How to add sets to the dataframe by loop?

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-1

I have some sets which contain numbers and named as k1,k2,k3,k4 ... k20. Now I want to make a dataframe base on them. How can I do it will loop? My present thought is

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

...

k20<- c(3,4,5)

i <- 1

df1 <- c()

which (i <= parameter){

df1 <- dataframe(df1,ki)

i = i+1

}

#What I want to do is build different size of dataframe by given a parameter

#when parameter = 15 then df1 <- dataframe (k1,k2,k3...,k15)

# when parameter = 12 then df1 <- dataframe (k1,k2,k3...,k12)

But it did not work. Could anyone give me some tips on how can I do that? Thanks

edited Jan 3 at 13:35

asked Jan 3 at 12:30

Codezy

18210

Any reason why rbind doesn't work?

– Vivek Kalyanarangan
Jan 3 at 12:32

@VivekKalyanarangan mean problem is ki do not work

– Codezy
Jan 3 at 12:33

What is ki in this case?

– Vivek Kalyanarangan
Jan 3 at 12:35

I think they are looking for data.frame(var = paste0("k",1:15))

– Jake Kaupp
Jan 3 at 12:38

@RonakShah Sorry I did not make it clean. I have edited my question now. Please tell me if I make it clean this time. thank you

– Codezy
Jan 3 at 12:40

|
show 1 more comment

-1

I have some sets which contain numbers and named as k1,k2,k3,k4 ... k20. Now I want to make a dataframe base on them. How can I do it will loop? My present thought is

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

...

k20<- c(3,4,5)

i <- 1

df1 <- c()

which (i <= parameter){

df1 <- dataframe(df1,ki)

i = i+1

}

#What I want to do is build different size of dataframe by given a parameter

#when parameter = 15 then df1 <- dataframe (k1,k2,k3...,k15)

# when parameter = 12 then df1 <- dataframe (k1,k2,k3...,k12)

But it did not work. Could anyone give me some tips on how can I do that? Thanks

edited Jan 3 at 13:35

asked Jan 3 at 12:30

Codezy

18210

Any reason why rbind doesn't work?

– Vivek Kalyanarangan
Jan 3 at 12:32

@VivekKalyanarangan mean problem is ki do not work

– Codezy
Jan 3 at 12:33

What is ki in this case?

– Vivek Kalyanarangan
Jan 3 at 12:35

I think they are looking for data.frame(var = paste0("k",1:15))

– Jake Kaupp
Jan 3 at 12:38

@RonakShah Sorry I did not make it clean. I have edited my question now. Please tell me if I make it clean this time. thank you

– Codezy
Jan 3 at 12:40

|
show 1 more comment

-1

I have some sets which contain numbers and named as k1,k2,k3,k4 ... k20. Now I want to make a dataframe base on them. How can I do it will loop? My present thought is

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

...

k20<- c(3,4,5)

i <- 1

df1 <- c()

which (i <= parameter){

df1 <- dataframe(df1,ki)

i = i+1

}

#What I want to do is build different size of dataframe by given a parameter

#when parameter = 15 then df1 <- dataframe (k1,k2,k3...,k15)

# when parameter = 12 then df1 <- dataframe (k1,k2,k3...,k12)

But it did not work. Could anyone give me some tips on how can I do that? Thanks

edited Jan 3 at 13:35

asked Jan 3 at 12:30

Codezy

18210

I have some sets which contain numbers and named as k1,k2,k3,k4 ... k20. Now I want to make a dataframe base on them. How can I do it will loop? My present thought is

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

...

k20<- c(3,4,5)

i <- 1

df1 <- c()

which (i <= parameter){

df1 <- dataframe(df1,ki)

i = i+1

}

#What I want to do is build different size of dataframe by given a parameter

#when parameter = 15 then df1 <- dataframe (k1,k2,k3...,k15)

# when parameter = 12 then df1 <- dataframe (k1,k2,k3...,k12)

But it did not work. Could anyone give me some tips on how can I do that? Thanks

r loops dataframe

edited Jan 3 at 13:35

asked Jan 3 at 12:30

Codezy

18210

edited Jan 3 at 13:35

asked Jan 3 at 12:30

Codezy

18210

edited Jan 3 at 13:35

asked Jan 3 at 12:30

Codezy

18210

asked Jan 3 at 12:30

Codezy

18210

asked Jan 3 at 12:30

Codezy

18210

Any reason why rbind doesn't work?

– Vivek Kalyanarangan
Jan 3 at 12:32

@VivekKalyanarangan mean problem is ki do not work

– Codezy
Jan 3 at 12:33

What is ki in this case?

