3, C4, D6, F8,...). However, not all the letters and not all the numbers are always present as also shown in the table above, where A1 to A12 and B1 are missing.
To filter and save the data, I have already coded a short script that works perfectly fine, but in this way, I have to adapt the parameter for the sorting and the resulting output file every time:
library(tidyverse)
df %>%
filter(TM == "B2") %>%
write.csv(file = "C:/Users/Desktop/B2.csv", row.names = FALSE)
I am sure that there would be a possibility to solve this problem with a for loop but as I am not yet that experienced with the use of loops, I would like to ask you, if you could help me with this issue.
Thank you very much!
r for-loop filter save export-to-csv
asked Jan 3 at 12:58
HotshotHotshot
7111
I have different data sets that all have several thousand rows and that all have the same structure with 5 columns. A subset of my data looks like this:
INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12
I now have to filter this data frame for all the different values of TM whicha are always a combination of a letter and a number from 1 to 12 (e.g. A1, B2, B3, C4, D6, F8,...). However, not all the letters and not all the numbers are always present as also shown in the table above, where A1 to A12 and B1 are missing.
To filter and save the data, I have already coded a short script that works perfectly fine, but in this way, I have to adapt the parameter for the sorting and the resulting output file every time:
library(tidyverse)
df %>%
filter(TM == "B2") %>%
write.csv(file = "C:/Users/Desktop/B2.csv", row.names = FALSE)
I am sure that there would be a possibility to solve this problem with a for loop but as I am not yet that experienced with the use of loops, I would like to ask you, if you could help me with this issue.
Thank you very much!
r for-loop filter save export-to-csv
r for-loop filter save export-to-csv
asked Jan 3 at 12:58
HotshotHotshot
7111
asked Jan 3 at 12:58
HotshotHotshot
7111
asked Jan 3 at 12:58
HotshotHotshot
7111
asked Jan 3 at 12:58
HotshotHotshot
7111
asked Jan 3 at 12:58
HotshotHotshot
7111
7111
4
Possible duplicate of Split dataframe into multiple output files
– Niek
Jan 3 at 13:04
add a comment |
4
Possible duplicate of Split dataframe into multiple output files
– Niek
Jan 3 at 13:04
4
4
Possible duplicate of Split dataframe into multiple output files
– Niek
Jan 3 at 13:04
Possible duplicate of Split dataframe into multiple output files
– Niek
Jan 3 at 13:04
add a comment |
1 Answer
1
active
oldest
votes
You should split your data.frame in a list, each element of the list then is printed:
# here you split by the variable you want:
listed <- split(data, data$TM)
listed
# here the partial result
$B2
INr FNr TM I1 I2
1 1 1 B2 1598,45 0,14
2 2 1 B2 930,40 0,11
3 3 1 B2 107,86 0,04
4 4 1 B2 881,09 0,11
$B3
INr FNr TM I1 I2
5 7 1 B3 2201,98 0,15
6 8 1 B3 161,30 0,04
7 9 1 B3 1208,14 0,17
8 4 2 B3 831,75 0,12
9 5 2 B3 1027,41 0,14
10 7 2 B3 2052,16 0,15
11 8 2 B3 159,63 0,05
...
Then R is a vectorized language, so you do not need in this case a loop, but you can use one of the apply functions, to apply to each of the list a function, in this case, write.table:
sapply(names(listed), # here the object to sapply the function
# here the function: you have to create the path with paste0
# adding the x to have the correct names
function (x) write.table(listed[[x]], file=paste0("C:\Users\Desktop\",x, ".csv")))
With data:
data <- read.table(text = "INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12", header = T)
answered Jan 3 at 13:24
s_ts_t
3,69121133
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54022787%2fhow-to-create-a-for-loop-to-filter-within-a-specific-row-and-to-save-the-output%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should split your data.frame in a list, each element of the list then is printed:
# here you split by the variable you want:
listed <- split(data, data$TM)
listed
# here the partial result
$B2
INr FNr TM I1 I2
1 1 1 B2 1598,45 0,14
2 2 1 B2 930,40 0,11
3 3 1 B2 107,86 0,04
4 4 1 B2 881,09 0,11
$B3
INr FNr TM I1 I2
5 7 1 B3 2201,98 0,15
6 8 1 B3 161,30 0,04
7 9 1 B3 1208,14 0,17
8 4 2 B3 831,75 0,12
9 5 2 B3 1027,41 0,14
10 7 2 B3 2052,16 0,15
11 8 2 B3 159,63 0,05
...
