Defining various forms of continuity in a (semi)metric space with a $rho$-relaxed triangle inequality.












0












$begingroup$


Suppose that $(X, d)$ is a semimetric space with a relaxed triangle inequality, i.e., $d: X times X to mathbb{R}$ satisfies for all $x, y, z in X$
begin{align*}
&d(x, y) geq 0 \
&d(x,y) = 0 iff x = y \
&d(x, y) = d(y, x) \
&d(x, z) leq rho (d(x, y) + d(y, z))
end{align*}



I'm wondering how to define various forms of continuity for functionals $f: X to mathbb{R}$ in this space. Regular continuity and uniform continuity are easy and we can define them the usual way:




  • Continuity:
    [
    forall x in X: forall varepsilon > 0 : exists delta > 0 : forall y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
    ]


  • Uniform Continuity:
    [
    forall varepsilon > 0 : exists delta > 0 : forall x,y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
    ]



What about something like Lipschitz continuity? We could certainly use the regular definition without thinking about it and say there exists some $K geq 0$ for all $x, y in X$:
[
|f(x) - f(y)| leq K d(x, y)
]
Or, equivalently, we could write it like our other continuity definitions and say:
[
d(x,y) < frac{varepsilon}{K} implies |f(x) - f(y)| < varepsilon
]



But this got me thinking that since we have the weaker form of the triangle inequality, is there something similar to Lipschitz continuity but involves the constant $rho$ that still remains meaningful?



Basically what I'm asking is, since we have a weaker triangle inequality, can we use the information of $rho$ to define a stronger notion of continuity than just continuity that involves the constant $rho$ that's somewhat meaningful?










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    0












    $begingroup$


    Suppose that $(X, d)$ is a semimetric space with a relaxed triangle inequality, i.e., $d: X times X to mathbb{R}$ satisfies for all $x, y, z in X$
    begin{align*}
    &d(x, y) geq 0 \
    &d(x,y) = 0 iff x = y \
    &d(x, y) = d(y, x) \
    &d(x, z) leq rho (d(x, y) + d(y, z))
    end{align*}



    I'm wondering how to define various forms of continuity for functionals $f: X to mathbb{R}$ in this space. Regular continuity and uniform continuity are easy and we can define them the usual way:




    • Continuity:
      [
      forall x in X: forall varepsilon > 0 : exists delta > 0 : forall y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
      ]


    • Uniform Continuity:
      [
      forall varepsilon > 0 : exists delta > 0 : forall x,y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
      ]



    What about something like Lipschitz continuity? We could certainly use the regular definition without thinking about it and say there exists some $K geq 0$ for all $x, y in X$:
    [
    |f(x) - f(y)| leq K d(x, y)
    ]
    Or, equivalently, we could write it like our other continuity definitions and say:
    [
    d(x,y) < frac{varepsilon}{K} implies |f(x) - f(y)| < varepsilon
    ]



    But this got me thinking that since we have the weaker form of the triangle inequality, is there something similar to Lipschitz continuity but involves the constant $rho$ that still remains meaningful?



    Basically what I'm asking is, since we have a weaker triangle inequality, can we use the information of $rho$ to define a stronger notion of continuity than just continuity that involves the constant $rho$ that's somewhat meaningful?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Suppose that $(X, d)$ is a semimetric space with a relaxed triangle inequality, i.e., $d: X times X to mathbb{R}$ satisfies for all $x, y, z in X$
      begin{align*}
      &d(x, y) geq 0 \
      &d(x,y) = 0 iff x = y \
      &d(x, y) = d(y, x) \
      &d(x, z) leq rho (d(x, y) + d(y, z))
      end{align*}



      I'm wondering how to define various forms of continuity for functionals $f: X to mathbb{R}$ in this space. Regular continuity and uniform continuity are easy and we can define them the usual way:




      • Continuity:
        [
        forall x in X: forall varepsilon > 0 : exists delta > 0 : forall y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
        ]


      • Uniform Continuity:
        [
        forall varepsilon > 0 : exists delta > 0 : forall x,y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
        ]



      What about something like Lipschitz continuity? We could certainly use the regular definition without thinking about it and say there exists some $K geq 0$ for all $x, y in X$:
      [
      |f(x) - f(y)| leq K d(x, y)
      ]
      Or, equivalently, we could write it like our other continuity definitions and say:
      [
      d(x,y) < frac{varepsilon}{K} implies |f(x) - f(y)| < varepsilon
      ]



      But this got me thinking that since we have the weaker form of the triangle inequality, is there something similar to Lipschitz continuity but involves the constant $rho$ that still remains meaningful?



      Basically what I'm asking is, since we have a weaker triangle inequality, can we use the information of $rho$ to define a stronger notion of continuity than just continuity that involves the constant $rho$ that's somewhat meaningful?










      share|cite|improve this question









      $endgroup$




      Suppose that $(X, d)$ is a semimetric space with a relaxed triangle inequality, i.e., $d: X times X to mathbb{R}$ satisfies for all $x, y, z in X$
      begin{align*}
      &d(x, y) geq 0 \
      &d(x,y) = 0 iff x = y \
      &d(x, y) = d(y, x) \
      &d(x, z) leq rho (d(x, y) + d(y, z))
      end{align*}



      I'm wondering how to define various forms of continuity for functionals $f: X to mathbb{R}$ in this space. Regular continuity and uniform continuity are easy and we can define them the usual way:




      • Continuity:
        [
        forall x in X: forall varepsilon > 0 : exists delta > 0 : forall y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
        ]


      • Uniform Continuity:
        [
        forall varepsilon > 0 : exists delta > 0 : forall x,y in X qquad d(x, y) < delta implies |f(x) - f(y)| < varepsilon
        ]



      What about something like Lipschitz continuity? We could certainly use the regular definition without thinking about it and say there exists some $K geq 0$ for all $x, y in X$:
      [
      |f(x) - f(y)| leq K d(x, y)
      ]
      Or, equivalently, we could write it like our other continuity definitions and say:
      [
      d(x,y) < frac{varepsilon}{K} implies |f(x) - f(y)| < varepsilon
      ]



      But this got me thinking that since we have the weaker form of the triangle inequality, is there something similar to Lipschitz continuity but involves the constant $rho$ that still remains meaningful?



      Basically what I'm asking is, since we have a weaker triangle inequality, can we use the information of $rho$ to define a stronger notion of continuity than just continuity that involves the constant $rho$ that's somewhat meaningful?







      continuity metric-spaces






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      asked Feb 2 at 0:11









      RahulRahul

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