– Vivek Kalyanarangan
Jan 3 at 12:35

I think they are looking for data.frame(var = paste0("k",1:15))

– Jake Kaupp
Jan 3 at 12:38

@RonakShah Sorry I did not make it clean. I have edited my question now. Please tell me if I make it clean this time. thank you

– Codezy
Jan 3 at 12:40

|
show 1 more comment

Any reason why rbind doesn't work?

– Vivek Kalyanarangan
Jan 3 at 12:32

@VivekKalyanarangan mean problem is ki do not work

– Codezy
Jan 3 at 12:33

What is ki in this case?

– Vivek Kalyanarangan
Jan 3 at 12:35

I think they are looking for data.frame(var = paste0("k",1:15))

– Jake Kaupp
Jan 3 at 12:38

@RonakShah Sorry I did not make it clean. I have edited my question now. Please tell me if I make it clean this time. thank you

– Codezy
Jan 3 at 12:40

Any reason why rbind doesn't work?

– Vivek Kalyanarangan
Jan 3 at 12:32

@VivekKalyanarangan mean problem is ki do not work

– Codezy
Jan 3 at 12:33

What is ki in this case?

– Vivek Kalyanarangan
Jan 3 at 12:35

I think they are looking for data.frame(var = paste0("k",1:15))

– Jake Kaupp
Jan 3 at 12:38

@RonakShah Sorry I did not make it clean. I have edited my question now. Please tell me if I make it clean this time. thank you

– Codezy
Jan 3 at 12:40

|
show 1 more comment

1 Answer
1

active

oldest

votes

You can use ls with pattern to get objects which start with k and then subset the objects using 1:n, use mixedsort to sort the vectors according to their names (to avoid k11 being picked up before k2) and put all this one dataframe.

library(gtools)



n = 5

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2 k3 k4 k5

#1  1  2  4  3  3

#2  2  3  5  4  4

#3  3  4  6  5  5



n = 2

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2

#1  1  2

#2  2  3

#3  3  4

data

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

k4 <- c(3, 4, 5)

k5 <- c(3,4,5)

edited Jan 3 at 13:59

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

Thank you for answering. Could you tell me the meaning of ls? And how can I control the number of ki I want to add into the df?

– Codezy
Jan 3 at 12:51

@Codezy ls actually returns characters strings of all the objects in your environment. just type ls() in your console and see what you get. With ls(pattern = "^k") it will return objects which only start with k.

– Ronak Shah
Jan 3 at 13:00

ok actually I want to make a function and control the size of my dataframe by giving the parameter. Do you know how to do that?

– Codezy
Jan 3 at 13:02

@Codezy I am not sure if I understand you completely. What do you mean by control the size of my dataframe by giving the parameter ?

– Ronak Shah
Jan 3 at 13:07

I got 20 sets which are k1 to k20, I want to make different size dataframes to only contain for example k1 to k5 or k1 to k16.

– Codezy
Jan 3 at 13:09

|
show 4 more comments

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1 Answer
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active

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1 Answer
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oldest

votes

library(gtools)



n = 5

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2 k3 k4 k5

#1  1  2  4  3  3

#2  2  3  5  4  4

#3  3  4  6  5  5



n = 2

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2

#1  1  2

#2  2  3

#3  3  4

data

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

k4 <- c(3, 4, 5)

k5 <- c(3,4,5)

edited Jan 3 at 13:59

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

Thank you for answering. Could you tell me the meaning of ls? And how can I control the number of ki I want to add into the df?

– Codezy
Jan 3 at 12:51

@Codezy ls actually returns characters strings of all the objects in your environment. just type ls() in your console and see what you get. With ls(pattern = "^k") it will return objects which only start with k.

– Ronak Shah
Jan 3 at 13:00

ok actually I want to make a function and control the size of my dataframe by giving the parameter. Do you know how to do that?

– Codezy
Jan 3 at 13:02

@Codezy I am not sure if I understand you completely. What do you mean by control the size of my dataframe by giving the parameter ?

– Ronak Shah
Jan 3 at 13:07

I got 20 sets which are k1 to k20, I want to make different size dataframes to only contain for example k1 to k5 or k1 to k16.

– Codezy
Jan 3 at 13:09

|
show 4 more comments

library(gtools)



n = 5

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2 k3 k4 k5

#1  1  2  4  3  3

#2  2  3  5  4  4

#3  3  4  6  5  5



n = 2

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2

#1  1  2

#2  2  3

#3  3  4

data

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

k4 <- c(3, 4, 5)

k5 <- c(3,4,5)

edited Jan 3 at 13:59

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

Thank you for answering. Could you tell me the meaning of ls? And how can I control the number of ki I want to add into the df?