Then R is a vectorized language, so you do not need in this case a loop, but you can use one of the apply functions, to apply to each of the list a function, in this case, write.table:
sapply(names(listed), # here the object to sapply the function
# here the function: you have to create the path with paste0
# adding the x to have the correct names
function (x) write.table(listed[[x]], file=paste0("C:\Users\Desktop\",x, ".csv")))
With data:
data <- read.table(text = "INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12", header = T)
answered Jan 3 at 13:24
s_ts_t
3,69121133
add a comment |
You should split your data.frame in a list, each element of the list then is printed:
# here you split by the variable you want:
listed <- split(data, data$TM)
listed
# here the partial result
$B2
INr FNr TM I1 I2
1 1 1 B2 1598,45 0,14
2 2 1 B2 930,40 0,11
3 3 1 B2 107,86 0,04
4 4 1 B2 881,09 0,11
$B3
INr FNr TM I1 I2
5 7 1 B3 2201,98 0,15
6 8 1 B3 161,30 0,04
7 9 1 B3 1208,14 0,17
8 4 2 B3 831,75 0,12
9 5 2 B3 1027,41 0,14
10 7 2 B3 2052,16 0,15
11 8 2 B3 159,63 0,05
...
Then R is a vectorized language, so you do not need in this case a loop, but you can use one of the apply functions, to apply to each of the list a function, in this case, write.table:
sapply(names(listed), # here the object to sapply the function
# here the function: you have to create the path with paste0
# adding the x to have the correct names
function (x) write.table(listed[[x]], file=paste0("C:\Users\Desktop\",x, ".csv")))
With data:
data <- read.table(text = "INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12", header = T)
answered Jan 3 at 13:24
s_ts_t
3,69121133
add a comment |
You should split your data.frame in a list, each element of the list then is printed:
# here you split by the variable you want:
listed <- split(data, data$TM)
listed
# here the partial result
$B2
INr FNr TM I1 I2
1 1 1 B2 1598,45 0,14
2 2 1 B2 930,40 0,11
3 3 1 B2 107,86 0,04
4 4 1 B2 881,09 0,11
$B3
INr FNr TM I1 I2
5 7 1 B3 2201,98 0,15
6 8 1 B3 161,30 0,04
7 9 1 B3 1208,14 0,17
8 4 2 B3 831,75 0,12
9 5 2 B3 1027,41 0,14
10 7 2 B3 2052,16 0,15
11 8 2 B3 159,63 0,05
...
Then R is a vectorized language, so you do not need in this case a loop, but you can use one of the apply functions, to apply to each of the list a function, in this case, write.table:
sapply(names(listed), # here the object to sapply the function
# here the function: you have to create the path with paste0
# adding the x to have the correct names
function (x) write.table(listed[[x]], file=paste0("C:\Users\Desktop\",x, ".csv")))
With data:
data <- read.table(text = "INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12", header = T)
answered Jan 3 at 13:24
s_ts_t
3,69121133
You should split your data.frame in a list, each element of the list then is printed:
# here you split by the variable you want:
listed <- split(data, data$TM)
listed
# here the partial result
$B2
INr FNr TM I1 I2
1 1 1 B2 1598,45 0,14
2 2 1 B2 930,40 0,11
3 3 1 B2 107,86 0,04
4 4 1 B2 881,09 0,11
$B3
INr FNr TM I1 I2
5 7 1 B3 2201,98 0,15
6 8 1 B3 161,30 0,04
7 9 1 B3 1208,14 0,17
8 4 2 B3 831,75 0,12
9 5 2 B3 1027,41 0,14
10 7 2 B3 2052,16 0,15
11 8 2 B3 159,63 0,05
...
Then R is a vectorized language, so you do not need in this case a loop, but you can use one of the apply functions, to apply to each of the list a function, in this case, write.table:
sapply(names(listed), # here the object to sapply the function
# here the function: you have to create the path with paste0
# adding the x to have the correct names
function (x) write.table(listed[[x]], file=paste0("C:\Users\Desktop\",x, ".csv")))
With data:
data <- read.table(text = "INr FNr TM I1 I2
1 1 B2 1598,45 0,14
2 1 B2 930,40 0,11
3 1 B2 107,86 0,04
4 1 B2 881,09 0,11
7 1 B3 2201,98 0,15
8 1 B3 161,30 0,04
9 1 B3 1208,14 0,17
4 2 B3 831,75 0,12
5 2 B3 1027,41 0,14
7 2 B3 2052,16 0,15
8 2 B3 159,63 0,05
9 2 B4 1111,49 0,16
10 2 B4 1312,15 0,12
1 3 B4 863,79 0,10
2 3 B4 104,06 0,04
3 3 B4 816,02 0,11
4 3 B4 1053,02 0,14
5 3 B5 132,32 0,03
6 3 B5 2059,03 0,14
7 3 B5 153,49 0,04
8 3 B5 1118,69 0,15
9 3 B5 1632,66 0,18
10 3 B5 1302,15 0,12", header = T)
answered Jan 3 at 13:24
s_ts_t
3,69121133
edited Jan 3 at 13:30
answered Jan 3 at 13:24
s_ts_t
3,69121133
answered Jan 3 at 13:24
s_ts_t
3,69121133
answered Jan 3 at 13:24
s_ts_t
3,69121133
3,69121133
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54022787%2fhow-to-create-a-for-loop-to-filter-within-a-specific-row-and-to-save-the-output%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
4
Possible duplicate of Split dataframe into multiple output files
– Niek
Jan 3 at 13:04