– Codezy
Jan 3 at 12:51

@Codezy ls actually returns characters strings of all the objects in your environment. just type ls() in your console and see what you get. With ls(pattern = "^k") it will return objects which only start with k.

– Ronak Shah
Jan 3 at 13:00

ok actually I want to make a function and control the size of my dataframe by giving the parameter. Do you know how to do that?

– Codezy
Jan 3 at 13:02

@Codezy I am not sure if I understand you completely. What do you mean by control the size of my dataframe by giving the parameter ?

– Ronak Shah
Jan 3 at 13:07

I got 20 sets which are k1 to k20, I want to make different size dataframes to only contain for example k1 to k5 or k1 to k16.

– Codezy
Jan 3 at 13:09

|
show 4 more comments

library(gtools)



n = 5

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2 k3 k4 k5

#1  1  2  4  3  3

#2  2  3  5  4  4

#3  3  4  6  5  5



n = 2

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2

#1  1  2

#2  2  3

#3  3  4

data

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

k4 <- c(3, 4, 5)

k5 <- c(3,4,5)

edited Jan 3 at 13:59

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

library(gtools)



n = 5

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2 k3 k4 k5

#1  1  2  4  3  3

#2  2  3  5  4  4

#3  3  4  6  5  5



n = 2

object_name <- mixedsort(ls(pattern = "^k"))[1:n]

data.frame(mget(object_name))



#  k1 k2

#1  1  2

#2  2  3

#3  3  4

data

k1 <- c(1,2,3)

k2 <- c(2,3,4)

k3 <- c(4,5,6)

k4 <- c(3, 4, 5)

k5 <- c(3,4,5)

edited Jan 3 at 13:59

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

edited Jan 3 at 13:59

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

answered Jan 3 at 12:42

Ronak Shah

46.6k104269

Thank you for answering. Could you tell me the meaning of ls? And how can I control the number of ki I want to add into the df?

– Codezy
Jan 3 at 12:51

@Codezy ls actually returns characters strings of all the objects in your environment. just type ls() in your console and see what you get. With ls(pattern = "^k") it will return objects which only start with k.

– Ronak Shah
Jan 3 at 13:00

ok actually I want to make a function and control the size of my dataframe by giving the parameter. Do you know how to do that?

– Codezy
Jan 3 at 13:02

@Codezy I am not sure if I understand you completely. What do you mean by control the size of my dataframe by giving the parameter ?

– Ronak Shah
Jan 3 at 13:07

I got 20 sets which are k1 to k20, I want to make different size dataframes to only contain for example k1 to k5 or k1 to k16.

– Codezy
Jan 3 at 13:09

|
show 4 more comments

Thank you for answering. Could you tell me the meaning of ls? And how can I control the number of ki I want to add into the df?

– Codezy
Jan 3 at 12:51

@Codezy ls actually returns characters strings of all the objects in your environment. just type ls() in your console and see what you get. With ls(pattern = "^k") it will return objects which only start with k.

– Ronak Shah
Jan 3 at 13:00

ok actually I want to make a function and control the size of my dataframe by giving the parameter. Do you know how to do that?

– Codezy
Jan 3 at 13:02

@Codezy I am not sure if I understand you completely. What do you mean by control the size of my dataframe by giving the parameter ?

– Ronak Shah
Jan 3 at 13:07

I got 20 sets which are k1 to k20, I want to make different size dataframes to only contain for example k1 to k5 or k1 to k16.

– Codezy
Jan 3 at 13:09

Thank you for answering. Could you tell me the meaning of ls? And how can I control the number of ki I want to add into the df?

– Codezy
Jan 3 at 12:51

@Codezy ls actually returns characters strings of all the objects in your environment. just type ls() in your console and see what you get. With ls(pattern = "^k") it will return objects which only start with k.

– Ronak Shah
Jan 3 at 13:00

ok actually I want to make a function and control the size of my dataframe by giving the parameter. Do you know how to do that?

– Codezy
Jan 3 at 13:02

@Codezy I am not sure if I understand you completely. What do you mean by control the size of my dataframe by giving the parameter ?

– Ronak Shah
Jan 3 at 13:07

I got 20 sets which are k1 to k20, I want to make different size dataframes to only contain for example k1 to k5 or k1 to k16.

– Codezy
Jan 3 at 13:09

|
show 4 more comments

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